Star Pattern Logic - Part 2 - By Naveen AutomationLabs

[@shivamkadu5010]

❤️ Start series on Selenium tricky Interview Questions and Answer.....🙏🙏

[@kulmeetkaur6243]

Thanks Naveen for the detailed explanation. I have been struggling with patterns for long.. feeling confident now :)

[@rd3316]

🙌 how can you explain this things so easily .. hats off brother 🙌

[@jobin_john]

Hackerrank have the same question.. but it will not allow 3 for loops, as it increases time complexity... Instead they will allow 2 for loops and a if condition inside the second for loop to switch between space and *

[@అర్పిత్]

Yes it can be solve by 2 loops only.

[@anupamrokz]

Hi Naveen, I developed another logic with only two loops, one outer and another one as inner. for(int i=1;i

[@sachintripathi5742]

Thanks Naveen, Your videos are amazing. Keep sharing more videos.

[@anmolsandal3454]

Thanku sir amazing video👍 keep up the good work

[@praveenreddy9454]

yes its good and we will get complete command using for loops but here time complexity is high because we are using 3 for loops,definetly interviewer asking this question,am also trying to do this by using java 8 streams,if you can also post it ,its helpful

[@AliG-se4ph]

thank you for sharing, just something small, while you are explaining you hover over on something and you say "dont do ... that here" but we dont see the pointer on that white screen.

[@snehap2127]

significant explanation

[@samtech6252]

hi naveen, I am waiting for the diamond pattern printing star program.nice explanation and easy understand thanks.

[@shadowfrost420]

once this is done can you please start series on String related interview questions and collection related programs

[@praveenkumar-tz8ss]

Yes

[@thalapathyprasad9511]

Great explanation 👏

[@ankeshkumar1299]

Eagerly waiting for the diamond pattern.

[@అర్పిత్]

Can you solve it with single loop or without loop?

[@pandudamera7211]

Thank you brother

[@madhankumar8926]

I got this question in Barclays interview...

[@aayushpatel3360]

awesome sir

[@deepankardey5935]

very useful!

[@hasini22]

Can u explain in js also

[@JKCOfficial08]

solution with only 2 for loops - for(int i=0;i=1;j--) { if(j

[@sreereshvkm726]

👍

[@learning8942]

❤️❤️❤️❤️❤️

[@amitkhosla8474]

❤️❤️

[@PS-od2mm]

❤️

[@rocky3641]

❤️❤️❤️❤️❤️❤️

[@rockyrajeshyt6658]

❤️❤️❤️

[@rajeshchowdhury181]

❤️❤️❤️❤️