Some Basic Concept of Chemistry 09 | Practice Problems on Stoichiometry | Class 11 | JEE | NEET |

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Watch Ad Free Videos ( Completely FREE ) on Physicswallah App(bit.ly/2SHIPW6). Download the App from Google Play Store. Download Lecture Notes From Physicswallah App(bit.ly/2SHIPW6) Notes Available at Home Page of the App(Home--Pace) PACE - Class 11th : Scheduled Syllabus released describing :- which topics will be taught for how many days. Available at PhysicsWallah App :bit.ly/2SHIPW6 Duration:-3months (Nov 2020 - Feb 2021) Free Batch Exclusive on our KZbin Channel:PhysicsWallah-Alakh Pandey Batch Details 1)Best Faculties across India for different Subject/Topics. 2)Complete & Relevant Syllabus Coverage of Class-11th within 3 Months- Fastrack Nov 20,2020-Feb 20,2021 3)Monday-Sunday : scheduled Classes everyday ( for each Physics, Chemistry,Mthematics & Biology) 4)FREE videos without ad available on app 5)Notes Link on Description Physics:Tues,Wed,Thur,Fri,Sat : 3:00 pm Chemistry: Physical & Inorganic Chem: Mon,Tue,Wed,Thur,Fri:7:00 pm|| Organic Chemistry:Sat,Sun : 9:00 pm Mathematics:Wed,Thur,Fri,Sat,Sun: 5:00 pm Biology:Wed,Thur,Fri,Sat,Sun: 10:00 am 4)Scheduled Syllabus released describing :- which topics will be taught for how many days. Available at PhysicsWallah App :bit.ly/2SHIPW6 Lakshya Batch-Complete Physics for Class 12th BOARDS/JEE MAIN/NEET Yakeen Batch-Complete Fastrack Course(11th & 12th) for NEET Accelerate Batch-Complete Fastrack Course of PCMB for Boards/NEET/JEE Mains Prayas Batch-Complete Fastrack Course of PCM for JEE Mains &JEE Advanced For more Details of the Batches visit PhysicsWallah App(bit.ly/2SHIPW6) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6

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@8:37 minute pe standard volume 22.7 litre Kyu li sir??

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yaar chem ka syllabus kya time pe hojega over

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i cant thank you enough for introducing me to the mole ratio method, since i was in 3rd class, I really had a hard time in the unitary method, formulas made it so much easier for me to get an answer. thank you sooooo sooo much

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did we learn unitary method n all in class 3?? i mean for chem

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Speechless 😶, lots of respect sir, amazing series. Next level concept explaination. I can feel them so well.🙏

[@mahi_mahi578]

10:10 why are we using stp = 22.7 While we commonly use it as STP =22.4

[@premamit04]

We use 22=4 when it is specified in stp that pressure is of 1 atm

[@dilipghoshjal]

22.7 is wrong.

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22.7 litre is modern STP value sis

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Yes you should watch all the lectures

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Sir by seeing this video all my confusion of previous class is over now it is crystal clear

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Sirr teaches so good means mujhe khi bhi smjh nhi aa rha tha Parr apse padh kar sab aa gya🎉Thankuu so much sir for ur efforts❤

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Sir you are great ,I was not able to understand mole to mole analysis but now it is all clear.Thankyou so much

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True

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[@poetrywithak3894]

in the numerical AG2CO3 after complete combustion gives 2Ag and CO2 +O2 in this molar mass of Ag2Co3 will be 278 but u take it 276

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At last he took only 108 for ag but 2 x 108

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Best video for limiting reagent . Thankyou so much sir 💫💫

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Thnku sir For inspiring us by teaching easy concept 🙏

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Bhai samjh me aa jata h kya?

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was that a sarcastic comment

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Sir, your teaching is outstanding. But , I’ll like to correct a silly mistake of you , that you are writing “ l “ as the abbreviation of Litres instead of “ L “ . Again , sir many many thanks for providing such beautiful and top class lectures for us at zero cost.

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he interacts so well as if he is one of our friend! :)

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Well said!!🤪

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Yaa

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At 38:00 why the answer is not 8 gm .By the proprty of law of conservation of. mass it hass to be 8 gm

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India's best teacher of CHEMISTRY ❤️😁

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[@drvinodkhanna3628]

For reaction 4Q +2P------R 16 mol of Q and 8 mol of P of R will produce A)4mol of R B) 2mol of R C) 8 mol of R D) n.o.t

[@drvinodkhanna3628]

4Q/16 = 4 2P /8= 4 Whose limit reactants and whose excess

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Is the answer option A?

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@@drvinodkhanna3628 answer is 4 mol of R. the concept is here both are equation in mole quantity so no one is limiting here. read the defination of limiting reagent

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No doubt left😗, thanks sir

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These questions are relatively easy. Actually, I was facing some problems with difficult past years' questions and was looking for problems solving but ended up getting easier ones again.... Sad life. 😭😢😥

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Bro apki practice apko ......kr wa dey gai sab..... never give up

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Best teacher of chemistry.. Ever sir.. 🙏🙏

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Mai nai kbhi soncha nhi tha ki mai bhi chemistry itnay achay sai smjuuu Thankyou sir❤️❤️

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Sir u had make stochiometry very easy for us. Brilliant sir. I m very lucky to be a part of this platform

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It's awsome trick❤️ Initially, I treat mole concept , a very hard chapter , but now after watching this lesson video , I'm actually feeling that this is the easiest chapter❤️

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Such a great teacher.... . Sir you made my concepts crystal clear

[@adityaop9555]

@8.19 it should be 22.4 not 22.7 becoz 1 mole gas contains 22.4L gas.

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But according to morden stp condition it is 22.7

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I'm waiting for ALAKH PANDEY CONCEPTS OF PHYSICS... 👍🏻👍🏻

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Heya!!

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Sir I think in question 3 mass of silver will be 4.32g instead of 2.16g because 2Ag is released as residue

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Yes I also thought of this

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nope

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Yes even me

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Sare questions bann gyee sir🥰....Thank u sir for the question. It is very much helpful 👏...hats off u for hard work and consistency🙌🤞.....

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Sir, thank you for the practice session.

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Thanks A Lot sir. Unitary method is so difficult. The mole ratio one that you explained is as easy as cutting a slice. THANKSS A lot sir You're the Best. Bless your Heart sir Love from Delhi

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Today's session was very great .. and exited for next one

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Every question has same method,,so plz bring difficult questions,,,to build confidence

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Best teacher i have seen🙂🙂

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Volume of one mole of a gas at stp is 22.4 litre

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Love you sir you are the best and calm teacher who teaches with cool mind I will come meet you sir

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Sir, Please start regular exams(or unit tests) also for Class 11(doesn't matter if we have to pay for that) Please Sir Please 🙏🙏🙏

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Yes sir,we need it

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Best teacher of physical chemistry

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Thank you so much sir from bottom of my heart ❤️ for these wonderful questions with explanation I was struggling in this topic but you made it too easy for us🙏🙏🙏

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Ya to hamara kaam hai baccha❤❤

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Why did sir took 22.7 instead of 22.4 at (8:25

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Sir you're my best teacher forever

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You are very good teacher in physics wallah

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I didn't understood mole mole analysis in the previous lecture but all my doubts are cleared by this lecture Thank you for this amazing practice session sir. 💝😊

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Same with me . Actually in previous lectures sir only teaches us theory but in this lecture we can easily understand by examples.

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Great sir May u live long❤️❤️❤️❤️

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Sir very big fan of yours, sir u are our God. 😍😍

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Astaghfirrullah

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Sir I am capable to do all questions of this chapter.....thank you sir for your rasayan Leela.......

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He is working hard to get u know the concepts which I learnt reading and understanding from the books ..so just pause at the moment u are not understanding and try to .

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Finally i ve understood sir. Thanks for ur great effort. 👏🙏

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Some suggestions junior {myself me student at nit durgapur} *Dont waste too much time on these rapid series *If u have time then first clear ur based practise more and more...if u dont have much time (as in my case) read less and practise more and more but i rwquest you not to spend hours and hours looking for motivation videos,rapid series for practising,...rather practise from ut book fir tryto solve it hard then see the solution...... There are thousands of resources available dont go around looking at all of them ....Alakh sir has been a god i followed all his theory classes for chemistry and physics they were brilliant....

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Wow. I don’t think so I will struggle in this concept

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The best questions and best teacher for practice

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Esa lg rha tha jese koi news suna rha ho 😅 Btw: nice explanation sir ❤️

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Every video will be best if Every lecture is explained By Pandey sir... no hates to any other teacher

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sir chemistry easy kar di aapne thank you sir😍😍

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Salute to you sir Really love your way of teaching 🙂

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Sir you are legend in chemistry

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Great sir May he live long ❤️❤️

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Sir aap boht aacha padhate ho

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Thank you so much for your brief explanation sir

[@jyotikondel1176]

Sir in 16:05 mass had came 2.16g So we need not to consist 2Ag molecular mass only the element not the atoms present cause no of moles consist 2 of Ag but for molecular mass we need not to???😀

[@prt4691]

Dekho moles the 0.02 of Ag Waha mass = 2.16 gm aaya na sir ka Woh taken mass hai na ki molecular mass Yaaani reaction mein kitna mass of Ag liya gaya hai 👍

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Sir but only one thing is that please sir speed up 10 days have passed we have not finished this chapter please sir .I know sir you can

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Best teacher and good explaination

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East and West Amit sir us best

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Sir me aapke charan chukar unko sparsh krna chahta hu. Thank you very much sir for the videos .thankyou so much sir

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Thank you so much sir.....! i was able to do all the problems. Its because of you sir....again thanks a lot sir.!

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You have gone a great job sir Your method is easy for us 👍

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WHAT A MUSIC🎶 DAY BY DAY 🙏👍😇

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Thanks you sir you made stoichiometry so easy to understand.

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Samaj aaaa gaya sir good job sir👍👍💐💐

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I was able to solve almost all problems but i had some problem in balancing . I.e need of best method of balancing , please upload🤗

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ABCD method pado ALAKH sir ki video hai ...fir balancing halwa ho jaayegi...😌😌😌

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best lecture on this topic ever

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Bhai ye channel bhagwan hai iit jee aur neet aspirants le liye❤️