O-Level Chemistry . IP Chemistry: Selective Discharge of Ions in Electrolytic Cells - Part 2

[@mukeshsinghania2570]

Thank you sir , I am from India where these concepts are often ignored and we solve problemz robotically in our coaching centres ...i discovered ur channel by chance ...thank u sir thanks a lot

[@SimpleChemConcepts]

I am glad that you have benefitted from my sharing!

[@swathinimurugan7343]

I am an indian too.....yup they ignore those concepts

[@mihreteabgirma6351]

Astonishing 💥💥💥💥💥💥🙌🙌🙌🙌🙌🙌🙌

[@yeabsirafikre3254]

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[@RakibulHuq-i9z]

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[@taymcg9371]

Saving my butt for my test tomorrow thank you!!!

[@lolomostafa9223]

Thank you so much sir this was very helpful

[@igdaljeet]

Amazing Explanation 🎉

[@bmzaron713]

Ur the man! The reduction potential of copper 2+ to solid is .34v and the formation of 4 hydroxide anions is .40v which makes sense when I think about the oxidation values ( -.34v for copper(s) and - .40v for hydroxide to O2 H20, etc.), so copper would be oxidized since it is greater in value (further right on the number line) for cell potential. This is great man, it helped me think about it! Also, I read that the reduction potential for graphite is .207v . Does that sound about right? It would make sense why it doesn't get oxidized before hydroxide

[@ChineduSylvanus-l1u]

Wow I love chemistry❤❤❤❤❤❤❤

[@dylanteh7675]

I needed this joshua thanks

[@neemataziz3671]

Every points are well explained.

[@zihuigan9897]

Hi! It is stated that nickel(II) sulfate acts the same way as cuso4 when using inert electrodes and ni2+ is discharged instead of h+. Why is that so when nickel is higher than hydrogen in reactivity series? Thanks for your help!

[@Enfieldic]

Because except this reactivity series there is another factor which decides which is going to discharge The factor is concentration Here ni2+ may have a greater concentration than h+ that's the reason why it got discharged

[@NaijaStarZone]

❤

[@kalebtesfahun8686]

Thank you sir

[@SimpleChemConcepts]

Welcome

[@ramanahlawat398]

sir what is the anionic preference order is it So4^(2-)>No(3-)>Oh(-1)>Cl(-1)>Br(-1)>i(-1) I am not sure please correct me if i am wrong

[@chemistrylearner2096]

its better if you write OH- before Cl- as in aqueous solutions, chloride ions are discharged not OH-.

[@chemistrylearner2096]

Raman your one is better at O level

[@luckykazivlog8782]

😍❤❤👍

[@Enfieldic]

Why while using active electrodes The anions didn't got discharge ??

[@rahelmeshesha]

Thank u soooo much

[@SimpleChemConcepts]

Most welcome 😊

[@rpsi]

THANK U!

[@SimpleChemConcepts]

You're welcome!

[@conservingcommonsense4980]

What makes it so you cannot switch polarity of the connection to go back and forth minimizing material loss? Stupid question I'm sure. I'm good at those. 😅

[@shadmanaziz7920]

Why 4oh-

[@yaseenmohammad9732]

BEAUTIFUL, I WISH YOU WAS MY TEACHER........

[@SimpleChemConcepts]

Thank you for your compliment.