Sochne Ka Tarika EP- 5 | England Olympiad Question | IIT JEE 2025 | Anshul Singhal

[@Acadza]

New SKT Video agaya hai

[@abhijeet_851]

sir 16:19 we will square both side & then we will take c^2 in denomiantor & Apply AM-GM then restore back the sin alpha. Ans to question at end is : x = tan^-1 (x)

[@unnati5385]

Sir aise hi SKT aur fundas laate rahiye. Prob solving me help krti

[@anshul8330]

Haan bilkil

[@jeeaspirant7210]

Soln of last prob tan(2x)=c/3 , tan(x)=2/c tan(2x)tan(x)=2/3 2t²/1-t²=2/3==> 2t²/1=2/(3+1) [CND] TAN(x)=1/2 x=tan-¹(.5)... Thank u guruji assuming coordinates is such an amazing approach... 🎉

[@anshul8330]

Haan uska answer shayad 1/2 sin invoice(0.8) hai

[@jeeaspirant7210]

@anshul8330 haa sir maine calc pr dekha dono ki value same aa rahi hai...

[@jeeaspirant7210]

26.56505° aa rahi h...

[@anshul8330]

@jeeaspirant7210 Wohi hai

[@Naman_shukla410]

Sir please" nichoda method (of integrals)"ko bhul mat jaiyega.

[@anshul8330]

Use daal denge kisi SKT video mein. Please share the video to help our little channel.

[@Naman_shukla410]

@anshul8330 already shared in group :)

[@NehaSingh-s5n5w]

Sir please upload relevant videos. I request you to make jee main pyq videos of last few years chapterwise. Plz atleast 5 chapter ke upload kar dijiye before jan attempt 2025. Pnc, probability, AOD, Straight Lines, Vector 3D

[@anshul8330]

PYQ aap khud solve karoge to jyada benefit hoga. They are already available on Google.

[@utkarshndaaspirant28]

Sir KZbin par course aya ga kay

[@souravgupta6884]

Problem question ans tanx=1/2

[@anshul8330]

Yes

[@FizaRizwan-zg3qp]

Sir ji video bana ke information du na ke batch aa rha hai 12 ka early ka aur bhi bacche jane ge

[@anshul8330]

Haan Bhai...Video banaunga.

[@FizaRizwan-zg3qp]

@anshul8330 ji sir

[@SATYAM-W7]

Very beautiful

[@SATYAM-W7]

Sir aap koi batch development par focus karte... please 🙏

[@anshul8330]

​@SATYAM-W7Early 12,th and ek 11th wasted batch aa raha hai

[@anshul8330]

Video share kar do bro

[@FizaRizwan-zg3qp]

Sir ji sahi me batch aa rha kya 12 ka

[@FizaRizwan-zg3qp]

Sir ji discount kar dena thora 😅

[@FizaRizwan-zg3qp]

Sir ji har jgah har unacademy ke batch me bol diya hu ke anshul sir ka 12 batch 15 jan se aarha hai isse aur bhi bacche aayenge padhne

[@UtkarshTripathi2007]

Sir are you launching a batch for jee advanced after January mains?

[@anshul8330]

Yes

[@FizaRizwan-zg3qp]

Sir ab batch laa bho do ab rha nhi jata😂

[@FizaRizwan-zg3qp]

Sir ji batch ka kab announce kar rhe hu

[@anshul8330]

Soon. Bola na 9k

[@FizaRizwan-zg3qp]

@anshul8330 mtlb sir prices hai 9000 na

[@anshul8330]

@@FizaRizwan-zg3qp Subscriber base 9k hoga tab.

[@Itz_gaming2.0]

Sir ji 12 ka batch aa rha kya kitne ka hai price bata do

[@anshul8330]

9999

[@ameyagfx]

My solution for the first problem: let the smaller angle be theta,we have: 90 deg > theta > 0 90 deg > alpha > 0 also: tan(alpha + theta) = 2tan(theta) ---- (1) Let tan(alpha) = y and tan(theta) = x; Rearranging 1, we get: 2yx^2 - x + y = 0 Now since theta is in the first quadrant, tan theta is positive and hence the roots are real. D >= 0 gives us: y^2 s is sin(alpha) s^/(1-s^2)

[@anshul8330]

That looks good.

[@FizaRizwan-zg3qp]

Bhai log sir batch la rhe hai bhai log

[@anshul8330]

Koi x bhi bata do kitna aaya?

[@AyushPatil-cs7xs]

x=tan^-1(2/(root11))

[@anshul8330]

I think 1/2 (sin inv (0.8)) hai

[@AyushPatil-cs7xs]

@@anshul8330 Haan sir, aaya

[@ninja-nd1wm]

Thank you sir but tbh it was easy sir Pls bring tough Q and amazing fundae 😀

[@anshul8330]

Funda 18 came.

[@anshul8330]

Mains nazdeek hai is wajah se too tough question par nahi jaa raha hun...Chalo very soon kuchh tough laata hun

[@notsumittt]

@@anshul8330 these videos are so good , im so thankful to the senior who recomended your channel to me

[@anshul8330]

@@notsumittt Glad to hear. Please share with others to help our small channel.

[@saketkumar-]

In last step multiply in denominator and divide Num/Den by c and apply am gm c² +4/c² +5 >= 9

[@anshul8330]

But will that work? Do alag alag terms mein AM GM? Ya fir chaaro mein mila kar?

[@anshul8330]

@saketkumar- Haan you are right.

[@Supp12345]

On further simplifying sin(a) Sin(a) = 1/ (c²+ 4/c² +5)½ Applying AM≥GM on (c² + 4/c²) maximum value is 4 Hence Sin(a) ≤ 1/(4+5)½ Or Sin(a) ≤ 1/3

[@anshul8330]

@@Supp12345 Haan ye achha socha aapne...Mein nahi soch raha tha tab

[@sibasishpadhy9172]

@xpyre9796 exactly