Thank you so much for this video, this contains examples for many distributions, which is what I longing for as most books only share the questions without answers😢. I will definitely explore other videos in this channel. Thank you once again❤
@statisticsmatt9 ай бұрын
Many thanks for watching! Don't forget to subscribe and let others know about this channel.
@rd107032043 жыл бұрын
Thank you so much for making these videos! I am in a statistics program but my undergraduate background isn't in math, so I always feel a little behind. Your videos are extremely helpful!
@statisticsmatt3 жыл бұрын
You are so welcome. I love hearing that the videos are helpful! If you'd like me to cover a specific topic, please let me know.
@risingstarr12342 жыл бұрын
thank you. the examples where the support depends upon the parameter were especially helpful
@statisticsmatt2 жыл бұрын
You're welcome. I love hearing that the videos are helpful. Much appreciated. Many thanks for watching. Also, don't forget to subscribe and let others know about this channel.
@ヒッセン-b9c2 жыл бұрын
thank you for this video, helped me a lot !
@statisticsmatt2 жыл бұрын
You're so welcome. I love hearing that the videos are helpful. Many thanks for watching. Don't forget to subscribe and let others know about this channel.
@zwan18862 жыл бұрын
Do you use Casella & Berger as a basis for a lot of this material?
@statisticsmatt2 жыл бұрын
I don't. Although I've heard that it's a great book and wish that i had a copy. Many thanks for watching. Don't forget to subscribe and let others know about this channel.
@fmiller362 жыл бұрын
For example 3, shouldn't the answer be the summation of Xi's as sufficient for theta? I don't see x-bar anywhere in the expression for g(T(x) given theta).
@statisticsmatt2 жыл бұрын
thanks for you question. also, many thanks for watching! much appreciated. You are correct that the sum xi's is a sufficient statistic for theta and i didn't explain how i chose x-bar. if we multiple sum xi's by 1=(n/n) we have n*x-bar, which means x-bar would be the sufficient statistic for theta.