Strength of Materials | Module 1 | Deformation due to self weight | (Lecture 14)

[@sonuverma3999]

Aap ki video toh hit ho gayi sir,ever civil or mechanical students know about Venu sir,eagrly waits for your video

[@dattarammalkar1442]

SOM me abh confidence aarha h sir.Thankyou gate academy plus for all your efforts.Special thanks to venugopal sir sare concepts clear ho rhe h

[@nidotalen255]

Whenever I have doubt I always watch this video again and again...this sir is really amazing.. He knows what students need

[@ashishk-tw9cr]

Uniform strength of bar describe very well great sir you are superb.

[@maliwad01]

Thank you sir🙏🙏

[@chandankumar-ll3jd]

Thankyou so much sir,,♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️👌

[@debjitdas6639]

Best professor ❤️🙏

[@31princedhadwal59]

Loved your teaching

[@shubhamsaini8298]

Glamorous teaching sir. Please upload module 4

[@Krishna-wz8mz]

Thank you so much sir ❤️🙇🙏

[@niteshsingh-jz5vp]

Very good lecture 👍

[@siddharthupadhyay8121]

self weight -- 9:00 self we. and area -- 10:00

[@alcryton6515]

Great video

[@bhaskargope3722]

When we consider the downward force on the element,why don't we consider its own weight too?We just considered the weight of the part below it.

[@muzamilnazirmalik619]

Because we consider the force on the bottom layer of that element.

[@shubhamwr]

@@muzamilnazirmalik619 but while solving actual problem we consider whole element itself right?

[@vibhasingh7372]

Very nice video sir

[@pranjalsingh5281]

Sir, you said the equation does not depend on area but sir it has gamma in it which depends on area!

[@aashucaashu]

gamma is material property .....rod large ho ya small ....area kam ho ya jyada ....gamma to gamma hi rhega ....sbhi ke liye constant ....

[@ashishk-tw9cr]

@@aashucaashu right bro

[@gkforkids7431]

Bt sir jab gamma ki value I.e. W/A*L put krege to area aa to rha h... Phir ye depend kyo nhi kr rha

[@savansolgama3087]

22:58 area of CB change with A to A+dA then why you take just A

[@souvikbiswas194]

pls reply this on this doubt sir

[@thehustlingbull5326]

@@souvikbiswas194 becoz even if we consider dA it will be multiplied with dY thus dAdY which is tending to zero thus neglected..

[@rrthorgamers]

Sir upload a lecture on topic Mohr's Circle

[@soulrdx6697]

Sir in bar of uniform strength Why we applied external load P ....please answer.

[@shrishkumar6018]

6:54 how come the length of the element be dy if dy is the thickness of the element in the figure ?

[@raghav210]

Superb sir

[@angshumannayak5337]

Sir why the cross section area of the element taken as A......

[@ChandanKumar-xd1tg]

Sir aap daily video daaliye

[@ShivamSingh-rc2np]

Very useful sir

[@rajshekharmunimadugula7047]

Super super sir....

[@pushkarvarma27]

Sir please provide us lecture on principle stress

[@gagansahu6108]

Sir thermal stress topic upload kariye

[@AbhishekYadav-dk9rg]

💯❤️

[@nikhilbundhele6111]

Thanks

[@sandeepsahoo2201]

very nice sir

[@akshayraghuwanshi1370]

Great..

[@saideepkomuravelli162]

Sir..in self weight deformation, if I takeout the support from upper end and place a support to the lower end of the column what will be the change in the formula!? Will it be the same??

[@samratchakravarty9318]

in that case, there will be a reaction at the support which would be equal to the weight of the body

[@saideepkomuravelli162]

@@samratchakravarty9318 But I think support reaction will be present in the previous case too🤔. Will there be any compression due to self weight?

[@samratchakravarty9318]

@@saideepkomuravelli162 yes bro..there will be a compression...but that would be in a molecular level...we can neglect it.... For egs , if u can imagine concrete pillars without any load on them..

[@saideepkomuravelli162]

@@samratchakravarty9318 If there is compression then there should be some self weight deformation. For that what would be the change in derivation is my question bro..It was asked in Barc interview last time.

[@shaunak7712]

Did you got your answer brother??

[@aniketsaw7347]

Thank U Sir

[@jakeerhussain4139]

I have one doubt..when we ingration " Y " there we add constant " C "

[@navneetbiswal1485]

if in the element the 2 forces are different then the element will nit be in the static equilibrium ,what about it sir ? and for gamma the area term is included hence the self weight deformation will depend on the weight where should we apply the force due to the self weight?

[@beingkewl4487]

But sir in lots of book... Change in length due to self wt. = (WL/2AE) Why??

[@gkforkids7431]

Bhai ye sahi h... Isme upper niche L se multiply kr dijiye then W/A*L = gamma... To Yhi formula aa jayega

[@raviranjan1084]

Right

[@mantrinaresh2229]

right

[@abhinabdas8661]

Sir i have a doubt If I am doing a numerical question and if it given a random bar, thn how could I know that this is bar of uniform strength or not!

[@shashanksharma5530]

Sir If this elongation due to self weight does not change wrt area so why the elongation of conical bar is 1/3 of that for the prismatic bar ? Can somebody please explain

[@adwaibowlekar3943]

At 10.04 min in this video you are saying that total deformation of prismatic bar does not depends on area but the formula for total deformation includes the term weight density which is weight divided by volume and weight density will change with change in area. So how is total deformation not dependent on area.???? I think that it is indirectly dependent on area due to to term weight density.

[@ektadhapola9698]

Weight density is equal to density *g Density doesn't depend upon area. It can be considered uniform through out the bar

[@sanskarkumar6484]

Sir why sigma will come out of integration is the stress is constant from y=0 to y=L?

[@mohammadisteyakahmad9484]

Super bro

[@adityashende1053]

Bro sigma is constant that is why it is the bar of uniform strength

[@backbenchers_ki_pathshala]

Sir uniform strength ka bar jo consider kiye wo prismatic kha tha? Area to change kr hi rha hai

[@rajdange1788]

Sir aur ap konsa subject padate ho

[@predatorgaming895]

Why should we consider load p

[@sumeetsingh222]

Sir is it possible in pratical bar of uniform strength??

[@simple_beings]

While using mass of cb area will be dA ...how can you take area as A ????

[@abhishekrai6414]

Sir jab deformation of element nikalte hai ap to dy length kaese hua apne likha hai (Wy×dy)÷(A×E)- Sir dy length kaese hua

[@SANDIPKUMAR-vr1os]

Thanks sir

[@shivannaumashankar7051]

Tqsm sir

[@SANDIPKUMAR-vr1os]

Good evening sir

[@piyushdeshmukh4282]

Sir Thermodyanamics ke bhi video upload karo..! Thermodyanamics padhneme Maja hi nahi aa raha

[@artistic-v8411]

piyush deshmukh ok dear....

[@piyushdeshmukh4282]

Er. Venugopal sharma thank you sir

[@legendsays757]

Er. Venugopal sharma Plz sir upload the videos of thermodynamics.... apake vajese muzhe thermodynamics achaa or easy lag raha hai.....jo bhohot boring subject muzhe lag raha tha....vahi subject muzhe interesting lag raha hai.....very very thank you sir

[@artistic-v8411]

please wait for 28 Nov.✌️

[@legendsays757]

Thank you sir

[@vikymehra5902]

Suppose if a body is in contact with earth's surface then the acceleration due to gravity acting on body will be zero?

[@vikymehra5902]

Reply plzzzz

[@zakhussain2489]

Sir area pe deppend to krta hi h deflection becuz formulae to WL/2AE hota h ..

[@amritakumari2303]

Yha pe Jo W h wo weight of whole bar h jisko wAL likha ja skta h...sir ne w ko Gamma likha h..it is weight per unit volume.

[@columbussaud3646]

❤️

[@appleipad798]

Sir,mass of CB element should be = A+ dA ??

[@mukeshkashyap5091]

Wo area lia hai . And stress se multiply hoke wo force nikal aaya h

[@biswabehera5580]

Sir how the area of element A in bar with uniform strength as A is changes with y.

[@rajkumariverma5886]

Area is not changing as it is prismatic bar

[@rdwtv999]

sir CB ka area A kaise le liye CB ka area to dA hona chahiye n

[@de3pakkumar295]

Sir Som kab tak khatam ho ga

[@dhawalsalwan]

Sir why neeraj sir is not uploading lectures of signals and system since last month??

[@artistic-v8411]

Dhawal Salwan text me in messenger

[@prajwalkumar4185]

Where is lecture 16....Thermal stress part-2?

[@pk-sb9vt]

Sir module>4 upload kre please

[@er.tejveersingh9995]

Sir deflection in beam karao

[@jakeerhussain4139]

Sir

[@engineeringtutorials5559]

Sir please English teach is better for South side

[@shubhamwr]

I'm feeling confident that i will crack BARC interview after watching this😇

[@de3pakkumar295]

sir abhi too 1st module khatam hua hai

[@de3pakkumar295]

sir ese ka exam 6th jan ko hai ...

[@nareinroy7265]

Sir plz provide pdf

[@ChandanKumar-xd1tg]

Ese exam 6 jan ko sir

[@sunrisersacademy1993]

sir main iss figure ki imagine nahi kar paa raha hun

[@palikasudhakar1437]

Sir please explain in english

[@abinashkarmakar360]

Sir har topic ke liye ppt banake samjhayiye to aur achha hoga

[@Status-tq2pw]

thanks

[@rajeshgour9435]

Thanks sir

[@souvikbiswas194]

22:58 area of CB change with A to A+dA then why you take just A

[@muzamilnazirmalik619]

As the section is infinitesimally small, change in area over this section is very very small, that is why we can take A +dA as A. I'm not sure about it, but I think it is so.

[@sujit4976]

Thanks sir

[@vivekmalviya3036]

Thank u sir