Special Programs in C − Binary to Decimal Conversion

[@sunnygomes608]

Best channel for computer science students so far. Thanks for making such great contents.

[@boblopez7649]

I did this program using shift left operator(

[@mayankjadhav4509]

Thank you so much sir...today i understood the program and Sir please post binary to octal and hexadecimal too...

[@Obama6464]

Great lecture. Many ways this can be done (including using the math.h library and utilizing the pow() function) but the previous person that taught me this didn't explain why we were doing the modulus and division in a clear way. You, however, did. Thanks!

[@-HarishkumarG]

Idk how am I going to survive in IT field 😭

[@ibtissamelhammoumy9586]

don't worry

[@-HarishkumarG]

@@ibtissamelhammoumy9586 thanks :-)

[@AshutoshKumar-jj6kz]

same here no logic only magic in programming

[@nileshtayade3546]

Don't worry bro me bhi apke jaisa hi sochta tha lekin dhire dhire Sab samaj ate jata hai bas koshish karte rho

[@AlameenAdeyemi]

It's 2024,how are u doing now bro

[@ramdayalkumawat2568]

Sir this is so wonderful lecture

[@madhavikatta7346]

Thank you so much Sir one day I will be in the good position definitely on that day I will sponsor huge amount money to our channel

[@ashokkumark2243]

We store hex value starts with 0x, and octal starts with 0 and decimal as it is in the integer type.. How do we store a binary number in the integer type?? Here why do we convert a decimal number to decimal again?? Where actually is it useful?? Can someone please explain??

[@AidenSalts]

what?

[@mdabubakar6874]

have u read digital electronics???

[@roshnimishra3454]

nice one made the concept very clear very helpful

[@dambro3312]

i did it using biwise operators! it worked! ig int bin_dec() { int bin,dec; scanf("%d",&bin); for (int shift; bin!=0; shift++) { int r = bin%10; dec = (r

[@rudrachakraborty7896]

Thank you, sir. This really helped me with my paper 1 programming practice. From London

[@nikhilsingh7666]

nice lecture I got a hint for the CodeChef challenge thanks

[@arnoldgatchalian8643]

Thank you I've learned a lot from you

[@Deepthi_Chowdary5321]

Sir u make more series on only focusing on problem..

[@YashDEVELOPER12]

Very beautiful explanation sir.. u r amazing 🙏

[@HuynhThanhThuan]

Very easy to understanding, thank you dear Sir.

[@vinaykamble162]

It's amazing explanation ❤️

[@shreya9275]

Absolutely Brilliant explanation

[@beauty-ez8ox]

Wow 💜💜💜 ... So nicely explained

[@kapiljetwani3540]

thank u for such a nice explaination!

[@avishekkbhatta]

best channel.................................................

[@shikhajamwal4709]

u have explained it very well

[@tumutarun5157]

Upload all videos in c language for learners

[@mdmuquimakhter5145]

awesomely explained

[@sahilarora7186]

very nice explanation thank you sir

[@itsbayahmed]

Here is another solution to this problem: #include #include int main() { long long int number, num, result, n; printf("Please Enter the Binary number: "); scanf("%lld",&number); result = 0; n =0; num = number; while(num != 0) { result = result + (num % 10) * pow(2,n) ; n++; num = num / 10; } printf("%lld in decimal is %lld", number, result); return (0); }

[@nishabhandari5190]

Thank you so much professor

[@gayathripvl8184]

sir you are doing very great job

[@gopichowdary2040]

Sir please upload daily one video like circuit theory videos are being uploaded

[@Hichamb04]

thanks bro that was so helpful .

[@aakashmudigonda3375]

if anyone of you guys, didn't understand the above code, this my own code, which I made from a simpler logic.... #include #include int main(void) { // example : convert 1 0 0 1 to decimal // [1]*2^(3)+ [0]*2^(2)+ [0]*2^(1) + [1]*2^(0) printf("enter a binary number : "); int n; scanf("%d",&n); int temp = n; int rem = 0; int result = 0; int count = 0; int last_num= 0; while (temp!=0) { temp = temp/10; count++; } temp = n; for (int i = 0; i

[@namraarif100]

Very helpful video sir But you did not initialize rem in start. Will it not a problem to run this program?

[@manojraut9630]

You are Best.👏

[@andistheinforitbutso7513]

All hail 🙌 Neso Academy

[@HelderKJPedro]

Thank you so much 🙏🏽

[@5303sandeep]

Here is the code for invalid input for eg:- 1201(which is not binary) #include int main() { //Initialization and user input int b,rem,decimal = 0,w = 1,num,c=0;//w = weight,b = binary printf("Enter binary number to covert to decimal "); scanf("%d",&b); num = b; //Binary to Decimal Conversion while(num!=0) { rem = num%10; if(rem>1) { printf("Invalid input:Input contains number other than 0 and 1 Please enter a valid input "); c = 1; break; } else { decimal = decimal + rem*w; num = num/10; w = w*2; } } //Printing result if(c==0) printf("%d is the decimal conversion of binary %d",decimal,b); }

[@tusharmathur5360]

thanks bro for sharing

[@komkirisma3347]

how to do it for decimal?

[@basics698]

Please make videos on control systems.

[@Khadra2024]

if i want to check if the number have only 1 and 0 how can i do that? if it has other number, send error message :(

[@mdathar1947]

Sir pls cover the corners case also...

[@mdathar1947]

If I enter a binary contain more than 10 digit ....2. if I enter for eq-101101010101 Will your program work in these 2cases??

[@zoreladreanrivera9822]

#include #include int main ( void ) { int binary; printf ( "Enter binary number: " ); scanf ( "%d", &binary ); int counter1 = 0; int A = binary; while ( A != 0 ) { A /= 10; counter1++; } int remainder = 0; int power = 0; int sum = 0; for ( int counter2 = 0; counter2 < counter1; counter2++ ) { remainder = binary % 10; power = ( pow ( ( remainder * 2 ), counter2 ) ) * remainder ; sum += power; binary /= 10; } printf ( "Decimal Equivalent = %d", sum ); return 0; }

[@bkrulz1280]

How to write it in a recursive function

[@ColorsOfLife114]

As the weight of first digit from right side is zero then why we take it 1???

[@dheerajk7]

Thankyou so much sir

[@jagugamit150]

I am getting error Input :- 0011 Output :- 9 Expected output should : - 3

[@sowmyapg3381]

Understood thankyou

[@ArunChoudhary-lr7rp]

Outstanding

[@ic4r023]

Very good video. But I replicated the exact same code in Dart (doing the syntax changes) and the result was different! It gave me 11.24999999. There is my code in Dart: num binary = 1001; num decimal = 0; var base = 1; void main (){ while(binary != 0){ var rem = binary % 10; decimal = decimal + rem*base; binary = binary / 10; base = base*2; } print(decimal); } Can someone please explain to me where I'm wrong?

[@tusharmathur5360]

seems nothing wrong

[@ramanandasharma9214]

please give the flowchart and algorithm for this

[@sinchana9358]

Plzz make a vedio on how to convert decimal to binary plzz sir🙏🙏

[@archipalexandru-ioan5898]

#include int main() { int var=65; int i; int bit; for(i=8;i>0;i--) { bit=(var>>i-1) &1; printf("%d",bit); } }

[@archipalexandru-ioan5898]

here you have,65 is the number converted to binary,the for its from 8 to 1,so you can store the bits from left to right

[@songoku2013]

But what if the input is '101.011' or any other fractional binary number ? How to program that ?

[@TheJoker-xw5pd]

Bro agar hum koi or number add kare like as jo binary me na ho to code invalid ana chaiye to kaise hoga

[@Ginihiniikk986]

what is weight??

[@rameshv2762]

It's a decimal value of number at certain position in a binary number.. Wn you travel from Lsb to msb... The value changes frm 2 to 2^n ..🙂

[@gamingcousinstamil]

Super sir

[@poojajagtap6356]

thanks sir

[@nazmashaik2558]

Sir I execute this program but the out put is not correct there is so different.what can I do

[@AdityaGupta-pl1ss]

What is the meaning of Weight here

[@ashishsinha8893]

Sir u r going to upload videos in daily basis or not ???????

[@muhammedshafeek3905]

In code blocks if I use space in print"%d " after %d before " once I build the code code block become stuck how I solve this

[@jagadeeshwaran1512]

I just added a feature to this program, i.e., to display a error message when a non binary number is entered.

[@subhadeepsinha1006]

how r you pirate king??

[@minku2108]

Program for binary to hexa?

[@true4189]

Thank u

[@mousex5532]

thankyou

[@amudhapi6492]

Why weight=1 and what r the purpose for use weight plz reply me

[@arunjithajith7958]

Weight is base Initially base value will be 1 so we initialise weight with 1

[@amudhapi6492]

@@arunjithajith7958 Thank u Arunjith

[@muskanustad3834]

What about negative binary numbers🙄?

[@avinashyadav8598]

Program dont work for 0011

[@jagugamit150]

Same bro

[@satyanarayanakoppuravuri161]

if we give binary as 0000 ?

[@krank3869]

it's gonna return 0.

[@hatemali4220]

Enta gamed strong

[@sharuhasans9417]

How 1 divd by 10 remainder will b 1

[@Vinay_Yarramsetty]

10) 1 (0 0 ------------- 1 I think this is the way But not like 1) 10 (10

[@gourabdutta7086]

10*0=0..so remainder will be 1

[@donpilarsuarezgudino5160]

This code don't work in Python... Any help??

[@donpilarsuarezgudino5160]

Problem solved: don`t worry any more folks

[@goldendragon5371]

Binary to octal please bro..... >.

[@Naveen-n3p1i]

Is not working all values🤷‍♂🤷‍♂🤷‍♂🤷‍♂

[@reimannintegrability]

😢

[@harshitha6160]

First view, and first comment

[@Kartik001arts]

Codes don't get executed which you teach in the window.....

[@redricblue8790]

Why did I choose software engineering? It's fucking hard

[@aldolhitlercondensation1363]

Hey I'm sorry you feel this way. This is actually fun if you get the concept, let me try and help. So the decimal number system (the system we naturally use) is very similar to the binary number system. Figuring out this key difference is all the logic you need to write the code. So for instance, to find the value of any decimal number we're actually multiplying each constituent digit with increasing powers of 10 for eg: 139 = 1*10^2 + 3*10^1 + 9*10^0 . It's just that we do this so naturally so that we don't usually give it a second thought. The decimal number system supports the digits [0-9] Comparing this with the very similar BINARY number system which just supports the digits 0 & 1, to get the value of a binary number we're simply multiplying the digit (bit) at each position with increasing powers of 2! for eg: 1011 represents 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 1 * 2^0 i.e the digit 11 in decimal. This is all the software engineering aspect there is. The rest is basically figuring out the fundamentals of any language to execute this. In fact, I would urge that you write your own code once you know this logic without referring the video. All you need to do that is i) knowledge of how to extract bit by bit from a given input ii) how to compute powers iii) how to use loops and conditional statements. Googling each of these gives you a clear idea of what they do. I hope i was able to help

[@Deepthi_Chowdary5321]

Don't worry yar. All will be good.. Better luck