Solving In Phasor - Part 1

[@thy7917]

for those need the calculation 5:45 : J^2 = -1 , 1/J = -J , -1/J = J -50J / 5 - 10j >> multiply by conjugate of (5+10J) / (5 + 10J) >> you should get (-250J -500J^2)/(25+50J-50J-100J^2) >>>> now apply J^2 = -1, you should get 4 - 2J as rectangular form... then convert them to polar form r = sqrt(x^2 + y^2) >>>>>>> final answer is 4.47 ..(-26.6*).

[@robert_redd1528]

bruh thank you, i was about to go and review this

[@TheTractorGuru]

You make this very clear! Helped me understand this months ago in my intro to circuits class, and helping me again now that I am tutoring the class.

[@juanvera94]

can you tell me how you are doing the calculations purely on the calculator? (what mode is it degrees, radians, any other calc settings that must be changed. also can you write out what you are typing on the calculator if you don't mind, please and thanks!)

[@seunanekhosiking3627]

juanvera94 complex mode dear

[@bajza6046]

to get the angle, you multiply the value by 180/pi to get from radians to degrees

[@ghitaghits1451]

@@bajza6046 you saved me !!

[@VndNvwYvvSvv]

This depends on the calcualor. Some will automatically interpret. Some will let you use rectangular and polar together. Others won't.

[@fredrickmukosha7818]

How did you come up with the angle -26.6

[@leangloav1300]

thanks you so much!!!

[@kaursingh637]

excellent -excellent -excellent - my lord -please solve by transfer impedence method also --please make lecture of 10 minutes i.e short time

[@ozanbenli8585]

you are the best sir , thanks

[@vadimkoller6232]

Sir, u are my hero :)

[@mokhlesturkman8825]

Keep going dr , u r awesome

[@phatnguyenable]

it is helpful but you should do all by hand not by calculator

[@mahmudalamnau6615]

Fabulous!

[@alexmartos9100]

I’m getting stuck on the phasor math. Do you convert to from rectangular to polar if you want to do the division by hand?

[@VndNvwYvvSvv]

If I recall, one form is easier for adding, the other for multiplication.

[@ruikangliu4802]

4.47 (-26.6) and 2+2i are parallel, so the total resistance should be 4.47 (-26.6) *(2+2i)/(4.47 (-26.6)+(2+2i))

[@kubilaykaand]

he totally forgot that, thanks god those are the basic consepts so we can still catch up the missing calls

[@MrSoccerPlayer7]

You don't need total resistance when using current division.

[@instaminox]

In engineering we are not alowed to use these calculators

[@fredrickmukosha7818]

Why negative -10j. Why the negative?

[@johnmichaelcadornigara6465]

how is the capacitor is negative?

[@hillarybett8644]

by the formula -j/(wc)

[@serikiyinka7906]

God bless you.

[@rickjljr11]

How about a 4th answer? needs to download open source Octave (~= MATLAB) >> Is = 4*cos(20/180*pi)+4*sin(20/180*pi)*i Is = 3.7588 + 1.3681i >> Zp1 = -5*i/(100*0.001)/( 5-i/(100*0.001) ) Zp1 = 4 - 2i >> Zs=2+0.02*100*i Zs = 2 + 2i >> I = Is*Zp1/(Zp1+Zs) I = 2.96187 - 0.34087i Why memorize this equation? Why not just use Ohms law? >> Imag = abs(I) Imag = 2.9814 >> Iang = angle(I)*180/pi Iang = -6.5651

[@sabatage13]

Correct me if Im wrong but when I did it I got: 2.47

[@its_dropdead]

I got the same answers that he got .

[@nibzlegend99]

Decent calculator lol

[@esa2236]

22:04 what happened to the 'j' after you multiplied 10j to 1.153?????????????????????????????????????

[@emstv463]

Its converted into polar

[@emstv463]

It is converted rectangular to polar

[@taiwanSmart]

what a calc!

[@donhjoe2162]

When I try to calculate this on the calculator it gives me an error

[@tenton2000k]

Can you do the calculations without a calculator...come on

[@fire619]

is there a part 2

[@AbdulAzizAlSiyabi]

where is Part 2?

[@moazelsawaf2000]

Thank you so much sir

[@GERBINO01]

zahi how why didnt combine the all the load to become 1 load

[@CFneo98]

it’s the current divider formula

[@suatbayrak2703]

for those who are asking how to do without calculator, answer is you cant. when it comes to how to do it with calculator, first you gotta calculate -j50/5-j10 by hand you can do it, its 4-j2. For making it phasor you open a root (4^2 + 2^2) and for the angle you use tan-1 (reverse tangent) function on your calculator and type tan-1 (-2/4) = -26.56 degree. but the prof rolled it into -26.6 for more nice value.

[@WAziz5]

how did tan-1(-2/4) = -26.56???? isn't it -.463??

[@andreahudson3496]

Isn't the current divider formula i(source) * (i(total) / i(target))?

[@hillarybett8644]

NO, it is (source current)*(offset resistor)*(total resistance)

[@uttamgupta1637]

You don't know this topic Please first get clear of it