Solving Systems of Linear Equations by Substitution Method

This algebra math tutorial explains how to solve systems of linear equations (simultaneous equations) using the substitution method. It covers a range of examples, including systems of equations with infinitely many solutions or no solution. It also shows how to verify/check the solution.
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[@gotutormaths]

Elimination method 👉kzbin.info/www/bejne/h2mre3ugdreAjNU Graphing method 👉 kzbin.info/www/bejne/iaC5hnh5pbyegcU

[@legendbro6230]

Thanks sir🎉

[@izuraiz4u]

Bro your explanation is outstanding! Very well explained.

[@errm63]

thank you so so much ive been searching for a straightforward explanation like this for hours

[@legendbro6230]

Any INDIAN HERE 🇮🇳 . . . . . . . . . . . . . . . . . . . . . BTW. NICE EXPLANATION

[@AmiiraSowed]

breath taking

[@ElizabethOtoo-es1rf]

The (d) I didn't understand

[@hamzakh3340]

Hey I have question C I haven't understanding how did you distrube by 5 The number was 5(2x+8)=(3/5-6)5

[@gotutormaths]

That is to get rid of the fraction on the right side of the equation, which is 3/5 (the coefficient of X). To clear the denominator, which is 5, we need to multiply the right side of the equation by 5. However, we also need to multiply the left side of the equation by 5 to keep the equation balanced. I hope this makes it clear.

[@viduninelithya5590]

Really appreciate.🥰

[@tv-11v]

What if my y have a decimal value?

[@MosMoses-h8t]

I love this patt😮😮😮

[@elizabeth-eh7zx]

Perfect work

[@jeon2097]

4:41 Can you explain why did you multiply by 5 ?

[@gotutormaths]

That is to get rid of the fraction on the right side of the equation, which is 3/5 (the coefficient of X). To clear the denominator, which is 5, we need to multiply the right side of the equation by 5. However, we also need to multiply the left side of the equation by 5 to keep the equation balanced. I hope this makes it clear.

[@sssssunyy]

hi, during the 10x + 49 = 3x - 30, i was just wondering why you can’t just combine like terms ? because in some situations you need to combine and in others you need to subtract. why is that? is combining like terms only for linear inequalities?

[@nerpeeplays7916]

C. x=-10; y=-12

[@User.not.found111]

Hello, amazing video, just wondering why for “D” did we cancel out the 6 with 12 but not the 10 and 2 for the last one?

[@gotutormaths]

Thanks! I'm glad you enjoyed the video. In example D, we had the expression 12((5+8𝑦)/6). We were able to cancel out the 6 with 12 because 6 is a common denominator for both 5 and 8y. So, we simplified 12/6 to 2, making the expression simpler before we distributed. In the last example, we had the expression 10(1/2 𝑥 + 3). Here, 2 isn't a common denominator, so we couldn't simplify it with 10. Instead, we just distributed 10 directly. Let me know if you have any further questions!

[@mohammadhasanshamsodin2386]

Hello Master. My question is how can we do this: Y=5x-1 Y=11-3x over 6

[@mohammadhasanshamsodin2386]

I get confused by questions like this

[@syvin9206]

In C, was it (-10, -12)

[@gotutormaths]

Absolutely, you are correct. The solution itself is accurate, but I mistakably swapped the X and Y values in the final answer. Thank you for catching that mistake!