Solving Aerodynamics Problems on NACA 23012 Airfoil using Mean Camber Line

[@Rafale-fr1xy]

hey why do x = c/2 ( 1 - cos theta) is it admitted ?

[@RickyTVyoutube]

I do not understand how you find 0.9335 rad. Can you explain?

[@simater.academy]

sure, first are you subscribed my channel. thank you for asking To transform from x to θ in the expression 0 ≤ x/c ≤ 0.2025, where x = c/2 * (1 - cos(θ)), or x/c = 1/2*(1 - cos(θ)), then subsitiute in first expersion, means that 0 ≤ 1/2*(1 - cos(θ)) ≤ (this value limit 0.2025 means): 1/2*(1 - cos(θ))=x/c = (this value limit 0.2025) = 0.2025 => (1/2*(1 - cos(θ)) = 0.2025 0 ≤ (x/c=1/2*(1 - cos(θ))) ≤ ((1/2*(1 - cos(θ)) = 0.2025)) now let us find θ (degree), from above equation 0 ≤ (θ = (cos-1 (1 - 2x/c)) ≤ cos-1 (1 - 2 * 0.2025) 0 ≤ θ ≤ cos-1 (0.595) 0 ≤ θ ≤53.487368 degree, convert to radian 0 ≤ θ ≤53.487368 *pi/180 =====> 0 ≤ θ ≤ 0.9335306 please subscribe more videos

[@piyushsuryawanshi7679]

hello, when you solve an numerical please explain it with step by step with explanation. otherwise it is of no use.