ST14: Identifying Zero-Force Members in Trusses

[@johndelapaz2701]

THE CLEAREST EXPLANATION I'VE WATCHED SO FAR!!! THANK YOU SO MUCH!!!

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One of the best leacture I have been encountered so far.

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Dr. Structure’s explanation always the best

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The best subcription that I have ever signed up for. I should've found this yrs ago. Thank you and thank you for your time and efforts for sharing your knowledge 🙇🏾‍♂️🙏🏾

[@oumaevans]

Your lesson is precise and concise. I appreciate all your efforts. Please keep up. Thanks.

[@enggismailali1700]

Thank you so much for your help. It's a very pleasure to me to see this channel which is now I think gonna help me in the structure analysis

[@utku3463]

Really thanks. Your technique is much simpler and understandable than other videos. Video helped me alot Thanks

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Very fast learning from ur videos Really helpful me way .

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Simple but effective lecture. Nice.

[@monuharendra]

U are awesome , the concept is marvelous.

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Great explanation

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you have singlehandedly saved my degree

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always Dr. Structure, he never disappoints

[@denisemdevlin]

This lecture was awesome. Thank you.

[@arunndinesh]

Perfect and simple lecture. Thanks

[@satishshrestha3563]

Thank you for your helpful video... please make a video for displacement analysis....

[@srihithakasturiA]

Thanks a lot Dr.structure u made it interesting 😍😍

[@shortsking-e6u]

Answers for the question asked at last are 1) 4 2) 0 3) 6 4) 2

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Thanks for your helpful videos.

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I watched like 20 videos on this crap and the only one I actually understood was this one. Thank you spooky AI lady.

[@maryeaarch]

thank youuuuu this is a really amazing explanation

[@nawabmohammadi9232]

thanks for you nice efforts.

[@venkatesh2285]

what happened to Dr.structure team?? we are awaiting for your videos..

[@DrStructure]

We try to get them out as soon as we can, at least one video lecture per month. But the time-intensive nature of these production may cause delays. Needless to say, the team is working diligently to move the broader project forward, devising, experimenting with and implementing ideas on teaching and learning centered around structural engineering.

[@gixerriders1993]

I want to learn design of truss for industry, workshop, store so how can I identify the size of sections like angle, rectangular hollow tube or circular hollow tube which can bear the coming load can you teach please

[@caesarendyheroedin7381]

More easy thanks

[@siddheshbhalerao3013]

Thanks...what are the solutions for remaining 4 questions ?

[@DrStructure]

The link to the solutions for the exercise problems is given in the video description field.

[@efetevfik2363]

How can I find the answers of last questions?

[@DrStructure]

They will be made available in a few days.

[@DrStructure]

Here is the link to the pdf file containing the solution for the exercise problems: Lab101.Space/pdf/exercises/ST14-Exercises.pdf

[@bilalelachab6270]

You just saved my whole MechEng career 😂😂

[@mizgintusgul8089]

Hi, just wanted to ask if you have more good support resources? I'm struggling right now with all the work and it would help to know please.

[@DrStructure]

@@mizgintusgul8089 You can find all of our existing learning content at our website: Lab101.space

[@mizgintusgul8089]

@@DrStructure thank you very much

[@t.f.r287]

Omg, same here. It is hard to study in a research based university in Malaysia.

[@aungkyawkyawsoe5593]

someone show me How can we find those zero force members in space truss.

[@bhavikbhatt8346]

Why 10:29 this is not zero

[@DrStructure]

Do you mean why GH is not a zero force member? Because there is an applied vertical load acting at H. The sum of that force and the force in member GH is zero (the sum of the forces in the vertical direction must be zero). But since the applied force is not zero, GH cannot be a zero-force member.

[@bhavikbhatt8346]

@@DrStructure no not GH but the corners. The corners should be zero.

[@DrStructure]

Why should they be zero-force members? Please present your line of reasoning (in a step-wise manner) that leads you to believe they are zero-force members.

[@bhavikbhatt8346]

@@DrStructure because there are no loading on the horizontal HK Not on GK so. That's why.

[@DrStructure]

@@bhavikbhatt8346 But there are two member forces in the horizontal direction at either joint H or joint K. One of them is the force in member HK. The sum of the two horizontal forces must be zero. But that does not mean the force in HK is zero. Unless you can prove/show that the other horizontal force (in member FH or in member GK) is zero, we cannot conclude that HK is a zero-force member.

[@vfgrfbgrb]

2.45 how is p zero its not on y axis

[@DrStructure]

True, P is not along the y axis. But, it has a component along the y axis. So, that (y) component of the force must be zero. If the y component of the force is zero, given that force is not along the x axis, then the force itself must be zero.

[@vfgrfbgrb]

@@DrStructure but doesnt p also have a compent in x axis

[@DrStructure]

Yes, it does. But if we show that the y component of the force is zero, then it follows that its x component is also zero. In this case, we know P makes a non-zero angle with the x or y axis. Let's assume that the angle between P and x axis is 25 degrees (you can use any non-zero value here). Then, the x component of P is: P_x = P cos (25). And the y component of the force is: P_y = P sin (25). In this problem, P_y = 0 means P sin(25) = 0. Since sin(25) is not zero, then P must be zero. And since P is zero, then P_x = P cos(25) is also zero.

[@vfgrfbgrb]

@@DrStructuremake a drawing so i can understand

[@vfgrfbgrb]

So q is zero