Automation Testing Mock Interview | Only Java Questions from Experienced Candidates

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SoftwaretestingbyMKT

SoftwaretestingbyMKT

Күн бұрын

Пікірлер: 11
@mayurjain7478
@mayurjain7478 Ай бұрын
Awesome Interview.
@SoftwaretestingbyMKT
@SoftwaretestingbyMKT Ай бұрын
Thankyou
@Shyam_1567
@Shyam_1567 Ай бұрын
​@@SoftwaretestingbyMKTinterviewer says to me at the end of my interview Good I will share your details with hr This means?
@dpm8799
@dpm8799 Ай бұрын
Good
@rahulj080
@rahulj080 Ай бұрын
1,2yr exp in manual testing, what should learn more to switch in New company ? Plss tell me.
@ChetanPatil-pf8xt
@ChetanPatil-pf8xt Ай бұрын
Nice mock
@Shyam_1567
@Shyam_1567 Ай бұрын
interviewer says to me at the end of my interview Good I will share your details with hr This means?
@slowmotivationforall
@slowmotivationforall 11 күн бұрын
you are selected in that round which this interviewer took and HR will take a final round of yours
@PuspalataMohanty0987
@PuspalataMohanty0987 Ай бұрын
Sir please take my mock interview and i am a fresher. Please sir
@ceotharun825
@ceotharun825 Ай бұрын
Bro take me mock interview I am fresher...
@slowmotivationforall
@slowmotivationforall 11 күн бұрын
import java.util.ArrayList; import java.util.Collections; import java.util.List; public class Anagram { public static void main(String[] args) { String str1="323"; String str2="233"; boolean flag=anagramString(str1,str2); if(flag) { System.out.println("Strings are anagram"); } else { System.out.println("Strings are not anagram"); } } public static boolean anagramString(String str1,String str2) { if(str1.length()!=str2.length()) { return false; } else { List listForStr1=new ArrayList(); List listForStr2=new ArrayList(); for(char c:str1.toLowerCase().toCharArray()) { listForStr1.add(c); } for(char c:str2.toLowerCase().toCharArray()) { listForStr2.add(c); } // Can use any of the below sort i,e either coleections class sort() or list interface sort(null) // Collections.sort(listForStr1); // Collections.sort(listForStr2); listForStr1.sort(null); listForStr2.sort(null); return listForStr1.equals(listForStr2); } }
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