Spherical Tensor Operators | Wigner D-Matrices | Clebsch-Gordan & Wigner-Eckart

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Pretty Much Physics

Pretty Much Physics

Күн бұрын

Пікірлер: 49
@dy1607
@dy1607 4 жыл бұрын
Spent several classes to learn these stuff. Tough thing. A good video to review.
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
Thanks for the nice comment!
@tomsmith6878
@tomsmith6878 4 жыл бұрын
I think this is the first video you guys have done that wasn't covered in my degree (ive watched most of them)… nice work!
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
We encountered them in a QM course, when talking about the Wigner-Eckart theorem. But also really nothing more than „they exist“. So we wanted to find out what spherical tensors are, how to use them and so on.
@tomsmith6878
@tomsmith6878 4 жыл бұрын
@@PrettyMuchPhysics same here, we covered Wigner Eckart without mentioning these
@surbhisinha8959
@surbhisinha8959 4 жыл бұрын
You guys are the best. Thank you 🥺
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
:)))
@luanmartins8068
@luanmartins8068 3 жыл бұрын
although the video is a bit fast, it's very well explained and clarified a lot of things, and also the way the notations were done was splendid!
@PrettyMuchPhysics
@PrettyMuchPhysics 3 жыл бұрын
Thank you very much! :)
@mdshaifullah9598
@mdshaifullah9598 3 жыл бұрын
Awesome channel. I love this channel so far. I would have been better if you made a tensor series for physics students.
@park19970429
@park19970429 3 жыл бұрын
I’m very moved with your kind explanation! Thank you so much!!
@PrettyMuchPhysics
@PrettyMuchPhysics 3 жыл бұрын
Thank you for your nice comment! :)
@ИгорьДымченко-к9л
@ИгорьДымченко-к9л Жыл бұрын
Absolutely Great explanation.
@PrettyMuchPhysics
@PrettyMuchPhysics Жыл бұрын
Thank you very much!
@paintokk799
@paintokk799 Жыл бұрын
Thank you for wonderful explaination! I am wondering how to obtain the tranformation of spherical harmonics under rotations (Y_{lm} --> D_{R}^{\dagger} Y_{lm} D_{R}) at 8:06. There is a bit leap from the previous derivation.
@gerardotoscano8090
@gerardotoscano8090 2 жыл бұрын
Hory shit ma man, this is incredible, ive finally understood QM in an easy and condensed way, i´ve been trying to understend these topics for months and even tho i did in a reasonable amount, now i understand so clear what is going on, Thank you so much, seriously. PD. I hope in the future you get interested in explaining some of the Judd Ofelt theory, specially, the combination of two tensor operators (dipole moment operator and Crystal field operator) into one using the 3j wiegner symbols. But it is just a hope. Anyway, I'll have donate soon cos this is amazing.
@PrettyMuchPhysics
@PrettyMuchPhysics 2 жыл бұрын
Thank you very much for your kind comment! :) TBH, I haven't heard of Judd-Ofelt theory until now, but it looks interesting! By the way, we did two videos on the Wigner-j symbols: kzbin.info/www/bejne/q5moo5J4d8aCkLs and kzbin.info/www/bejne/pIqcYY2hYsSkp6s 🙂
@gerardotoscano8090
@gerardotoscano8090 2 жыл бұрын
@@PrettyMuchPhysics Yeah, thank you very much, im actually watching them right now
@mergen9802
@mergen9802 3 жыл бұрын
7:10 why is it J that enters D=exp(-i θ J)? Does it also include spin degree of freedom?
@PrettyMuchPhysics
@PrettyMuchPhysics 3 жыл бұрын
We used J to denote the generator of rotations in general. If there is no spin in your system, then the generator of rotations is L.
@mergen9802
@mergen9802 3 жыл бұрын
@@PrettyMuchPhysics what if there is a spin d.o.f.? Would it be the total J instead of L? Naively I would assume it's still L since R is a spatial rotation...
@정웅찬-p8s
@정웅찬-p8s 2 жыл бұрын
thanks for making this video! but i have a question 4:25, coefficient of spherical basis. e+ and e- inner product is 0 when alpha=1/2, beta=1/2 why are alpha and beta's sign differently?
@thenaughty5441
@thenaughty5441 2 жыл бұрын
Wow this is so helpful, thankyou !
@PrettyMuchPhysics
@PrettyMuchPhysics 2 жыл бұрын
We're glad it was useful to you! 😃
@DarkRanger882046
@DarkRanger882046 4 жыл бұрын
Thanks. great job.
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
Thank you! 😁
@MastermindofBCB
@MastermindofBCB 4 жыл бұрын
Very nice work! May I ask what Soft-/Hardware you use as a "blackboard". Need to give some online exercises this semester and I'm somehow not very pleased with the stuff we have.
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
Thanks! Software: "Explain Everything", hardware: iPad + Apple Pencil!
@adonaihilario1006
@adonaihilario1006 3 жыл бұрын
Using the relation shown in 13:50 I can write Y_(1,0) = Y_(1,-1) Y_(1,1) ⟨1 -1 1 1 | 1 0⟩ + Y_(1,-1) Y_(1,-1) ⟨1 1 1 -1 | 1 0⟩ but this yields zero, while it should yield Y_(1,0) = sqrt(3/4π) cos(θ). What am I doing wrong here?
@PrettyMuchPhysics
@PrettyMuchPhysics 3 жыл бұрын
The second line with Y_LM etc. should have been under quotation marks or something; it's more symbolical and we should have made this more clear, I'm sorry. Two spherical harmonics contract like this: en.wikipedia.org/wiki/Spherical_harmonics#Contraction_rule and the reason is explained here: physics.stackexchange.com/questions/512197/decomposition-of-spherical-harmonics-via-clebsh-gordan-coefficients
@krishanusengupta7710
@krishanusengupta7710 3 жыл бұрын
Thanks a lot.
@ngankinfung
@ngankinfung 4 жыл бұрын
I think the CGC table is lacking some square root?
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
Yes, exactly! Usually, in order to save space, square roots are omitted from Clebsch-Gordan tables. So if you see a „-1/3“, this actually means „-sqrt(1/3)“!
@ngankinfung
@ngankinfung 4 жыл бұрын
@@PrettyMuchPhysics Great video anyway!
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
Thanks :D
@devangshukla3688
@devangshukla3688 2 жыл бұрын
Pretty nice
@PrettyMuchPhysics
@PrettyMuchPhysics 2 жыл бұрын
Thanks!
@taw3e8
@taw3e8 4 жыл бұрын
well... that's not my level :(
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
Doesn't have to be! Remember, our videos are meant to be a refresher when you study something and don't quite understand it. No need to worry if you don't understand such a topic after the first watch!
@taw3e8
@taw3e8 4 жыл бұрын
@@PrettyMuchPhysics well, i'll have to study it first to be able to refresh it...
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
@@taw3e8 Exactly! And if you do, please come back and rewatch it :D
@taw3e8
@taw3e8 4 жыл бұрын
@@PrettyMuchPhysics i'm sure i'll be back :p
@Ovechkin8484
@Ovechkin8484 4 жыл бұрын
Fuck yeah
@PrettyMuchPhysics
@PrettyMuchPhysics 4 жыл бұрын
:D
@jakubjungle656
@jakubjungle656 3 жыл бұрын
A man in a dream told me that you could use the framework of angular momentum and spherical resonance as a cypher for non-commutative, quasi linear fluid dynamics. The cypher decodes all the way down to a singular non-tensosorial expression which defines itself as "the absolute zero of space-time" . A sub quantum VOID which pulls time in one side and spits out the other like a black hole but with no gravity.
@jakubjungle656
@jakubjungle656 3 жыл бұрын
The time that spits out from this void, is observable and measurable. The quantum foam is the residue of the past, as it passes time along, it blends the consequences of the previous moment and applied them generously to the eventualities and inevitabilities of the future, from one moment onto the next, for ever. Until some military learns how to split it like an atom cuz that would probably kill us all.
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