Example Particle Kinetics with normal and tangential coordinates (part 2/2) - Engineering Dynamics

Part 2 of an example particle kinetics problem using newton's second law with normal and tangential coordinates

[@cwa5493]

I hate dynamics and get nothing out of lecture, but when I watch videos like yours it finally clicks. Thank you for helping us moron's understand, and please keep making more videos.

[@structurefree]

thank you for your question and noticing that error!! I think I forgot a negative sign for the mg*cos(theta) at 2:58. I'll have to annotate the video.

[@yusuffabdulmusawwir6807]

Why are we adding a negative sign??...can we just assume wcostita and wsintita?

[@trinitywilkins2445]

Watching in 2020 and your video is much appreciated! So thorough! 🙏🏼🙏🏼

[@structurefree]

wakanda and structurefree forever!

[@CodyKoehler]

Your videos are amazing. I really appreciate it.

[@Eshaddy2]

You're the coolest man, love your videos, so helpful!

[@ibrahimkuru3910]

You are the best man.

[@canberkfidan]

hi, can it also be solved with the radial and transverse components ?

[@PieRad1]

Great video! When you integrate @ 32 sec., where did you get -1 and -4?

[@fernandezaljonkyle2118]

hey, just want to ask why the mgsin(theta) became positive since the video from the previous video, the W has a negative sign .

[@jishnusuri]

The equations at the beginning and the one at 2:58 dont match Is there any reason for it?

[@aselgunasinghe2936]

Nice

[@amyisaverb]

Enjoyed your video, very helpful in learning dynamics. I noticed at the end you get 56.86cos(ϴ)-23.24N. I did the same problem and got 37.39cos(ϴ)N from next to last step (56.9961-2g)cos(ϴ). Thought you should know.

[@Ledviir15]

Where do the -1 and -4 come from?

[@PrinceAbubu59]

-1 comes when he evaluates the integral (cosϴ - cos(o)) and -4 you get that after evaluating the other integral (v^2 - 2^2 ) He basically skipped that one baby step from cal 2

[@serkutaktas577]

in the first step we found -mgcosq+Nb=mv^2/q but after he transfer it to positive i think he made a mistake about it

[@structurefree]

Serkut Aktas yes, at 2:40, I forgot to include the negative sign...the equation should be -mg*cos(theta) + N_B = mv^2/rho. thank you!

[@BrandonDeehan]

@4:45 shouldn't the answer be Nb= 19.62N*cos(theta)-23.24N

[@Yllor07]

I know it's old, but it should be + 2kg(9.81)cos(theta) // not negative(-) 2kg ... And he updated it but not visible until the video end.

[@mariopersaud6703]

im so confused idk why i cant figure it out but how did you get 5.81 @1:28

[@josiahkwong-wah4263]

me too, have you figured it out yet?

[@Mohammad12765]

yeah where is comes from? should not it be +4

[@kennethforonda1752]

seriously, how did he arrived a 5.81 value

[@CodyKoehler]

This is old, but if others have the question. He added the 4m²/s² to both sides after multiplying both sides by two. It moves it from right side to left.

[@andrewwong8686]

This problem can easily be solved using Conservation of Energy.