Smith chart problem 3 | EC8651 | Transmission lines and RF systems

[@dharanineduceliyan07]

how did you find the admittance value as 0.41+j2.31...where the values located

[@jegabot5377]

It's the coordinates of the point B that you get by extending the line 0A to the circle

[@tejaspednekar1412]

More importantly...it's normalised which u get from Smith chart....so to get admittance shouldn't it be multiplied by Ro????