SN74HC244N Octal Buffer

[@dropsosense1506]

It is nice to see the 244 in use. In the 1980's the 244 and 245 (bidirectional) were often my go to for bus use.

[@nozynoz]

nicely explained and demonstrated could have not put it better my self. Cheers. Thank you for your video.

[@synthesizer.repair]

Brilliant explanation.

[@W1RMD]

Great video. Thanks for sharing!

[@durgaparshad1928]

Hello sir.. I want to know that programme burn in these ics?

[@quieneressomoslegion930]

Friend, I have a big question, I have a BTS7690 module that is used to control the direction of a DC motor, but the SN54HC244 integrated circuit has continuity in the VCC and GND pin (pin 10 and 20), is it in another circuit? I would appreciate your help friend

[@tuppyglossop222]

I assume that when you release the input enable switch the chip retains the state of the data switch?

[@SteveRaynerMakes]

No, when the output enable lines are high the outputs are high-impedance, when the output enable is low then the outputs match the inputs. Nothing is stored.

[@tuppyglossop222]

@@SteveRaynerMakes Because it’s a buffer and not a latch? (A mechanical engineer cosplaying an electrical engineer here...)

[@W1RMD]

@@tuppyglossop222 Correct! Watch Mr. Carlson's Lab Nixie Tube frequency counter video thats 116:39 long at the 34 minute mark to see the chip in action.

[@edoardomariascardamaglia4325]

Very good 👍

[@SteveRaynerMakes]

thanks

[@Lucretia9000]

I'm just reading through Steve Ciarcia's book and have this and the HC254 and I was going to use this to buffer the Z80, but then I read on a forum that they recommend 74LS244 instead because they're schottky's. Can I use the ones I have?

[@SteveRaynerMakes]

Do you mean a 245? I'm not aware of a 254. If so, both the 244 and 245 are schmitt trigger. Not sure about the schottky part you are referring to. Where as the 244 is unidirectional, known as a buffer, the 245 is bi-directional, known as a transceiver. I believe either would work in this application. I would presume back in the day the 245 would have been more expensive. But I'm only guessing.

[@micknorthyard815]

If you mean HC versus LS then it might work, or it might not. The voltage levels are different HC=CMOS and LS/HCT=TTL