Solving equations with lambert w function

[@MsHojat]

There's no explanation as to why the given solution is helpful/useful for anything though.

[@NitroKitKat]

Welcome to math

[@MarkGlowInTheDark]

I don't have a clue what that whole explanation is. What i do know is: 2X+X=3X. So 4:3=1.666667 so X is 1.66667 in my head

[@Ykulvaarlck]

since when is 2^x equal to 2*x

[@awaken6094]

2^x is not 2x

[@NitroKitKat]

ok so fyi : 2 to the power of x isnt the same as 2 times x , if i say 2 to the power of 3 is 8 , 2*3 is 6... so its not what u think it is

[@MarkGlowInTheDark]

@@Ykulvaarlck well i am not a mathematical person and have a ton of trouble with formulas. So to keep it simple i was wrong

[@MarkGlowInTheDark]

@@NitroKitKat thanks for explaining, sounds logical. I never liked mathematics xD. That makes this sum even way more difficult

[@darcash1738]

It seems like the exponent needs to match the added x term to work out. I made a gen solution doing the same process. AB^(Cx^n) + Cx^n = D x^n = [-W(AB^D * lnB)/lnB + D] / C If there’s a way to do it where they don’t need to match as Cx^n, what is it?