Smith Chart Example for Transmission line Parameters (VSWR, Reflection Coefficient & Admittance)

[@EngineeringFunda]

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[@vishnuprakashjaya642]

Sir videos are super and simple explanations 😍

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[@fehmi1004]

Thank you, sir. again a Great lecture

[@EngineeringFunda]

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[@user-ip2vx]

great work sir which is very helpfullll!!!!!!

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[@ravexi6622]

Amazing Video

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[@lightyagami6345]

very helpful lecture sir......

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[@704nazmusshakibneshat9]

Thank you so much sir

[@OnlyCompleteSolution]

Very good video doubt is clear thanks ❤️

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[@jerinaa967]

How did u move and place 0.1 lamba ?

[@sakshisharma2930]

Sir, why we take load towards the generator to find Vmax and Vmin?

[@engineeringuniversity]

Thank you very much

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[@lirancohen1350]

Sir, how can we go towards generator by 0.338*lambda if L=0.1*lambda? it passes it by far.

[@fabregod24]

Hello, Liran Cohen. Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)

[@vigneshnambiar8908]

​@@fabregod24very well explained ty ❤

[@fabregod24]

Hello, Sir. I'm really grateful you with your job. I just wanted to say Thank so much. Besides that, I have noticed a mistake in this. When you find the Input Impedance, you said that it's 2.8, but it's 2.6 since the chart smith over there goes from 2 in 2 by line. Hope you are fine, and I'll be waiting you answer.

[@EngineeringFunda]

Solution is perfectly correct as it is computerized solution dear.

[@fabregod24]

@@EngineeringFunda Oh, well, I'm sorry then. I thought that the line that was before the 3 is 2.8, and the one that is before the 2.8 is 2.6, which is where the interception point is in the video.

[@pranavterkhedkar2831]

When you making Input impedance real why you did not multiplied with Zo here ????? Purposely??? Or you forgot to multiply???? ByTheWay Thank you to My favourite Virtual Teacher ❤❤ keep Going Sir....

[@EngineeringFunda]

Actual value will be Zo × Z.

[@pranavterkhedkar2831]

@@EngineeringFunda ok❤️

[@Rajdey4481]

sir could you please tell me that how to calculate vmax 0.88 lamda?in this question

[@namege]

Great lecture! Which software do you use for drawing the VSWR circle and lines?

[@EngineeringFunda]

PPT

[@khushshah6139]

The input impedance is normalized, to find the real value, it needs to be multiplied by z0.

[@bhawanishankar713]

thanks

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[@manyatapattnaik2784]

I want to find input admittance.... whether we can find it extending the line of input impedance

[@nani-t2i1c]

Tysm

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[@srinivaskadama]

How you tell that value of Vmax =0.008 and Vmin value how u calculate sir

[@fabregod24]

Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)

[@sudarshanchauhan6005]

Sir How come Vmax is smaller then Vmin??

[@EngineeringFunda]

Where?

[@EngineeringFunda]

It is location not value

[@sudarshanchauhan6005]

@@EngineeringFunda ok. I got it Thank u

[@umaschannel3244]

Sir the distance between load and generator is 0.1 Then how is the V min at a distance of 0.338 from load towards generator

[@_KTharun]

How V max value is 0.088??? Can you explain ..!!

[@Lokesh-hc3ji]

sir can you explain how you are moving 0.1lambda value

[@EngineeringFunda]

Towards the generator means clockwise rotation. See the question in which it is given that move by 0.1Lambda from the load. Here from the load means towards the generator.

[@_KTharun]

@@EngineeringFunda sir how V max is 0.088 lamda !!

[@diyasoni7605]

@@_KTharun did you solve it? can anyone explain how vmax and vmin calculated? sir please be clear

[@ananyachakraborty8498]

sir please make a video on double stub matching on smith chart

[@EngineeringFunda]

Noted your request

[@lofi_song562]

Sir how your measure 0.0338 lembda and all i confused

[@Bablooo69]

It's actually 0.088 lambda It's calculated when u take the distance from zl line on generator to the vmax line

[@pseudohawk1656]

There will be non minimum right? Because 0.388 is not possible on 0.1Lambda line

[@fabregod24]

Hello, Pseudo Hawk1. Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)

[@sheshadrisheshadri1389]

How 0.088lambda L=0.1lambda plz reply sir

[@EngineeringFunda]

Data is given in question dear

[@ronaldleon6952]

Hi, how do I find the Zin at the generator?

[@EngineeringFunda]

By moving from the load in clockwise direction we can get Zin

[@ronaldleon6952]

@@EngineeringFunda hi Tks for the response, until which position do I have to move clockwise ? And once I move there how do I find the impedance ?

[@EngineeringFunda]

@@ronaldleon6952 for that I have already made video on smithchart, just go through my playlist

[@shashankcholleti2003]

how is lamda assumed sir

[@EngineeringFunda]

It is not assumed dear.

[@princeaidam6732]

How is Vmax value 0.088 please any explanation

[@pranavterkhedkar2831]

End point minus starting point Which is 0.25-0.161

[@curio9541]

how is Vmin larger than transmission line 0.1

[@EngineeringFunda]

It is possible dear

[@argypan6879]

if Z_L = 1+ 1j and Y_L = 1 / Z_L then Y_L = 0.5 - 0.5j not 0.52 - 0.52j

[@saikiranffgaming5502]

Sir Vmin value is wrong