SSC JE 2023 | Engineering Mechanics | SSC JE Previous Year Question Paper | Mechanical Engineering

[@EngineersWallah]

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[@mohdimran91]

Coplaner concurrent two equations .:..TWO equations options c Non coplaner and concurrent ke liye 3 equations B option

[@akashpatil4992]

yes particle doesnt not have any moment eqns

[@KJKalita]

Le master ji- moment aata hi nahi...are moment aata hi nahi😂😂😂😂😂 are bhai reason doo...galat chij samja rahe ho😂

[@shubhammukherjee2280]

3rd question ka ans b) hoga i think

[@mohdimran91]

Because force system is non coplaner so why B option

[@shubhammukherjee2280]

@@mohdimran91 fir coplanar concurrent me kya hoga.

[@mohdimran91]

Two equations sum of all force equal to zero

[@akashpatil4992]

@@mohdimran91that is for coplanar only two directions on a plane and 3 directions for non coplanar so correct ans is B

[@akashpatil4992]

@@mohdimran91 "For a particle to be in translational equilibrium, the vector sum of all external forces acting on the particle must be equal to zero. This is expressed using the equation: ΣF = 0 Where: ΣF represents the vector sum of all external forces. The "Σ" symbol denotes summation over all forces. "0" indicates that the net force is zero. Mathematically, you can represent this condition as the equilibrium equation for forces in the x, y, and z directions (assuming a 3D space): ΣFx = 0 ΣFy = 0 ΣFz = 0"

[@railttechnology]

Best teacher

[@End_status_11]

Yes sir

[@mohdarshad1610]

SSC (JE) Paper me calculator allow hota hai ki nahi please reply??

[@unknownbhai4308]

No

[@amannegi8522]

10saal.likh ke 2017 ka karwaya bas