SSC CGL 2024 |Maths Best Question asked in CHSL 2024 Exam|SSC CHSL 2024 Maths Questions|by Sahil sir

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Quick Tricks By Sahil Sir

Quick Tricks By Sahil Sir

Күн бұрын

SSC CGL 2024 |Maths Best Question asked in CHSL 2024 Exam|SSC CHSL 2024 Maths Questions|by Sahil sir
Welcome to "Quick Tricks by Sahil Sir" - A Satisfactory Solution for all subjects.
This channel boosts your exam preparation for Railways (JE, NTPC, ALP, RPF & Group D), CET New Pattern, SSC CGL (Tier-1 & Tier-2), SSC CPO (SIs in Delhi Police, CAPFs and ASIs in CISF), SSC CHSL (10+2), SSC MTS, SSC Constable GD, BANK (PO/Clerk), UPSC CSAT, State PSC, RAS, CDS, NDA & All State & Central Government Exams & Placement Exams. Prepare for your dream job in the competitive examinations with India's most trusted Educators i.e. SAHIL KHANDELWAL, AKASH CHATURVEDI & HARISH TIWARI.
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Пікірлер: 28
@QuickTricksBySahilSir
@QuickTricksBySahilSir Ай бұрын
Quick Tricks by Sahil Sir - play.google.com/store/apps/details?id=com.quicktricks.sahilsir Maths by Sahil Sir Telegram - t.me/sahilmaths
@shibamsadhukhan121
@shibamsadhukhan121 Ай бұрын
nice session...continue this session till cgl exam...
@SonuMeena-nv9cv
@SonuMeena-nv9cv Ай бұрын
Bhai meri bat hi chiny li
@sagarbhadra9971
@sagarbhadra9971 Ай бұрын
Nice session sir ♥️
@belimitless6225
@belimitless6225 Ай бұрын
Shandar lecture guru ji ...🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
@sscmypride
@sscmypride Ай бұрын
Continue this class
@rajorshiacharjee8325
@rajorshiacharjee8325 Ай бұрын
Very good class Thankyou Sir. 👍👍👍
@sscmypride
@sscmypride Ай бұрын
Thanks sir
@prateekchabbra634
@prateekchabbra634 Ай бұрын
Sir top 20 time and speed ke krvado ssc chsl top vale pls 🙏
@nilabjasaha3255
@nilabjasaha3255 Ай бұрын
Thank u sir a lot
@simpeeprajapati8556
@simpeeprajapati8556 Ай бұрын
Thank u sir ❤🎉
@PriyaJaiswal-lw2ig
@PriyaJaiswal-lw2ig Ай бұрын
Sr session daily le kr ay plz
@amitjangid7170
@amitjangid7170 Ай бұрын
Sir apne ctm se to easy hi h 🎉
@Dangidangi899
@Dangidangi899 Ай бұрын
Sir ji mptet varg 2 k liye bi class L lijiye KZbin pr
@hkgamerz..
@hkgamerz.. Ай бұрын
1st wale me
@sahilkhandelwal8631
@sahilkhandelwal8631 Ай бұрын
Quotient ko divide kro
@Officialgiris
@Officialgiris Ай бұрын
❤❤❤
@hkgamerz..
@hkgamerz.. Ай бұрын
Question ko samjao to sahi apne hisab se bta rahe ho konse number kaha se aaye wo to batao
@hkgamerz..
@hkgamerz.. Ай бұрын
Sir jaldi jaldi kar ke award nahi lena he bachho ko samajna he to samja warna band kar de
@pranaydarhe1473
@pranaydarhe1473 Ай бұрын
Bhai mat dekh
@AYUSHVERMA-el1sh
@AYUSHVERMA-el1sh Ай бұрын
Sir question no.10 m 5 se divide krne pr reminder 1 nhi aa rha h
@fun_mania007
@fun_mania007 Ай бұрын
Find the number when successively divided by 3,5 and 7 leaves remainder 2,1 and 3 respectively, and the last quotient is 3.
@fun_mania007
@fun_mania007 Ай бұрын
Sir chatgpt answered =To find the number, we need to work backwards using the given information about the remainders and the last quotient. Given: - When the number is divided by 7, the remainder is 3 and the quotient is \( q_3 \). - When the quotient \( q_3 \) is divided by 5, the remainder is 1 and the quotient is \( q_2 \). - When the quotient \( q_2 \) is divided by 3, the remainder is 2 and the quotient is 3. Let's denote the original number by \( N \). 1. **Start with the last quotient:** \[ q_1 = 3 \] 2. **Use \( q_1 \) to find \( q_2 \):** \[ q_2 = 3 \times 3 + 2 = 9 + 2 = 11 \] 3. **Use \( q_2 \) to find \( q_3 \):** \[ q_3 = 5 \times 11 + 1 = 55 + 1 = 56 \] 4. **Use \( q_3 \) to find \( N \):** \[ N = 7 \times 56 + 3 = 392 + 3 = 395 \] So, the number is \( 395 \).
@fun_mania007
@fun_mania007 Ай бұрын
But the answer is wrong and when i correct the question as by adding only to the question as Find the number when successively divided by 3,5 and 7 leaves remainder 2,1 and 3 respectively, and only the last quotient is 3.
@fun_mania007
@fun_mania007 Ай бұрын
It replies the correct answer
@fun_mania007
@fun_mania007 Ай бұрын
Let's carefully solve this problem step-by-step. Given: - When the number is divided by 3, the remainder is 2. - When the resulting quotient is divided by 5, the remainder is 1. - When the resulting quotient is divided by 7, the remainder is 3. - The last quotient is 3. Let's denote the original number by \( N \). 1. **Let the last quotient be 3:** \[ q_3 = 3 \] 2. **When this quotient is divided by 7, it leaves a remainder of 3:** \[ q_2 = 7 \times q_3 + 3 \] \[ q_2 = 7 \times 3 + 3 = 21 + 3 = 24 \] 3. **When this quotient is divided by 5, it leaves a remainder of 1:** \[ q_1 = 5 \times q_2 + 1 \] \[ q_1 = 5 \times 24 + 1 = 120 + 1 = 121 \] 4. **When this quotient is divided by 3, it leaves a remainder of 2:** \[ N = 3 \times q_1 + 2 \] \[ N = 3 \times 121 + 2 = 363 + 2 = 365 \] So, the number is \( 365 \).
@cookingg13
@cookingg13 11 күн бұрын
Way of teaching is not good
@Xyzuphomo-di4jt
@Xyzuphomo-di4jt Ай бұрын
Last question mere shift me aya tha 😢
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