Slope deflection method

This video is example 1 on slope deflection method.
Chapters:
0:00 Question Explanation
1:12 Formulas
2:42 Fixed end Moment
4:48 Slope Deflection Equation
10:27 Equilibrium Equation
11:33 Final Moment
13:00 Bending Moment Diagram
For Example 2 on slope deflection method in Hindi Check out the following link:
• Slope deflection metho...
Cantilever Method:
• Cantilever method | st...
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Complete concept on:
Influence Line Diagram: • Influence Line Diagram
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THREE MOMENT EQUATION example 1:
• Clapeyron's Theorem Of...
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CONJUGATE BEAM METHOD:
• Conjugate beam method ...
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[@Civillearningonline]

Moment Distribution Method with sinking support: kzbin.info/www/bejne/hYmvo4OlmbeIfJI

[@premsaimarella5616]

Bro I think you had made mistake in the step of 2/3+3/8 which is 25/24. Thus the value of EI(ib) is 14.4

[@Civillearningonline]

You are right bro.

[@mr.gubagub1899]

Thanks bro I was confused because of this idiot

[@aayushpathak6120]

Exactly

[@aayushpathak6120]

He took deflection at c zero

[@ankushchoudhary8086]

3/5 is the right value

[@sahil8696]

Wonderful✨😍

[@bhandariakshaykumar5142]

It was crystal clear and explained very well... Very well executed the sum explanation.. We want this type of teacher in our country

[@learncivilwithparam170]

kzbin.info/door/gSu05skHs7WxhTd3doO1eg

[@parveenantal3163]

Mistakes are the sign of something good.. You are doing such a amazing work sir... Respect 💐 and keep it up.stay blessed.

[@waseemofficial5334]

Welldone

[@rahulrathee7999]

Sir shouldn't it be 25/24 EI ib In last line of 3rd step

[@rufusmatthew5664]

Superb

[@alaganijagadeesh1368]

Sir, for simply supported using formula 3EI/L... we get other valves of final moments and for simple supported using normal formula 2EI/2... Getting different values why?

[@Civillearningonline]

The formula which you have asked for I myself have consulted to my teacher when i was in college. And they suggest me to use the formula which i have used in this video. No doubt the formula which you are showing is correct but it's actually not used when you have a look in some higher books.

[@tlnnarasimhamurthy1529]

Wt about step 3 final that is 24/25 didn't get how 25 will come ?

[@revanthl9276]

I think he made mistake when we do the lcm it becomes 25/24 because (2/3+3/8)

[@mohdwasim3438]

Bro handwriting is superb 👍

[@faladeadetola6287]

Summation of moment at point B ought to be equals to zero (MBA+MBC=0)

[@Civillearningonline]

Yes. Right

[@tlnnarasimhamurthy1529]

How it will get 125? In step3

[@PavanKumar-xp9ik]

Sir in slope deflection eqn how at Mbc taking hinge Plz reply anyone why can't we do same procedure as we did

[@Civillearningonline]

Here is your answer. We need to use that equation when our hinged support is at the end of the beam. If we use the same equation then we will have one variable more than the number of equation.

[@Civillearningonline]

And to prevent the solution getting lengthy we use that equation. And it is easy to recognize whether the support is hinged or fixed just by observation.

[@Civillearningonline]

Here is my another video on slope deflection method here i have provided all the reason of using that equation , recognizing the fixed and hinged support as well as the problem that we face if we use general equation of slope and deflection. If yuo still face any kind of difficulty then let me know. Fell free to ask. kzbin.info/www/bejne/p4KkonqYgJZsi6M

[@alaganijagadeesh1368]

Sir, for simply supported using formula 3EI/L... we get other valves of final moments and for simple supported using normal formula 2EI/2... Getting different values why?

[@Deekshith9844]

Bro formula is wl/4 not wab/L

[@Civillearningonline]

Yes you are correct. And i have used both the formulas at the end the result is same. So don't hesitate just prepare well. Thanks.

[@abhishekpatil6380]

Sir can we get still more problems

[@Civillearningonline]

There more such problems i have discussed you can check out the playlist or description.

[@king.kundansahani2346]

Nice

[@Civillearningonline]

Thanks alot

[@rohitsukale9473]

👍👍😊

[@gphanichetan2824]

bhai everything is perfect but agar question mein find the slope bole toh final answer kya likhna hai?

[@akhilpp009]

What is diff between slope defln and kanis mthd

[@Civillearningonline]

Kani's method: It is suitable for multi storey building. As there is no need of deriving equation and solving it. So it's time saving. While, Slope deflection: It is used to analyse both statically determinate and indeterminate structure. Considering deformation due to bending only.

[@shreyashsaxena2568]

Sir why was the expression for Mbc different that the other expressions

[@Civillearningonline]

It's because our support C is hinged and lies at end. Do follow the step shown in the video whenever this case arises. It reduces one unknown and the solution becomes easy.

[@powerstar76]

Bro explain clockwise and anticlockwise direction

[@Civillearningonline]

Clockwise means the movement which is similar to the movement of ⏰ like _ 1, 2, 3 and so on. While anti clock wise is movement opposite to the direction of movement of ⏰. Eg. 12, 11,10,9 and so on.

[@powerstar76]

@@Civillearningonline I mean in the problem Clockwise means +or -

[@Civillearningonline]

Clockwise +ve and anticlock wise -ve if we are taking moment about RHS and ( clockwise will be -ve and anticlock will be +ve if we are taking moment about LHS.)

[@sabirsayyad8182]

How to find support reaction in this problem can anyone tell me plz

[@sabirsayyad8182]

For last cantilever span only

[@Civillearningonline]

If we consider only last cantilever portion of this beam, then it's reaction will be -6KN.

[@powerstar76]

Bro u told that upwards direction is - it's downwards means +

[@Civillearningonline]

It's sign convention for find shear force.

[@michaelib7093]

Sir, why is Mab negative

[@lukmanopeyemi8761]

Anti clockwise moment

[@paruvumanoj8167]

Sir the value of Mcb is zero right then why haven't you substituted while drawing in diagram?

[@Civillearningonline]

Support C is simply supported but span CD is overhanging so the moment due load on CD is transferred to support C.

[@paruvumanoj8167]

@@Civillearningonline ok sir thank you

[@hymavathi.v18]

Sir was it only one hinge support at c?

[@Civillearningonline]

Yes

[@hymavathi.v18]

Then at B was it simply supported beam

[@Civillearningonline]

Simply supported beam are actually the beam having hinged support.

[@Civillearningonline]

You will find this when you will practice some some numericals. It need practice and once you practice it's gonna be fun. Believe me😁

[@gururajln282]

What about joint "C"

[@Civillearningonline]

Here in this numerical joint C is hinged support. And always remember that we apply the condition "equilibrium of joint" only at intermediate supports. Here in the figure you can see that only joint B is intermediate and the joint A and D are lying at ends. And if there were given one more intermediate joint(D assumed) after joint C then we would have applied one more consideration taking the equilibrium of joint C. I hope i am able to clear your doubts.

[@Adi-dl9vu]

@@Civillearningonline Is joint d is continuous...if not then we taken as joint na..

[@gururajln282]

@@Civillearningonline send me your Email ID I have lot of doubts, in this topic, I will share that to you........ Plz 🙏🙏

[@Civillearningonline]

[e-mail]

[@lakshmybiju8532]

How did you find that the end C is hinged

[@Civillearningonline]

It's clear from the diagram.

[@Civillearningonline]

As you can see that the hinged support is represented by arrow.

[@lakshmybiju8532]

@@Civillearningonline then end B is also hinged am i right

[@Civillearningonline]

Yes

[@paruvumanoj8167]

Sir how do you identified point B is roller and point c is hinged

[@Civillearningonline]

If the support is represented as arrow then it's hinged and if it has a circle then it's roller support.

[@paruvumanoj8167]

@@Civillearningonline sir even though the point B is hinged we shouldn't use that equation...we should use that equation only for the 2 ndor 3rd span right??

[@akarshben4982]

For point load..... WL²/8 ryt..... Or just WL/8...

[@Civillearningonline]

WL/8

[@samiullahkhursheed8140]

Sir how to get Deta A and Deta B in Casio

[@Civillearningonline]

I am unable to understand your question. Please clearfy.

[@Civillearningonline]

While solve equation we do not need to enter Deta in casio. There is another way of solving the equation in calculator. 1.Press mode 2. Press 5 Now Select the type of equation you want to solve. Now enter the constants.(i.e.numbers) Hope you got your answer.

[@fathimashinmiyal9590]

Sir..pls confrm the value of EIib..it's not 125/8 ..correct value is 72/5

[@fathimashinmiyal9590]

Then only the final moments value will be same..

[@Civillearningonline]

Yes you are correct. I am extremely sorry for this. It has happened because i have mistakenly written 25/24(EI.ib) =15 as 24/25 (EI. ib) =15. Thanks alot for letting me know. By the way i have another video in hindi on same topic. And i am sure you are going to find it very helpful. Have a nice day.

[@Civillearningonline]

Slope deflection method in hindi: kzbin.info/www/bejne/p4KkonqYgJZsi6M

[@isolemayian6181]

What if the other end was also fixed

[@Civillearningonline]

Check playlist you will find an example related to that concept.

[@paruvumanoj8167]

Sir why you haven't find Mcb?

[@Civillearningonline]

Moment at hinged support is zero.

[@paruvumanoj8167]

@@Civillearningonline sir point B also hinged then why we haven't kept zero sir?

[@Civillearningonline]

But support B is at intermediate position.

[@Civillearningonline]

Dear paruvu, I have created a seperate playlist on my channel for slope Deflection Method you should check out some other examples also. Then I am sure you will be able to clear all your doubts.

[@powerstar76]

CtoD not there? Lot of confused how it will get 125/8 &

[@Civillearningonline]

I hoe you understand Hindi check out the playlist you will find some other examples of this method and they are going to help you alot.

[@powerstar76]

@@Civillearningonline no sir can't understand in hindhi only kannada and english but

[@powerstar76]

How it's came not understand

[@Civillearningonline]

I will reply you shortly.

[@Jaydev-oj2hx]

Bro, u told that for midspan, moment is Wl/8 in the beginning, but 12:35 here u put Wl/8. Why?

[@Civillearningonline]

Yes dear. While calculating fixed end moment we use WL/8. And at the time of drawing BMD we need to use wab/l for point load and wl^2/8 for udl. Hope you understood.

[@Jaydev-oj2hx]

@@Civillearningonline yes sir. Thanks

[@shaanchutoori]

how do we know that “c” is hinged

[@Civillearningonline]

Hi ged support are represented by arrow headed upward or triangular shape. Go through some problems which will help you to distinguish different types of supports.

[@tiamiyuhamed9333]

B is also hinged then

[@Civillearningonline]

@@tiamiyuhamed9333 B is hinged in this question. We need to check whether the support at the farther end is hinged or not. That's it.

[@maniaanayak8919]

Mcd=-6*2 kese hua thora bataiye

[@Civillearningonline]

Because humar end c hinded he and support c k right pe overhanging portion bhi he so jab overhanging portion right side rahe ga then hum us k karan jo moment aaye ga usko -ve lenge and agar humara overhanging left side hota to hum moment +ve lete. I hope aap ko samajh aaya hoga. Best of luck for your exam. Description me aap ko 2nd example ka link mil jaye ga. Dekhlo wo bhi. Once again best of luck.

[@irshadmohammedkhan6719]

While writing in exam for shot heading i have to use red pen

[@Civillearningonline]

You must not have used red pen.

[@shashwatpoudel7273]

Ramro sanga van na ehh

[@Civillearningonline]

Playlist hera. Aru pani video xan. That will help you a lot.

[@aktrending2136]

Can you please explain step 3 I'm not understand how u get values EI (ib) 🙄

[@Civillearningonline]

Simply solve the equation using calculator or manually by elimination method.

[@haroonrasheed7697]

In 14:32 how do u get 18

[@Civillearningonline]

Hello dear, First of all thanks for your comment. Here is your answer, It has happened because of overhanging portion at support C. Your question is we take moment 18 at C. You will find your answer at 8:59 - 9:30. Do watch that step you will find your answer. Have a nice day....

[@haroonrasheed7697]

@@Civillearningonline tq so much 👍

[@devanshipandya337]

👍👍

[@revanthl9276]

How come it's 24/25 it must be 25/24 right?

[@Civillearningonline]

Yes. You are right. Sorry for it.

[@revanthl9276]

@@Civillearningonline it's ok

[@srujanatenneti4827]

How to do it when there is no simple support at C? Thank you sir

[@Civillearningonline]

If there is no simple support at c or if there is fixed support at c then use the usual slope deflection formula and and there will be no need of providing free moment.

[@srujanatenneti4827]

@@Civillearningonline ok thank you sir

[@Civillearningonline]

@@srujanatenneti4827 if you understand Hindi then you can watch my another video on same method and i am quite sure the these videos are going to be very helpful to you. Do check out the description section. Best of luck for your exam.

[@srujanatenneti4827]

@@Civillearningonline thank you sir. I do understand hindi.

[@SandeepYadav-bj1zl]

You played many gemics in this video not yet clear

[@Civillearningonline]

You can check for some other videos. I have created a seperate playlist on this method with extra examples.

[@kavikavi4744]

Mba +Mbc= 0 so how that 34.41 and 33.14 came. must be both same.

[@Civillearningonline]

Hello dear, First of all thanks to you for your comment. You might have noticed that we have got (EI/ib) in all three equations. And we have calculated the value of (El/ib) using the portion AB of the beam. Also, I have not used Mba + Mbc = O here in this numerical. And that's why we have got that answer. And believe me it won't create any kind of problem. And one more suggestion to you to solve problems related to slope deflection method. Try to use both the equation i.e. equation for fixed end and hinged support whenever you have such questions. Because incase if u are using the same equation through out the the Numerical gets trouble some i myself have faced that. This was my first video on this topic. I will soon be adding more examples to clear ur all doubts so stay connected by subscribing @civillearningonline. And i will show the application of Mba + Mbc =O in some other example soon. Thanks alot for ur comment. Have a nice day.

[@Civillearningonline]

I hope this video is going to help u alot. kzbin.info/www/bejne/p4KkonqYgJZsi6M

[@Civillearningonline]

I have no idea whether you are familiar with Hindi language or not. Let me know by replying this. I am ready to help you out with all your confusion.

[@kavikavi4744]

im from srilanka . can you make moment distribution method little hard question in english. before 15th . i will share your video with my friends. thank you .

[@Civillearningonline]

Of course I will. On each and every type soon.

[@victory_bestie4593]

Sir iam not understand because your talking letters at below. So background are totally dark exact step are not visible to eye

[@Civillearningonline]

Please check playlist you will find some other examples on this method. And i am sure they are going to help you alot.

[@Civillearningonline]

Here you go. kzbin.info/aero/PL513Y7_xBTnAprzGbIpMFzGm-ju1ZiCuS

[@kingsman5813]

Yr sahi sahi likh ta kite thirty likhi jnda kite thirty nine

[@Civillearningonline]

Bhai playlist check karlo ek video hindi me bhi he. Hope Ap ko achha lagega.

[@Civillearningonline]

kzbin.info/www/bejne/p4KkonqYgJZsi6M Slope deflection method in Hindi.

[@byniritheshkumar9053]

where is Mdc bro?

[@Civillearningonline]

Span DC is overhanging portion and there is no support at D so there will no moment (Mdc).

[@vedantauti221]

Vedant Auti 🦋 Roll number 26

[@Civillearningonline]

#binod 😁😁

[@Civillearningonline]

@Pratik Aute pratik auto😂😂

[@Civillearningonline]

@Pratik Aute it's not so hard. You just need some practice. Prepare well. Best of luck.

[@Civillearningonline]

@Pratik Aute well done 👍👍

[@nijanthanperumal7516]

talk loudly

[@K1M01]

Shhlurrppp ..........

[@shaistakhan6476]

Mcb/2=15 OR AAP NE 18 LIYA HAI...18/2....DON'T UNDERSTAND .......PLZ REPLAY

[@shaistakhan6476]

Or aap n 18 likha hai diffrence

[@shaistakhan6476]

formula mai aap n mcb/2 hai ....mcb ki value 30 h.... 30/2 lena hai to 18/2 kiyu liya hai....

[@Civillearningonline]

Hello dear, Aap ka question he ki Mcb/2 ko 18/2 q liya gaya he? Ans: Humara jo support c he waha pe 2 moments aa raha he ek to point load jo span BC pe he and dursra overhanging portion CD. To aisa case me kya hota he ki hum total moment at C ko lenge ge. And is k liye C pe lag raha sara moments ko hum add karenge. And humne to fixed end moment at CB +30 calculate kiya he. And overhanging portion ka load 6KN , negative moment generat karta he at C and jab hum add karenge (+30-12) at C pe to wo humra total moment at C hota he . So Mcb/ 2 = +18/2 le te he.

[@Civillearningonline]

Maine isi liye such type question kiya tah ta ki koi confusion na ho and yaad rakhna aap jab bhi overhanging portion aaye to us k karan jo moment generat hoga us ko hum include karenge.

[@Civillearningonline]

Agar samajh me aagaya to reply ko like kardo aap ta ki muje pata chaljaye ki aap ko samjh aaya. And aap ko ek aur video mile ga same method pe hindi me aap us ko bhi dekh sakte ho.

[@rohitdongare7623]

Dongare Rohit

[@Civillearningonline]

#binod 😂😂

[@asifshaikrc2786]

English aya tho baat kar bhai ni tho hindi may hi bol plz🙏

[@Civillearningonline]

Ye lo bhai hindi bhi he kzbin.info/www/bejne/p4KkonqYgJZsi6M

[@asifshaikrc2786]

@@Civillearningonline bura mat manna fir 😊

[@Civillearningonline]

Koi baat nai yar, Just prepare well. Best of luck

[@humanfirst5483]

Hindi bolna bhaiyyo

[@Civillearningonline]

Ok