STUDENT QUESTION Grade 12 Calculus Graph Interpretation | NTE

Grade 12
Cubic Graphs
Student Question
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Question submitted by : Nompendulo
Grade 12 Prelim North West 2016 Q7
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#Grade12HasNeverBeenEasier
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The Department of Basic Education does not endorse or accept responsibility whatsoever for the accuracy of the explanations and/or methods provided in the solutions presented in this video. All errors and misconceptions conveyed remain that of New Technological Education.
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[@damonrossouw9732]

That last Question stumped me... Not gonna lie.

[@1moving-forward]

I almost didn't trust your last answer because the examiner said that k>0 and k

[@tedblue3281]

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[@muziwakheprosperous315]

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[@silindokuhlenoxolo1052]

Can you please do some questions that have a turning point which is also a x- intercept

[@samzalucio2225]

5 November 2021 here we come. Hope my students will master this upcoming paper.

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@@Brianbandzzz nope😭😭😭😭

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Thank you so much 🙂

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[@nicholus__4570]

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[@mphatso4669]

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[@kamogelojiyane9929]

can i ask how you got the 3x squared plus 2px plus q is equals to zero

[@user-pb5cn1bw3k]

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[@clairepurdy7238]

I will see you guys next time.... 11 months later still no new uploads😂

[@ThePLUGThapelo]

Whats K related to x/y?cos wow😧

[@elisha9625]

Nice

[@northhorr1783]

awesome

[@nl8915]

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[@basetsanantokozomamaila1910]

It's not visible 😢

[@serogolemogole2685]

N4 differential calc

[@EmmaKapokola-kk4rn]

So cute

[@candiesmasweets4479]

For the last question, is it not -12-19?

[@loratolovesoreos]

I'm sure you've been answered but incase you haven't, we are looking at k as the movement of the graph of g. -19 and -12 are the y-intercepts of the two graphs, and not the movement of the graph. So when g goes through -19, the graph hasn't been moved therefore k is 0. When g goes through -12, it has been moved 7 units up as in its original position, it goes through -19. So k(the movement of the graph of g) is between 0 and 7

[@loratolovesoreos]

I hope that makes sense😭😭😭

[@Elunico989]

It doesn't 😢

[@sunshinemagagula1284]

Mistake in your solution to 7.4. The correct solution should be 0 ≤ k < 7. If k = 0 and f(x) = g(x) + k then x^3 + 5x^2 - 8x - 12 = 5x - 19 So that we obtain x = 1 , x = 1 and x = -7 Hence we have TWO positive roots, as required.