Balancing Chemical Equations with Algebra (Chemistry)

[@thegoodlydragon7452]

Wow. This has really helped me really grasp algebra much better. I like to see it applied in a concrete way where I can see clearly what X, Y, and Z represent. Thank you so much!! When next I cross the path of somebody struggling to grasp math or chemistry, I'll recommend this channel. :)

[@byeol6981]

she is seriously a life saver, thank you so much.... gonna nail my test!

[@Socratica]

We're so happy to hear you found our video helpful! Would you do us a favor and share it with your classmates? That will help our channel grow! Good luck on your test!! :)

[@notsorarevolcano2912]

this is amazing! the best thing about this is that im learning both chemistry and math at the same time, thanks alot!

[@lemueljohnurbano4448]

This is the video that introduced me to Socratica. I was searching for videos on balancing equations because I was tired of doing the trial and error method. Learning algebra was a pain for me because I just can't see the sense of all the numbers and letters. But here is this video using algebra to systematically balance equations. So I checked out the channel and the rest is history.

[@saumyatripathi935]

you made balancing so easy. i hope most diff. equation can b balanced by this method

[@user-pz6tb3yq4k]

This is so much better than the guessing game i usually play!!!

[@vinaykumar-co2dw]

Thanks for helping me to understand the balanced a chemical reaction by algebric method....

[@Socratica]

You are very welcome! We're so glad you are watching!! :D

[@adolfninh23]

Appreciating this, really ! My chemistry teachers never teach me this method

[@PANKAJYADAV-om2tk]

You are the best teacher

[@robithevampire]

Where did the number 4 come from in 9:30? Is it the equivalent of A, B, C & D?

[@Socratica]

Great question, Robert! We are multiplying through by 4 to get rid of the 5/4 fraction in front of the O2. It will get rid of the 3/2 fraction in front of the H2O as well. You can multiply the entire equation by any number you want, as long as you multiply both sides. Imagine you multiply the entire equation by 2 - that's just saying you have double all of the amounts. Multiplying by 4 just means you have 4 of these reactions running simultaneously. It doesn't change the balancing of the equation - it just makes the numbers easier to deal with.

[@techworm3609]

Robert Ocon Dado u have u multiply it by LCM like the LCM of 2 and 4 is 4

[@TaboteHaile-kp9xo]

You are a best teacher I never seen.🎉

[@Socratica]

You are so kind. We're glad you're watching!! 💜🦉

[@thatonzimande9612]

thanks Mama ,,u know there was sum bout ur voice that jst made me understand

[@deepakkumarrai5759]

fantastic mam i never thing algebraic method for balancing another then hit and trial method

[@jellyrice5599]

That method are very help me. I had know that it was have this method but no one that i just heard before was explain with clear and fluid describe like your video. I like those example they are cover all of my question to this method. Thank you so much.

[@KenMyles-xt2yw]

The background music suggests that music is needed in order to learn. Background music in a classroom would interrupt and compete with the main purpose of the classroom which is for students to learn, but not to be hearing music or any other sounds which interrupt or compete with the instruction.

[@vinaykumarsonti3186]

thank you☺its really helpful..😊

[@heshamwaleed4069]

I really like algebra, its so powerful and I love it

[@Socratica]

It really does help you approach problems with confidence! 💜🦉

[@martinezmelmar3908]

9:30 (Example #3 ) How did you say that we need to use "4" ? As a coefficient ? How did you get "4" ?

[@_hydrogelic]

She's multiplying by four on both sides to eliminate the 5/4 coefficient of oxygen

[@Zephon9]

I like the algebraic method better. Partially because I like and have done so much math.

[@Socratica]

+Zephon9 Personally I agree - I love using the algebraic method - it just makes so much sense to me! Thanks for watching and commenting! :)

[@kennywen3041]

Same here!

[@srv1tz_foxy793]

@@Socratica it doesn't make ANY sense for me at all

[@nnmott1]

Omg. First video .. I love this Kim! New fan right here.

[@Socratica]

Thank you so much for visiting, Natasha!!! :D

[@PANKAJYADAV-om2tk]

You have cleared all my doubt

[@Socratica]

Wonderful!! We're so glad you are watching and learning with us!! 💜🦉

[@nithishkumar768]

thank you so much......this helped me a lot!

[@Socratica]

You are very welcome!! We're so glad we could help. We'd love to hear what other topics you would find useful! :)

[@robinzatulovski4098]

thank you so much!

[@Socratica]

robin zatulovski We're so glad you found our video helpful! Thanks for watching!

[@Shiv-z8i5n]

Thx a lot plz keep up the good work :) cheers!!

[@SUMIT.TUTORIALS]

I love your explanation Thank you so much #great work.

[@ravitirumamidi489]

why did you take a=1 in the end .....like how do u know which substance to be taken as 1 !!! pls this video can help me a lot

[@2exokaiidolsidol648]

I think it's always and most of the time set as 1. Coz if you have fraction just make it to whole number.

[@ArjayMancio-qz1qn]

I really like algebra , it's so powerful and it's can help to me😊

[@Socratica]

We feel this way too! It's so useful!! 💜🦉

[@mrunggolgt4145]

I love you! Thanks so muchhhh

[@Socratica]

We're so glad we could help!!! Good luck studying. Let us know what else we can do! :)

[@karenkwang3960]

so do you always set 1? for example you did a=1 do you always do one?

[@Socratica]

Usually - just to make things easier. If you set one variable to 1, you are automatically simplify the process of solving for the other variable(s). If you set it to something else, you'll just wind up having to simplify (divide through by some number) at the end. Try it and see! Thanks for watching :) If you found our video helpful, share it! That really helps us grow.

[@thinesho5344]

How do you know what molecule to start with? Does the molecule always have to have the value of 1?

[@YoshevElazarMikael]

thank you very much

[@tosintise6848]

Thank you so much. God bless you

[@physicssimplified1769]

On 7:40 you said that no. Of hydrogen are equal on both sides.how is this possible 2H and 2H are not same

[@Socratica]

Raj Singh Thank you for watching and commenting! Could you give a little more detail to your question? Is it possible you mean a different time than 7:40? Do you mean at 8:03? The idea is, when the equation is balanced, the # of hydrogen atoms are equal. So we write out the equations to reflect that - and we are solving for the coefficients which will allow the number of hydrogens to be the same on both sides.

[@kychemclass5850]

Nive video. I was trying to practice this method on a more substantial equation however... Would love a video on algebraic method for: Urea + sodium carbonate = sodium cyanate + CO2 + NH3 + H2O Urea = (NH2)2CO sodium carboante = Na2CO3 sodium cyanate = NaNCO The equation isn't hard to balance by inspection, but I made a mess of it using the algebraic method. :( and I ran out of steam :(

[@brainwasher5106]

Wouldn't the equation be: CH4N2O + Na2CO3 + H2O --> NaOCN + CO2 + NH4 or Urea + sodium carbonate + water --> sodium cyanate + carbon dioxide + ammonium

[@Dagim1215]

You are a good referer thanks

[@christiansmakingmusic777]

Hi Socratica, what piece of music is being played in the background? We would like to use it as a piano lesson. Thanks for the great video, it totally helped us in balancing equations. Keep up the great work!

[@Socratica]

Isn't it so beautiful! It's the second Allegretto waltz by Alexander Griboyedov (or Griboedov). Here's a recording: kzbin.info/www/bejne/imGbfpWofsSsmsk Thank you for watching!! 💜🦉

[@edwina_wiina]

Thank you so much!!!!

[@dollysheth4676]

can u tell me how to solve this algebraically nacl+mno2+h2so4 giving you nahso4+mnso4+h2o+cl2

[@mehmetedex]

Formula is not correct

[@RovenNogas]

I learn this video to how to solve algebra problem and its help to our student... -Anjellyn Nogas

[@physicssimplified1769]

Yes,I mean at 8:03 but how is 3a = 2d,H3=H2 how is this possible I cannot understand.?

[@Socratica]

Raj Singh Ah, I see! What we know is that *when* the equation is balanced properly, the number of H atoms will be the same on both sides of the equation. To find the number of H atoms on the left, it will be some coefficient (we'll call it a) in front of NH3, and you multiply that by 3 (from the H3) to get the total number of H atoms on the left. Imagine, when it is balanced, that it turns out the coefficient is 2. Then 2NH3 means there would be a total of 6H atoms. In other words, 3a (3times 2) = 6. You do the same thing for the right side of the equation. There are Hs in H2O. We don't know what the coefficient is in the final balanced equation, so it is an unknown, a variable. Let's call that variable d. To find the total number of H atoms on the right, multiply that coefficient by the number of H atoms (there are 2 H atoms in H2O). So on the right, the total number of H atoms will be 2d. As we said before, when the chemical equation is properly balanced, the number of H atoms will be the same on the left and the right, so that's how we get 3a = 2d. We continue to do this for all the atoms in the chemical equation (so do the same thing for N and O) and then you have a set of equations where you can solve for the unknowns a,b,c, and d. Good luck! And thanks for watching! :)

[@physicssimplified1769]

Thanks now I understood....very good

[@anushkaroy6666]

how do we know which compound's coefficient has to be taken as 1??

[@vinaykumarsonti3186]

please upload the videos about chemical bonding..☺

[@Socratica]

+Vinay Kumar Sonti do you mean Ionic Bonds, Covalent Bonds, and Metallic Bonds? Please check the playlist - they are up already! Thank you for watching! :)

[@techworm3609]

I really liked the video how can I support your channel

[@Socratica]

That is so kind of you, TechWorm360, thank you for asking! The most important thing our viewers can do is share our videos with everyone they know! Post them on Twitter/ Reddit, etc. That will really help us find our audience. If you'd like to make a donation to help fund our videos, you can become our Patron on Patreon here: www.patreon.com/socratica We​ ​also​ ​welcome​ ​Bitcoin​ ​donations!​ ​​ ​Our​ ​Bitcoin​ ​address​ ​is: 1EttYyGwJmpy9bLY2UcmEqMJuBfaZ1HdG9 Thank​ ​you!!

[@foodieg990]

Thank you so much very helpful

[@Socratica]

We're so glad to hear you found our video helpful!! Thanks for watching! :D

[@stayclashy3433]

This video proved to be very helpul...how can i support you?

[@Socratica]

You are so kind, thank you for considering supporting our work! We do have a Patreon: www.patreon.com/socratica If you would prefer to make a one-time donation, you can also use Socratica Paypal: www.paypal.me/socratica Thank you for letting us know you found our video helpful. It really does inspire us to make more videos! 💜🦉

[@eurekanunez2376]

Love u guys

[@dipendrakumar8506]

Thanks

[@brianm22]

For the steps used to solve example 3 you have 3 equation with 4 unknowns. This would mean that you cannot solve the system of equations. I see that the way you got around this is explicity defining one of the unkonws as "a=1". My question is how did you know to put "a=1" and not something like "d=1"? is this convetion to define the non oxygen coefficent as 1.

[@manissharajeindran430]

Y do you set y as 1

[@mesalekassahun339]

It's nice thanks

[@pandurangilager2521]

Nice

[@Yogesh-kr7bo]

tnq so much

[@KenMyles-xt2yw]

The background music is not necessary. It actually interferes with the instruction. The instruction is needed, but the music is not.

[@topperssecretsolution6719]

How to solve CH4+O2/C+CO+H2O

[@dandelion2414]

I can not understand how to make an Equations in NaOH+H2SO4=Na2SO4+H2O

[@bertukan3motuma912]

Why is y=1?

[@KenMyles-xt2yw]

Thank you for ending the music.

[@jayashreeparthasarathy5149]

Thanks a lot mam. I'll hit a bull's eye in my exam

[@machovalkarie7896]

a lot faster than trial and error

[@Spo_ng]

honestly finding out this method makes me feel like im cheating 😂😂😂

[@Socratica]

For real!! Once we learned this technique it's hard to go back to the random hunt and guess mode. 💜🦉

[@ernestopanza4194]

God bless you my sweet angel.

[@jutoputo]

Yeah... but how do I know that something equals 1?

[@Socratica]

This is a good question, and something that people often miss the first time they try this method. The idea is, you are SETTING one of the values to 1. IF it is one, then what will the other values be? You solve for all the others. It's a way to simplify the math right from the start. You could just as easily set that value to 5, or 10, or some other number, but then you'd wind up having to simplify it later. You can give it a try!

[@jutoputo]

@@Socratica Thank you!

[@genesis4686]

Wow

[@mesnekohuledawit2546]

thank you so much really nice method

[@kunslipper]

Thank you so much.

[@paxsinica5202]

thank you so much!

[@Socratica]

You are so welcome! We're so glad we could help! :D