Stairway to Seven: Thick fog for a Monday!

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Күн бұрын

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@ThePedallingPianist Ай бұрын

Thanks for giving this one a go! It seems your other commenters have shared a few other ways that you could've made slightly easier progress near the beginning - and it's not quite correct to say that an odd digit must be the centre of a palindrome (32323, for example, is palindromic but has odd digits at both ends... the odd digit does have to be in the centre as well though) - but you did well to break through and finished it off very smoothly indeed! The title was actually a bit of a spoiler: the palindrome is a "stairway" shape and had 7 cells :D

@SudokuSleuth Ай бұрын

That was a misstatement if I said that for sure. Only that if it’s odd digits in length the centre digit had to be odd. Had I done a bit of Sudoku this would have been a much shorter video 😉 Fantastic puzzle as usual and really interesting variant. I hope you’re planning on more of it!

@annikaQED Ай бұрын

Now that I've gotten my head around "self-referential" palindromes a bit, I'm looking forward to putting my new-found knowledge to use in similar puzzles. More, please!!

@Eftelingannie Ай бұрын

I solved it somewhat different. When Sudoku Sleuth starts thinking about the palindrome i moved on in box 5. Because of the 3's only could go in r6c1 and r6c3 there is a hidden pair of 2's and 4's in c2. From there on i could fill in all the pairs in boxes 1,3 and 5. After that i did fill in the candidates in boxes 2,4 and 6. After this i started to work out the palindrome. Made it in around 6 minutes.

@titusadduxas Ай бұрын

8:25 - Very nice and surprisingly approachable.

@shiftyhexahedron7891 Ай бұрын

What a smooth 12 minute solve.

@mscha Ай бұрын

9:50: How could you “get away” with an 8-cell counting palindrome with 2 2s and 4 4s? What would the other two digits be?

@SudokuSleuth Ай бұрын

Fair point!

@SudokuSleuth Ай бұрын

Fair point!

@leickrobinson5186 Ай бұрын

Fun puzzle! I can see the possibility for much more challenging puzzles with this rule set. 4:19 for me. 😄

@boydegg Ай бұрын

4:10 great little puzzle

@anaayoung9142 Ай бұрын

The comments helped me on this one!! I forgot about the last rule 😅 Thanks 😊

@niyazali7983 Ай бұрын

3:24 for me. Once I got the break-in it was very smooth-sailing on this one (once I remembered the counting rule at least...🤣)

@Sinisest1121 Ай бұрын

5:33 for me today. **Spoiler Warning** When you get pencilmarked everything in box 3 then you had possibility to see that row 4 in box 4 is 135 and in first cell 3 is not an option there. Can that be 5? No because to construct palindrome where is 5 times 5 we need like something about 15 cells. But we already know that 6 is not on palindrome so maximum what we can make ise 2+4+5 = 11 length palindrome as we are only allowed to use only one odd digit in that counting palindrome. that way i know it is 1 and consecutive rule told me immediatly these cant be 2-s next to it. Then i need something else what must be 2 and two more 4-s to finish their count.

@SudokuSleuth Ай бұрын

Please do add a spoiler alert to the comment and space out the tip please

@annikaQED Ай бұрын

(SPOILER) Considering the possible lengths of the palindrome is key. For example, if the length of the palindrome is 6, then 6 can be expressed as the sum of distinct whole numbers in 4 ways: 6 = 6, 6 = 1+5, 6 = 2+4, 6=1+2+3. But in a palindrome of even length all the addends must be even, so only 6=6 & 6 = 2+4 can work. In a palindrome of odd length, all the addends save one must be even. Thus for example 7 = 1 + 2 + 4 can work. In retrospect, the title is very apt.

@stephenwampler1889 Ай бұрын

Thank you!! This was really helpful, I couldn't follow Sleuth's palindrome logic

@trdi Ай бұрын

14:57 I am not sure that we know R5C3 is 246 just like that. Based on the available info at that point, it could still be an odd digit, the same as R4C4. It requires just one more step to see that it has to be even. I think.

@edenfraser Ай бұрын

3:42 today very exciting!

@karthick_michigooner7431 Ай бұрын

Yay!!! Just noticed i made it to the Outro!!!

@SudokuSleuth Ай бұрын

Thank you for supporting the channel!

@oldguydoesstuff120 Ай бұрын

That counting palindrome is interesting. I got there, but it took me about 20 minutes. Spoilers... ... It didn't take me too long to figure out that you can have only one odd digit on such a palindrome and it must appear in the center. That's the only way to get an odd number of appearances on the line. After the 6 is placed and we clear some fog, the line goes off into what must be an odd digit by sudoku. And it can't be a 3 by the non-consecutive rule. So it's either a 1 in the center or there must be 5 5s on the line. To do that, the only 5 that is missing is in the fully revealed box 3. The line would need to drop down into box 6 to get a 5. Once it does that, it has to go back through box 4, but that requires passing through another different odd digit. So 5 is ruled out and it's a 1 one the line. That reveals the rest of the palindrome, and we're off to the races.

@iuriikononenko9238 Ай бұрын

Completed in 4:04 Spoiler alert! I marked the tip of palindrome, and checked if it was different from 24 in box 3, then the only digit could be placed would be 6, but it breaker, as all the 6s would have to be placed on palindrome, which is not true in box 3 already. Thus 24 on palindrome are the same, and obviously could not be 2s. Then it moved really fast

@steampunkskunk3638 Ай бұрын

5:51 once the palindrome us solved, it all falls into place.

@steveunderwood3683 Ай бұрын

That was a very quick and simple puzzle, but rather satisfying in the way it works out. How did he make such a meal of figuring out R4C4 has to be odd, and therefore has to be the centre of the palindrome? He must have had a bad day.

@SudokuSleuth Ай бұрын

Leaving Sudoku too lay would be my guess 😉

@martingayle5376 Ай бұрын

Your early logic showed that r4c3 could not be a 2. Still, thanks for the puzz/vid!

@karthick_michigooner7431 Ай бұрын

You missed a very important logic while considering R5C3 that is fundamental to the puzzle. (SPOILER).... A Odd length palindrome once the R4C4 is on it that digit cant be 3 as it is near 24 cell. B. Odd length oalindrome can only have one odd digit bcos there is only middle cell C I think R5C3 could never have been 4 because then we would have had double two on one side of palindrome. Could never be 6 because one 6 is already off palindrome. BUT COULD HAVE BEEN 5 D. So considering "Can 5 be on it?". We can have a max length palindrome of 5-4-2 = 11 cells. But to reach Box 1, 2,4, 5 and 6 to get 5 5s you need atleast 12 or 13 cells. Hence wont work. Therefore R5C3 = 2 and we go from there.