As representative of the state general of the Dutch royal democracy I hereby pardon your mispronunciation.
@emotionaljackfruit6 жыл бұрын
Loal
@hwinter33475 жыл бұрын
Lol
@zubaidaqasim54794 жыл бұрын
Lolol what even
@codehawkofficial4 жыл бұрын
lole
@userkeerthu2 жыл бұрын
Lol 😂
@Sofia-ow8go5 жыл бұрын
You made single-slit and double-slit diffraction easy to understand and now I am not panicking over physics anymore, you're the true og, my good sir.
@rvxn2 жыл бұрын
indeed
@ahmedibrahim92177 жыл бұрын
i like how he didn't ask for a like and sub in the end and simply said "you're all good"
@najjmx24225 жыл бұрын
Ahmed Ibrahim which deserves both a sub and a like
@HarshRajAlwaysfree5 жыл бұрын
Because it's Khan academy
@gmnahin3 жыл бұрын
That is called nonprofit organization...
@milkwasabadcholce8 жыл бұрын
THANK YOU, why isn't Huygen's principle taught BEFORE two slit interference in all the texts, you'd think this knowing this beforehand would save you from a lot of misguided connections.
@KimKim5658 жыл бұрын
milkwasabadcholce because it doesnt have anything to do with the doubleslit experiment. Different causes..
@googlesuckscock65387 жыл бұрын
Kim double slit interference involves the interference of two point sources. Single slit interference involves the interference of an infinite amount of point sources, and defines diffraction: they are definitely linked.
@davidk75442 жыл бұрын
science is all about being hard ;)
@REVIEWSGALATTA Жыл бұрын
in india huygen's principle and wave nature of light is taught first and then we move onto young's double slit experiment.
@helldi2blo11 ай бұрын
@@REVIEWSGALATTAyea exactly, its taught before and tbh it caused SO MUCH confusion, i have been stuck on it for a day 🥲 i was trying to find a connection bw huygens and double slit and obviously got more confused
@adolphmatjukotja70968 жыл бұрын
This concerpt never made sense to me until I watched this video,,, thank you a lot for the lesson
@unorthodox35934 жыл бұрын
😭😭I wanna cry coz I still don’t understand this
@boonheeliew24883 ай бұрын
Please refer to " Science Alert, current research in Physics".
@leonordin30528 ай бұрын
Its so stupid my testbook tells me nothing like this and expects me to understand. As others has mentioned you are a hero. its so easy to enjoyable to learn with your videos. thumbs up
@AshikurRahmanRifat7 ай бұрын
Same my book is also doesn't explain this topic well..This vedios explain it in detail
@agumonkey7 жыл бұрын
if huygen's interpretation was taught to me before geometrical optics I'd be an astronomer/photonicist. It's such a leap from too simple -> crazy, to weird -> everything become simple
@1dayfree Жыл бұрын
So let me bring to your attention the elephant in the room.... What are the light waves refracting THROUGH?? The universe is pretty simple when you think about it and don't overcomplicate and keep bombarding and bamboozling teenagers with complex formulas and experiments that are just the same as magic tricks (smoke and mirrors) . Thankfully I managed to see around the slit as it where 30 years after being brainwashed😁 n.b. I have left a few comments under single and double slit experiment KZbin videos that have questioned the narrative and all of a sudden I am now not allowed to post a new comment, just reply to one?? ..I must be onto something 🙄
@MS-qh3iz4 жыл бұрын
The ONLY single slit diffraction video that’s actually makes sense. Thank so so so much Khan Academy!! Saved my A level!!
@fenrir834 Жыл бұрын
Twhen my school teacher taught me this, i was unable to understand it, but with your explanation i think i understood it just fine. THANK YOU,
@jolez_48694 жыл бұрын
4:53 Engineers approximation: 8≈∞
@codehawkofficial4 жыл бұрын
hahaha
@jeffreyzwiebel1764 ай бұрын
Geniss i mean genius I mean I'm drunk
@rifathasan27412 жыл бұрын
You made this critical topic easy to me. Thank you so much sir. Lives in Bangladesh 🇧🇩
@namename31302 жыл бұрын
I have never had such a strong sense that something is wrong
@varunmudgal87523 ай бұрын
one of the best explanations of single-slit diffraction. good job
@bhaveshohal33905 жыл бұрын
Khan Academy....The Savior
@reetichauhan3555 жыл бұрын
Can someone please just make a playlist of all videos by David SantoPietro. That would just make life so much more easier.
@DanStep-yo3pv9 ай бұрын
Finally! Thank you for your amazing explanation. Absolute legend.
@alexandramitric Жыл бұрын
omg, what a good way to explain it visually, exactly like how i like to learn physics. THANK YOU
@danvladoiu93655 жыл бұрын
Your videos are absolutely brilliant! Excellent job and thank you for making this topic so clear and visual!
@Dhruv-Kumar2 жыл бұрын
I had to watch this 3 times to finally get it
@Fransamsterdam7 жыл бұрын
Very interesting, especially for a lay man who has been told so many times that only a double slit will show interference, thanks to quantum mechanics... By the way, your pronunciation of Huygens is quite good if I compare it how 't Hooft is sometimes announced on KZbin. :-)
@kiranrq93876 жыл бұрын
Fransamsterdam in your comment quantum mechanics solved the main question Hahn that each point acts as a wave thanks........
@catastrophe21553 жыл бұрын
This just motivated me alot to learn physics:D
@Bereket2D2 жыл бұрын
thank u thank u the first sentence that u said is why I'm looking for this in the internet I was so frustrated that all the books I have were talking about waves interfering with out telling me why they interfere in a single slit in the first place
@kiranrq93876 жыл бұрын
Omg you are a life saver ❤️... thank you very very much. It solved all of my questions which I posted in double slit experiment video regarding if the wave spreads out does that mean wavelength of that particular wave increases?
@kr1shnav Жыл бұрын
Nice 😊
@zulamanavraj96692 жыл бұрын
Thank you for this precious resources for the students
@shantaramchavan5063 жыл бұрын
Straightforward,pure teaching
@Frostbitecgi5 жыл бұрын
thank you .... now i understod that.... that was killin my brain for years :3
@mistofmipa77864 жыл бұрын
Terima kasih, materinya sangat bagus
@evanwolfson61304 жыл бұрын
I don't know why but I never seem to understand Kahn Academy. It seems like it should make sense (especially compared to my teachers) but it just goes in one ear and out the other.
@phumudzomamatsiari7872 жыл бұрын
Brilliant...thanks a lot🤗
@brighttips8203 Жыл бұрын
wonderful explanation💥
@rvxn2 жыл бұрын
A true lifesaver
@violinsheetmusicblog11 ай бұрын
Why are we only considering the points spaced w/2, w/4, w/8 apart? Shouldn't we be considering each pair of points instead since they each would contribute to the intensity? Also, it seems like even if the w/2 cancel because they are half a wavelength apart, the points w/4 apart wouldn't cancel because by definition they must be less than half a wavelength apart so I don't see the logic there at all.
@johnwilliams51522 жыл бұрын
I understand your explanation of single slit diffraction of light and the production of small maxima either side of the big central maxima. However, whenever single slit diffraction diffraction is set up in a ripple tank there is no sign of the small maxima either side of a central maxima.
@AdityaRaj-lj5wf3 жыл бұрын
This helped a lot.
@neetusharma10678 жыл бұрын
this is awesome I wish someone could have taught like this to me earlier
@anwesharout49815 жыл бұрын
The diagram is so damn satisfying! 😬 I know this is weird but it is (to me) 🙄
@Rocky-me5cw5 жыл бұрын
weird*
@jimf25256 жыл бұрын
This has bothered me for a very long time. Thank you very much for this video. Great explaination! My very minor criticism is when you say that the wave cancel completely at that point. Later, you explain that there is a slight difference [in the length of the triangle]. At that point you could add that’s why they don’t cancel entirely. But, I wouldn’t redo or add to the video if it changes the duration google posted as it gives you precidence! Again, great job and thank you for bringing up Huygen’s! - Jim Foit
@salah88881005 жыл бұрын
Good explanation. Thank You..
@SummitSeekers2125 жыл бұрын
Thank you so Much!!! The start of the video was exactly answering what I was looking for I had no idea their was so much more to it
@kayrstar89654 жыл бұрын
Love ur teaching skills🤘❤️
@rubayaislam34662 жыл бұрын
oh my god u saved me thank uuuuuuuuuu
@shubhamjhariya98778 жыл бұрын
I was so confused with this equation that path difference of minima is getting for constructive. Thank you for video
@Gamemaster81675 жыл бұрын
God bless you Sir
@HarshRajAlwaysfree5 жыл бұрын
This man is speaking the language of gods
@SquirrelASMR2 жыл бұрын
Omg hyungugons thing is cool
@Perfectgirlxx99xx5 жыл бұрын
I don't know if i should be happy or disappointed at myself because I'm not upset about anything lol
@mbk9287 жыл бұрын
Thanks, man. I am the best in my physics class! lol
@rajeshkshirsagar52355 жыл бұрын
Doubt: what if we took 9 sources(as in odd sources) instead of 8, wouldn't there be further complications with deciding whether it ends us up with constructive or destructive interference ? Kindly respond.
@VG__2 жыл бұрын
2:40 , 3:21 🌟
@jinghuiyu86113 жыл бұрын
I don't know if i have got it right but, the way you cal the different wave lengh as w/2*sinΘ confuses me,because the right part of light from the footprint seem to have different wave distance
@ayushagarwala41132 жыл бұрын
For once in my lifetime I was proud of myself for being clever but then "Ah! Not really." 14:14
@nukegundie Жыл бұрын
"Crazy, but true!"
@wo_ot545812 күн бұрын
i was wondered that if the screen is a curved arc, what would the interference pattern look like?😮😊
@weraponpat19137 жыл бұрын
thank you!
@sherazkhan28028 жыл бұрын
How can we be so sure that destructive interference will occur at those specific points like if the waves from the uppermost and the middle points interfere destructively at that point then it could also interfere constructively with the waves from the other points .... And why should we take half of the slit and not the full one ??? They are just ripping my mind @part!!!
@googlesuckscock65387 жыл бұрын
Sheraz Khan experiment
@ikstreme37187 жыл бұрын
For a destructive interference to happen, all the waves have to cancel out - the sum of their "heights" has to be 0. That means that for every wave with height y there has to be a wave with height -y at that point we are looking at. If it were otherwise, all other waves would cancel out and that wave would be "left alone" so that point wouldn't be a dark spot, the sum of the heights would be equal to its height = y. So whichever way you add the waves, you should always end up with the sum = 0 for it to be a dark spot. for example lets say you add up separately waves with positive heights at that point in a specific time, and separately the ones with negative heights then. lets say the heights are y,x,c,v,b... and -y,-x,-c,-v,-b... or what ever names you want to call them. The sum of the positives is y+x+c+v+b+..., and the sum of the negatives is -y-x-c-v-b.... and the ULTIMATE sum is (y+x+c+v+b.)+(-y-x-c-v-b...). As you can see whatever the sum of the positives is, the sum of the negatives is always - that, so the sum is always zero for that point. So pairing off the waves is just editing the sum (y+x+c+v+b.)+(-y-x-c-v-b...) to y-y + x-x + c-c + v-v + b-b +... (You must note that the heights of the waves are dependent on time so when I say that a wave's height is positive I mean its positive in a certain moment in time, not always, same for negative). You might ask well how do bright spots appear then. Well for bright spots at a specific moment there are more "positive" waves than "negative" ones, or vice versa, so not all of them cancel out, and thus the sum is not equal to zero and there is a constructive interference. Hope this helped :)
@sherazkhan28027 жыл бұрын
IKstreme Yeah that was a great explanation . But what I am thinking is that why should we apply plain Mathematics to it .... If I apply some logic , what my mind says is that there shouldn't be any destructive interference . Like , for example all the waves arrive at the same time ... You said there will be y for -y and x for -x and so on . But let say the y . Thus y could also be in destructive interference with the x wave or -x or what else you call it . Then , why should we add up the two y's (positive and negative) . Now you might say that x and y can't be added because they are different variables but let's forget about that because we don't have an equation like that . It could be numbers and then numbers could be added in any way . What my concern is that why should we be adding two waves from two distinct points while there are waves from numerous and numerous points . Based on your explanation , I think when we add them all together we won't be getting either a constructive or destructive interference anywhere ...There shouldn't be one of them.. I hope you get my point.
@ikstreme37187 жыл бұрын
if y and -y are in a destructive interference, and y and -x are also in destructive interference, then so are x and -y, so any way you pair them up the total sum is always zero: (y-y)+(x-x)= 0+0 = 0 (y-x)+(x-y)=0+0 = 0 Even if you add waves that are not in destructive interference the total sum will be 0. lets say y+x=a, then by simple maths (-y) + (-x) = -(x+y) = -a. So even if you do: (y+x)+(-y-x)=a-a=0 you still get zero because ultimately they somehow all cancel out
@sherazkhan28027 жыл бұрын
IKstreme Ok it makes sense but I am still very much confused . I am just thinking that how can there be + for every - when the waves are pointing at a point far away from the central point ?
@ryanaimtiaz8836 жыл бұрын
Why are we taking the topmost and middle point of the slit to get a dark point? How do we know?
@D8Football6 жыл бұрын
Ya I don`t get it either. He said "if it's destructive at half the slit length" and proceeded to make that scenario the official formula
@Kevin-cf2qe5 жыл бұрын
@Ryana Imtiaz He took the "topmost" and "middle" point, only for the sake of explanation. But this applies for any two arbitrary "points", as in reality, there's an infinite number of "points" within the band of light that passes through the slit, where you can't really select "points" that are "topmost" and "middle", as concepts like "points" are just an approximation...
@Kevin-cf2qe5 жыл бұрын
@@D8Football actually, it isn't the "official formula" but more of a presumption made to help find an explanation to why it so, i.e., why there's a dark region between the bright ones.
@unknotmiguel8 жыл бұрын
yes but when you make the middle of the slit half polarized then they should not interference with the other neighbourhood. also the cancellation is must happen at the slit point only. its not really like a lake of waves.. once it cancells its done, that wave wont de-cancell due to phase swap.. thats why when u move the wall back and forward, you dont see alternating blobs that would represent the peaks and destruction points intersecting the wall...
@MysticMD10 жыл бұрын
Wow thank you!
@PR0Z0MBIE98777 жыл бұрын
This is easy to understand. But what confuses me, is when two waves that run along each other completely PARALLEL and apparently never intercept each other can interfere with each other.
@AtulMishra-xi8qb8 жыл бұрын
thanx sir
@pokerater44638 жыл бұрын
it is pronounced "Ha-hen's principle"
@Anonymous011-KАй бұрын
Lifesaver
@chiragvashist84159 жыл бұрын
2:11 is really cool and "UGE"
@Syed-wj4pj7 жыл бұрын
Well then are there no troughs??...u can keep zooming in and all u see are wave fronts??
@nafisahmad86455 жыл бұрын
path difference for destructive points is (2n+1)*half lambda,so in this case why is asin theta=n*lambda not asin theta=(2n+1)*lambda
@venera43035 жыл бұрын
Im living for your "w" prononcuation, cuz its so cute
@vedikaaggarwal29738 жыл бұрын
Huygens principle is actually like having infinite slits and getting a uniform pattern because infinite points on wavefront form infinite wavefronts . may be!!
@higaddrip25833 жыл бұрын
How does infinitely many diffracting waves make a ‘full’ wavefront before the slit then? Why does the slit make the infinitely many diffracting waves into an interference pattern not a ‘full’ but smaller wavefront? I guess I understand that the slit can make a interference pattern but why doesn’t it do the same thing for a normal wavefront?
@infinitygaming48316 жыл бұрын
At the centre of the screen, there is zero path difference between each pair of sources and they interfere constructively . But the resulting phase of each contructive interference isnt necessarily in the same phase isn't it . That means the centre of the sreen which we see much brighter shouldn't be that bright.
@johanneskrv2 жыл бұрын
Well explained, thank you. Question: if hyugen's principle is true, how can you direct any light at a particular direction, for example a pointer laser? Shouldn't any light source always be a source of spherical wave fronts?
@blueheart45612 жыл бұрын
That are polarized light
@ht-ve9fe2 жыл бұрын
I think it's because Laser light is collimated which means the light rays are all parallel so, it spreads very little on it's journey.
@johanneskrv2 жыл бұрын
@@ht-ve9fe ok so would agree then that hyugen's principle in fact is not true?
@ht-ve9fe2 жыл бұрын
@@johanneskrv No I wouldn't because after certain distances lasers do begin to diffract. Other than what I need to know and the brief information I have read, I am not really in a position to comment whether he is right or wrong and he more than likely has greater understanding of the subject than you do and certainly more than me. However, from what I've studied, nothing disproves and there's plenty of people who have devoted their lives to Physics and even this topic which I am sure would have been disproved by now if he were to be wrong.
@johanneskrv2 жыл бұрын
@@ht-ve9fe i'm not saying he is incompetent. Just wondering why in some cases the hyugens principle seems to be in effect and in others not. This seems contradictory.
@rainbowunicornfart12329 жыл бұрын
Cool video
@mihreteabgirma63513 жыл бұрын
I know right 😒 "single" and then "interfered" wtf🥲 Thanks tho🥰
@shivshankar82177 жыл бұрын
please make a video on maxima minima and everything please?.
@bingingawaylife84053 жыл бұрын
Can you tell me in which video you derived dsin(theta)=delta x?
@anubhavbahadur5586 жыл бұрын
Great video ! Very informative ! Just one question , how is the difference between the two arbitrary points chosen , w/2 ?
@cinnamonbun2166 жыл бұрын
Anubhav Bahadur if you calculate it comes out w/2. There are 8 points hence the distance between two consecutive points is w/8. The points he chose had 4 points in between. Hence, the distance is 4*w/8 = w/2
@papiyaghosh1022 жыл бұрын
Actually it's not arbitrary, you set and divide the slit line up in such way that two points superposition cancels and things pair up.
@ehsanrahani2940 Жыл бұрын
@@papiyaghosh102each two pairs cancel out assuming slit is very small right?
@Abhijeet_Chakraverty7 жыл бұрын
It was nice playing that game to obtain wsinΦ=√\
@KM-bc3lm2 жыл бұрын
Not sure if this counts but I have a growing light for plants. Unintended experiment. There is a small single slit where light breaks through. I get 4 single strands of light in a tight angle, Red, Purple, Red, Purple. What the heck is going on here? Edit: Ah I get it, now, the edges spits the light. 1 edge, two beams. 2 edges 4 beams. I've never seen this before, I was just mindblown how it could happen without trying. Perfect conditions.
@sainithi35143 жыл бұрын
Actually at 11:03 shouldn't it be m+1/2??
@sarthaksharma93227 жыл бұрын
Hello, I wanted to ask something, in the video you divided that slit into 8 parts or let's say you have 8 sources, what if you make an argument that 1st source and 8th source interfere then I am getting wsin(theta)=lambda/2 ??
@CloudDinoGod7 жыл бұрын
If all integers give destructive, what gives constructive besides 0??
@paulregan93046 жыл бұрын
When path difference is an even number of half wavelengths you get constructive whereas an odd number of half wavelengths gives destructive.
@bingingawaylife84053 жыл бұрын
How is 5th source w/2. If there are 8 sources than the 4th source should have been w/2.
@_Olivine_3 жыл бұрын
It's like single-slit interference is like an infinite-slit, continuous version of the double-slit interference, I guess
@Aman-tf8bt4 жыл бұрын
Thank you sir you really give a very nice and simple explanation 🙂. Sir is it possible to also add mathematics of diffraction also
@kumarg21236 жыл бұрын
ya it's nice
@weising73025 жыл бұрын
I was wandering what is wsinD= wavelength but i had figured it out at the end of the video which is AX÷D = wavelength
@CalebDiT6 жыл бұрын
Huygen is "HOW-chen," with 'ch' pronounced as in 'loch."
@snehalsha64765 жыл бұрын
Walter Lewin said "HHURRHENNS"
@karthikeya35945 жыл бұрын
Which app you use for this demonstrate
@abhishekippili6774 жыл бұрын
how would you explain that wsinΘ=4Λ for 4th destructive point
@martindupuis55284 жыл бұрын
nice
@MrThingummy4 жыл бұрын
Don't understand why Theta remains the same at all point pairs surely it must change enough to make a difference. When the wavelength of light is in nm, (really tiny) a miniscule change in Theta would move the point from destructive to constructive.
@Rocky-me5cw5 жыл бұрын
Walter lewin said the name correctly(he is dutch)
@tonymon87511 ай бұрын
Brilliant. But puzzled by why the interference pattern is always horizontal. If Huygen's is correct then shouldn't there be a spherical pattern? Or... What if there was just a small hole instead of a slit? What would the pattern be?
@lepidoptera93377 ай бұрын
If we make a small hole, then the pattern is, indeed, spherical. It's called an Airy disk.
@boonheeliew24883 ай бұрын
Please refer to " Science Alert, current research in Physics".
@TON-vz3peАй бұрын
0:45 this representation of a light wave is absolutely wrong. Light is not one big wave which can span across space like a wayer wave. Its point fluctuations in the EM field. So multiple packets of light are actually going through the slit at the same time causing the interference
@ajeyabhat811910 жыл бұрын
there is no interference 1.all the points on the wave front are the source for new wave. 2.circles are drawn a the points as centres 3.the circles are joined tangentially 4.and light travelles
@suppandi10009 жыл бұрын
ajey bhat But the circles that traverse backwards get cancelled out by incoming wavefronts right? I don't see whats wrong with his presentation.
@nivedhithathiru18109 жыл бұрын
Spandan Bhattacharya we know tat amplitude =1+cos (teta), in forward direction, teta = 0deg hence amplitude will be 2..... in backwards direction, teta= 180deg ; ampli= 1+(-1) = 0....!!!! tats y there are no backwards wavelets..!! :)
@danieldavies13628 жыл бұрын
How come the points on the end of the wavefronts don't spread out as there's no point to one side of them? Also, when the wave meets a slit, how come the points next to the barrier on the reflected wave diffract, for similar reasoning as above?
@tmjcbs5 жыл бұрын
I'm going to be very nitpicky: his full name is Huygens, with an 's' at the end, so it's actually 'Huygens' principle'. 'Huygen's principle' would suggest his name is 'Huygen'. The pronunciation is acceptable: I can't think of an English word with the same 'ui' sound, even the 'RightSpeech' video on KZbin does'n get Huygens name right... Nice video BTW...
@shribalajiv280620 күн бұрын
It was clear. But why are we choosing two points which are half a slit distance apart. If we choose the top and the bottom point they would still interfere and form destructive pattern at lambda by 2 path difference. I am not understanding why we are choosing two points one in the top and the other one in the middle of the slit. Can anyone pls explain?