I will support by letting all students in my pre-calculus class know about you and ask them to subscribe if they will; also when possible I will contribute financially by joining Patreon. Thanks for all you do.
@mushipoo10 жыл бұрын
you're awesome! Thank you!
@lZYAN10 жыл бұрын
would there be a solution in the 3rd quadrant because a negative / negative = positive?
@agent47581610 жыл бұрын
Yea, but you can't go to the 3rd quadrent becase it's only from [0, pi]
@cristhiancanelo57639 жыл бұрын
how did you know so easily that cos(y) over sen(y) were equal to square root of 3? it's kind of tricky
@MrLuckychi11 жыл бұрын
First to comment? Great video by the way.
@ethanchou49066 жыл бұрын
"harder exampe"
@dima7138710 жыл бұрын
I thing this problem is quite tricky. What i got is Pi/3 as the only solution. I believe you forgot that you are solving for half angle y=x/2. Solution for y will be pi/6 but for y/2 it will be 2pi/6 or pi/3. I find it easier to make a table of all possible solution and then plug n=0,1,2...in.