Strength of Materials | Module 3 | Bending Moment Diagram | (Lecture 34)

[@ajaydevang]

Best teacher for engineering mechanics on KZbin ❤❤❤❤❤❤

[@satyakichatterjee1003]

for simply supported UVL SF=0 at l/(root 3) distance from B BMmax= wl2/9(root 3)

[@tariq2296]

BMmax = 2wl^2/9✓3 aa Raha h

[@29_ce_simadrinaskar86]

(-5wl²/81) a Raha he

[@ravirajranjan2775]

We get shear force zero at L/√3 distance from Right end(i.e point B) ,and the value of maximum bending moment is WL^2/9√3

[@vikasverma6502]

Thank you sir for your nice explanation. L/(3)^(1/2) . I have found without any difficulty with the help of concept.

[@archananair9915]

God bless you for such wonderful experience.

[@27_arnavsinghce52]

Thank you sir for such a wonderful experience of teaching❤️

[@Rahulkumar-tk5vv]

Sir please at least SOM khatam kr dijiye.....it's difficult to understand and you are truly helpful in understanding this subject.....please complete this one at least......we all will b thankful to you and your academy....humble request sir

[@shree945]

For simply supported UVL question, SFD would be an open up parabola in negative region upto x=L/1.1732 and in positive region upto L ,with corresponding y values .

[@CohnJena99]

Sir, i respect your hardwork , but the proper explaination of sign convention , L to R concept, Reaction calculation in SF and BM is so very complicated . Thankyou so much

[@techeasy3667]

Thankyou Very Much For Your Dedication To Make videos. Thanks from my heart. U r really doing good work.

[@ChandrakantNishad]

Very good approach for online lectures and good lecture..

[@sunilmadaancreativeideasch496]

Because your concept is very good. So i want to complete all SOM module with your video lecture. So please..please upload all pending lectures in your channel. Regards Sunil

[@civilengineers6032]

SIR BAHUT BAHUT DHANYABAAD 👌❤

[@baruahsarthak_]

Sir aaap bohot ache parhate ho....aise hi video dalte rahe....

[@structuraldrawingsforfresh9437]

Directly come to point sir

[@pramodrao1494]

Thanks sir ! Sir please make more video on som plz complete the syllabus of SOM 🙏 ASAP

[@anirudhparvatikar7990]

Get lecture venugopal sir. Keep sending more

[@harshittiwari9558]

One of the best lecture...thank u sir

[@abidislam8410]

Super... sir you develop our concept. May! Live you long long!

[@BIPINKUMAR-wr3ju]

Max BMD WL^2/9√3 distance from B is L/√3

[@shubhammaurya492]

thank u sir, sir please upload further videos soon🙏🙏

[@vaibhavdate1369]

sir you have made SFD and BMD so easy i will recommend my friends to refer this module

[@indranilbhattacharjee5662]

Best SOM teacher 🙏🙏🙏

[@shrawanshah8291]

U r great sir.Your teaching style is awesome.Thanks a lot sir

[@shubhamsaini8298]

Glamorous teaching sir. Amazing

[@suryatejanagavarapu6415]

WL^2/9*√3 is max bending moment for uvl in simply supported beam

[@rameshalle6377]

How bro?

[@ankitpatelab365]

@@rameshalle6377 assume a distance x from triangle side/point where V=0, so BM be the max, and use similarity of triangle to find x. After that summation of moments till x, (for UVL, remember 1/2*base*Height at x/3 distance from the height vertical)

[@anshumansinghsisodia2189]

@@ankitpatelab365 please clear this

[@adityashukla3444]

The value of x at which shear force is zero in simply supported UVL is L/root(3) And value of maximum bending moment is wL^2/3root(3) .

[@aftab2360]

best lectures for SOM sir

[@VinodKumar-bb6ml]

Good reference for refreshers

[@RoyalRishav01]

Good explain dear sir ❤️ jaise aaj kal ke bache actor actress banna chahta hai thik vaise hi mai bhi aapke tarah hi banna chahta hu sir 🙏 🙏🙏 I am your big fan sir😘😘😘😁

[@anirudhparvatikar7990]

Great lectures on bmd and add. Thank u very much

[@shivarajeswari5898]

Bending moment max at L/root(3) from right end

[@Gulshankumar-cn8om]

Thank you very much sir

[@JB-uu8wi]

SIR BAHOOT ACCHA...

[@ritikkaushik1501]

Thanks sir, please make a video on T or I section of moment of inertia

[@deveshwarhade8368]

Sir since the slopes in case of SFD and BMD are zero at minimum at maximum points. So in case of BMD of simple supported UDL, why the slopes are not zero at X axis (minimum points).?? And it's zero then the shape of parabolic curve in BMD will be different.

[@subratadutta7710]

Sir,max BM for the cubic curve is wl²/12. Is it right?

[@chandankumar-ll3jd]

Thankyou so much sir ♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️👌👌👌👌👌👌

[@Rajkumargadge]

SF =(W/3)-(Wx^2/L^2) BM MAX.=0.1283*WL

[@Education-js1sx]

best Faculty

[@Cryptic_Chai]

BM is max when v is 0, But for SFD of UDL Simply supported, v is 0 at two points, centre and point B. But we wrote M max only at one point (centre), Why??

[@veera7391]

No Bhai SFD is zero in SSB (UDL) only at centre... At A it's wl/2 & At B it's -wl/2...

[@Prayamclassesmath]

Sir thanks for these wonderful explanation of all the videos and clear concept building but sir please upload further videos soon

[@tuhinsuryachakraborty]

Please complete the lectures on Strength of Materials

[@mithileshshukla8722]

Fabulous lecture

[@MohdZeeshan-gu6kq]

dear sir, i was waiting for nearly a month for your new videos,,thanks for uploading it

[@mubeenabegum357]

Please pray that he starts worshipping the Creator.

[@shubhamgurav9194]

Best content ever🙏🙏

[@dewashishpatel5578]

Sir,Thank you very much for such informative video sir please complete syllabus..

[@29_ce_simadrinaskar86]

Bending moment at UVL is(last question) =(-5wl²/81)

[@vsharma197]

Awesome sir!! ❤️

[@ruhulaminshatu2787]

Is the last bending moment curve is right? Two slopes are zero so cubic curve should be different. Please ans me.

[@sangeydorjee9878]

From left= l/3 From right=2l/3

[@navinbharti4283]

point of contra flecture is ((2*L)/3) and max bending moment is ((2wL^2)/27

[@engineeringstudents150]

Thank u sir❤️

[@lavanyakotni9404]

Then what will be the BMD for uvl load sir

[@57aditya]

Sir for the given uvl we should solve from right to left then maximum bending moment comes to negative

[@shivamghundare9930]

Very perfectly understood

[@ramraojadhav3103]

2l/3 &L/3

[@ashrafkhan5607]

Very nice session sir Thanks

[@yashghanshani5790]

Sir plz share videos on material science and RAC...

[@indrajsaini8560]

You are grate sir...

[@harshvardhanreddy6328]

🙏🙏🙏 Thanks you sir❤️❤️

[@bablookumar5549]

Very useful video

[@TarunKumar-tx7ik]

sir aage wale modules bhi upload ker doo

[@AjitKumar-np8sm]

X= L/3 from A X=2L/3 from B Maximum BM= WL^2/9

[@abhishekkumaranshu3074]

Sir aage ka video kab aayega?

[@tariq2296]

S.F=0 at x=l/root3 from A B.Mmax=2wl^2/9root3

[@amitmishraanant7831]

43:19 slope concept

[@yaseen5048]

Why other videos have been deleted

[@mayurbauskar1574]

If ans will be positive then we can draw sagging case parabolic curve and ans will negative then we can draw hogging curve its right sir.

[@piyushraj9749]

Why dv/dx =-w for UVL because it was derived for UDL?

[@Sports7G1]

this is universal bro

[@naveenkhani6272]

Sir i have one ques., Wher we use sfd and bmd in practical life

[@prabhatkumar-ue4kt]

sir plz upload video frequently

[@rohitbhatt1974]

Kuch supports m apne section method use kia or kisi mi without section method use kiye SFD draw kr dia..kaise pta chalega ki section method kb use Krna hai ..

[@ankanaman8451]

Sir at 45:08 sir shear force at point c zero kaise ho gya sir shear force at point c is equal to( -pa/a+b ) tha n to aaap es ko zero kaise kiaa hai

[@thesarcasticengineer7]

Ho jayega bhai shuru se achha se digram draw kijiyega to aa jyega

[@vindhyeshvariprasadupadhya2365]

Deflection of beam par video बनाइए sir

[@vaishnavidhruv7558]

Sir ye concept to uvl on cantilever beam ke liye hai to agr Right to Left SF and BM ka calculation karenge to values negative hogi kya?

[@ghousebabu9270]

Sir please tell the topic beam with internal hinges also sir...

[@aryanshrivastav1211]

Sir, cantilever or over hanging beams ke bending moment k liye video aayega..?

[@anshumansinghsisodia2189]

Bro please help me to find this please

[@aryanshrivastav1211]

@@anshumansinghsisodia2189 aap gate academy k Chenal pe dekho...kahi mil jayenge ..

[@pravinjadhav2766]

Sir when u r going to upload further modules..pls do it...

[@pranayjain1737]

Nice video sir. Concept clear Ho gaya hai but practice ki jarurat hai isliya kon si book refer Karna chahiya jo Apke concept si milti hai ho. I have R. K Rajput but sign convensation different. Please suggest. Thanks

[@shubhammaurya492]

Thank u sir...... 🙏🙏Sir please som complete kr dijiye.......

[@UVS0079]

43:24 sir point B pe to shear force zero aaya tha. Please clarify this doubt

[@121aayushpatel4]

Bro don't confuse with concept of just before and just at point in sfd because in sfd point load show sudden reaction. Actually both lie at same poi t isliye to sir ne bhi bmd me just before nhi nikala only just at point nikala .

[@UVS0079]

@@121aayushpatel4 Yeah this got clarified. thanks tho

[@121aayushpatel4]

@@UVS0079 👍👍

[@anujnamdev2567]

SFD for simply supported (UVL) nhi bana, sir please help

[@naveenreddy1180]

Thanku so much Sir

[@MunnySingh-qi7kc]

Thnku sir

[@aryansharma2592]

Slope and deflection macauley method

[@laljeetyadav6354]

Maximum B.M. = (4WL^2)/27

[@subratadutta7710]

Sir,if the uvl is reversed ( at b w=0,at a w=w), then the graph will be exactly like x²=4ay graph. Is it right? If anybody knows please help.

[@ankitrawat7334]

21:24 sir ek bat smjh nhi aayi agar point B pr bhi shear force ki value 0 hai to figure m maximum kyu aaya

[@SagarBhola]

Kyuki dm/dx=V hota h ... Aur max BM ke liye dm/dx=0 ... So comparing the two .. V=0

[@shivamghundare9930]

Thanku

[@ravikantpandey3612]

l/3^1/2

[@rishabhgupta2340]

l/root(3) from right end- B.M. max

[@dhananjaydhondarkar5810]

sir plzz add lectures on slope and deflection

[@-ZubayerAhmedAditto]

thank u sir.

[@sksameer7735]

Thanks sir

[@sudhiryadav6504]

sir please complete all modules of this topic (SOM). we are eagerly waiting for that.

[@kunjpatel993]

distance =L/√3 MAX MOMENT = WL^2/9*√3

[@thesarcasticengineer7]

👍

[@pratikbothara1766]

Why force in uvl act at centroid

[@VIJAYKUMAR-ic5jb]

Sir please complete syllabus of som