Shouldn't (n^2-1)*n = n^3-n ? it doesn't change the answer but just in case
@mathwithprofessorv Жыл бұрын
Let me check-at what timestamp?
@danielaalvarex10 ай бұрын
3:33 I noticed too
@mathwithprofessorv10 ай бұрын
@@danielaalvarexYes ok thank you for finally telling me where! Sorry for that boo boo-but yes; the result is still the same. 👍🏻 Good job catching that. 😊
@pontshokgalelemagane1332Ай бұрын
Made a mistake at 3:19 prof on the numerator when taking the limit☺. I hope you noticed it . Otherwise thanks for the lessons prof
@dayanaraflores81913 ай бұрын
hi professor v!! I am loving your videos!! I was wondering if you could do a part 2 with some trig?
@mathwithprofessorv3 ай бұрын
There is a part 2! I don’t remember how much trig is on there but check it out and get back to me
@CarlPowell-rn3kh4 ай бұрын
For the alternating series (n^2-1)/(n^3+1) why not just compare It with an alternating harmonic series and do a limit comparison test re which will prove convergence
@mathwithprofessorv4 ай бұрын
You can’t use LCT for Alternating Series, the conditions require all the terms of the series to be positive.