In the above rxn which is the rate determining step??? In sulphonation of benzene Also in iodination??
@arvindkumarm19278 жыл бұрын
In iodination of benzene, deutrobenzene(C6D6) nd tritiobenzenzene(C6T6) The rate determining step Is the breaking vof C-H bondCan u pls explain Y??The same happens in sulphonation of benzene
@saurabhinorange11 жыл бұрын
Can you also do side chain oxidation using kmno4 Thanks
@zabign72499 жыл бұрын
is it possible to do a friedel craft after sulfonation
@goldenfriedc6 жыл бұрын
the so3h has one bond between the oxygen and sulfur? that oxygen should have a bond between H and S?
@pieter-ruannpieters92506 жыл бұрын
why would the H2O take another H from the benzene, rather than the H going to the (HSO4)- from the previous steps?
@lelo379Ай бұрын
H2SO4 is a strong acid, therefore the reaction HSO4- + H+ -> H2SO4 is highly discouraged
@AnshMehtaGR88 жыл бұрын
how can a strong acid behave as an base and autoprotonate itself???
@motivations-d6sАй бұрын
I was 5 years old
@AnshMehtaGR88 жыл бұрын
why this is a reversible reacn ??? is this due to its Energy Profile??