Sum of Products (Part 2) | SOP Form

Digital Electronics: Sum of Products (SOP) Form in Digital Electronics
Topics discussed:
1) Canonical or Standard sum of products form.
2) Minimal sum of products form.
3) Canonical to minimal SOP form conversion.
Follow Neso Academy on Instagram: @nesoacademy(bit.ly/2XP63OE)
Follow me on Instagram: @sujeetsingh20(bit.ly/2JLcQz5)
Contribute: www.nesoacademy...
Memberships: bit.ly/2U7YSPI
Books: www.nesoacademy...
Website ► www.nesoacademy...
Forum ► forum.nesoacad...
Facebook ► goo.gl/Nt0PmB
Twitter ► / nesoacademy
#DigitalElectronicsByNeso #DigitalElectronics #SOPForm

[@AceMovieShorts]

This whole series is just amazing and fresh after the 6 year. It is just wow that I am commenting here bcz it is very less chance that I commented on a video. Thanks again a lot lot 👍👍👍👍👍

[@ChetturuKhaleel-h5p]

Even after 8 years

[@AceMovieShorts]

@@ChetturuKhaleel-h5p f*ck man, I can' t believe, I got notification after 2 year for reply and What!!! It's been 2 year of my comment!!!

[@jaihindjaibharat1182]

Even after 2024

[@adumont]

I love this series. Thanks you so much. I'm learning a lot. Im literally devouring the videos one after one

[@pradeepchaudhary2739]

thanks sir... you created my interest in ece ... i have done btech...in btech i didn't study though the majority of teachers were good....i started after btech for ssc ,bank and all that govt non-technical exams and some technical exams form(without prepare😑)...one day i was watching your lectures for BJT.... after watching your lectures i decided to go for technical also with preparation.... and you just make electronics favorite for me 😃... thanks again

[@anontyim]

what are u doing now , just curious

[@swastikthorat9501]

helpful video to understand sop during corona pandemic.Great teaching!

[@locsei105]

Thanks for this great series of videos. It is very well explained. Keep up the good work! :D

[@gee_at_ease]

You are a Blessing!

[@Dharani12335]

Excellent teaching really awesome Thank u so much sir. These videos are very helpful

[@yugaluk0710]

in the second question also we are writing the SOP form of the given expression, but then it contradicts the fact that we write minterms for those combinations only for which output is high, but in the 2nd question 1st minterm is m0 , combinations for which doesn't give output as 1 it is 0 in Truth Table

[@snehashishbanerjee2575]

Good observation! I'm also wondering about this thing!

[@deepaktewari977]

@@snehashishbanerjee2575 you are comparing the truth table of 1st question with the second one

[@circuitsanalytica4348]

@@snehashishbanerjee2575 these are different questions. TT is fr first problem and in second problem m0 is 1 as it is given in the expression.

[@circuitsanalytica4348]

@@deepaktewari977 exactly...

[@youngmoneyy76]

thank you SO much!

[@yukthakiran7909]

its ok write the exam without fail

[@chakradharthota1100]

@@yukthakiran7909 😂

[@ece39pranshupatel71]

Best series on digital electronics 🔥🔥

[@circuitsanalytica4348]

Yes, his vidoes are very good. .....

[@durgaprasadthandra4066]

You are my one of best online teachers, thank you so much

[@circuitsanalytica4348]

Yes excellent classes...

[@macaulayomoikhojede-great8880]

NESO ACADEMY. THANK YOU SO MUCH. VERY SIMPLE EXPLANATIONS AND EASY TO UNDERSTAND 🔥🔥

[@merajis]

This is fantastic! Thank you

[@Martin-dk5ve]

I have learned alot from this, thanks

[@juliawanja8114]

Thanks sir,,i have exam for digital electronics today and you saved me with this tutorial 🎉🎉

[@BlackOpal-dk6iv]

SIR I HAVE COMPLETED LECTURE 13 OUT OF 202. TREMENDOUS LECTURE AND THANKYOU FOR YOUR GUIDANCE !!

[@emvegito]

U litterally solved question2 with 1st truth table but m0 and m2 are not high so why take them in sop form

[@jahidshaon9640]

he just explains from 1st table

[@pavanvimmii9154]

you explain from the first table . the question is without truth table and provided only minterns so then he has to explain how to write minterms in sop form

[@priyannssshhhh1111]

Sir, i am learning a lot from this. thank you. is this series designed for Gate aspirants or engineering college exams.

[@Aman_Yadavvvvv]

Thank yo so much for these wonderful lectures, i have a doubt and that is in the second question also we are writing the SOP form of the given expression, but then it contradicts the fact that we write minterms for those combinations only for which output is high, but in the 2nd question 1st minterm is m0 , combinations for which doesn't give output as 1 it is 0 in Truth Table

[@yugaluk0710]

same question i have ... please clear it we r having problem #NesoAcademy

[@goumuk]

That truth table is valid for question 1 only. In the 2nd question, the truth table is not given, but we can construct it since we know the function f has 1 value for minterms m0, m2 and m3. We get this information from the question.

[@hadoopbro8103]

@@goumuk But in the previous vid he clearly mentioned that the truth table will not be given in the question. So, how did he derive the values of F?

[@alokdedo9987]

Are you indian....pls tell how can I use this ..and at where .... I'm in class 11 na .....

[@eutopiarhythms8743]

I love Neso Academy ❤️

[@simbathelabrador8925]

in 2nd question m0 and m2 output is low. we should consider only high outputs in sop form, then how are we using low? can anyone help?

[@anshverma2954]

m0,m2 output is low for the function given in first question. For second question just neglect the output of the truth table given in video; as we have to check the output for the func. given in 2nd question.

[@Rahulgupta-lr9wr]

@@anshverma2954 ha aapne shi bola or upper wale me bhi ki output high ka dekhna hai by jb questions m hi given de rkha hai to panchayat Kyu krni

[@ghhzhxbzhx4663]

@@anshverma2954 pr AB , A'B' kaise likha sir ne?

[@gautamsoni4375]

in 1 question it is sop but no condition is given in question 2.

[@emvegito]

@@anshverma2954 but A'=0 B'=0 and its an AND operator so how can the output be high for this

[@knowledgeunlimited]

sir why should we only consider high values in sop form??

[@vikasbhai4517]

rules hote h jo follow karne hote h

[@noorkhattak9247]

@@vikasbhai4517 ye 1 or 0 kaisy ata hai

[@ahsansiraj7505]

@@noorkhattak9247 ye high low h bhai 1 = high 0= low Ye apne app dia rehte hai ques. Me hope u understand..

[@UECAshutoshKumar]

Thank you sir

[@shankhadeepchoudhury8656]

Ur teaching is very nice

[@bertinaagnes73]

In the last video at 10:38, by distributive law you taught us to neglect compliment. But in this video, 7:32 your asking us to keep the complement? Which is right? Someone please help.

[@himanshu7103]

video is only 8 min long lol

[@bertinaagnes73]

@@himanshu7103 read it again, "in the last video"

[@shivanipriya9395]

Thanx sir for these series of videos...It is helping me a lot.....Bt sir aap PDF ka link share kijiye n plzzzzz to solve more and more questions....

[@murarikargnaneshwar9450]

Sir pls provide notes as pdf it will be very helpful sir🙏

[@komilj5580]

Sir, my minimal result is Y = A + B for the function Y = m0 + m2 + m3. I solved the problem like this: Y = A'B' + A[B' + B] => Y = A'B + A => Y = A + B

[@lisaroy8706]

Priority order NOT> AND>OR

[@abhishekverma614]

thanks for such best delivery

[@taazaimaan]

sir please specify how to make truth table of sop

[@akashmishra741]

Yes sir

[@slingy7009]

@@akashmishra741 bhai just previous vid mein bataya tha

[@akarshsaxena7810]

sir in 2:30 min...in example of standard SOP form A'B' toh 1st term h.. l mean low value h...and aapne bola tha standard SOP form high values se bnti h...

[@_tauqeerahmad]

this is what i am saying....i thinks sir ne thodi mistake ki hai

[@nopecharon]

Awesome work

[@shivanimishra6394]

sir can u provide videos for electronics devices.

[@steevenkenny9791]

You killed it sir...love the show

[@barsilgen120]

thanks a lot

[@pradeepmishra7231]

sir , do you provide other subject video lecture apart from digital electronics??

[@ravikumarsingh6195]

In distributive law which to neglect A' or A as SOP 1st video A' is neglect and SOP 2nd A is neglect...... Answer me

[@amirinenisaivenkatadhanush9303]

Yes, I have the same question too.Please answer this

[@bhanusharma9768]

Shaandar jabardast jindabad

[@akshaypatel1362]

thanks for upload it's really help to understand

[@pagal6397]

Thank you so much 💓

[@bechir406]

how could we use the sop form when we have 0 as an output like in the second exemple

[@rohithooda1577]

In the 2nd example when we are minimizing the solution; A'B'+A.B'+A.B if i take the last 2 term(A.B'+A.B) and i reduce it my answer is A'B'+A. Can you explain me how to reduce it further to get the answer B'+A?????????

[@AJ-bj5ds]

For example F=X+YZ =(X+Y)*(X+Z) [Distributive Law] Then in ur question A'B'+A Can be written as (A+B')*(A+A') As we know that A+A'=1 therefore =(A+B')*(A+A') =(A+B')*(1) [ A*1=A ] =(A+B')

[@rohithooda1577]

Thanks dear :)

[@AJ-bj5ds]

@@rohithooda1577 😄

[@SwastikKS]

@@AJ-bj5ds you helped me 4 years later

[@nitishkumarprajapati6096]

Thanks Sir 😀😀

[@abdulahad1538]

sir in Q4 (midterms) the truth table will be like a=0 b=0 g= 1 a=0 b=1 g=0 a=1 b=0 g=1 a=1 b=1 g=1 is this right

[@bipinlimbu3061]

how to make truth table of sop form?

[@namastenoob6023]

in second example if we give A=0,B=1 that is m2(minterm 1) the result for F=A'+B is 1 .but its not as per truth table

[@GurpreetSinghkalyan]

NAVEEN GOLLA loīa97

[@JayPatel-lp2qf]

Thank You!

[@RajeshSoni-dw1rv]

How u determine number of minterm in canonical sop form ?

[@circuitsanalytica4348]

That depends on other terms, if there is any non standard product term, based on number of missing variables number of minterms will increase. If only one variable is missing then number of terms will increase by two....For details visit my channel....

[@tushartyagi5293]

sir i have a doubt in second questions that is we given that m(small m) so why we not choose the low of y . thanks a lot sirr for providing wonderfull content

[@samyukthajhanvi]

Tremendous explanation sir but some what confusing for me🤔🤔🤔🤔🤔🤔

[@chirag3866]

is the solution A + B' correct ?

[@ishaqkhan4508]

u are awesome bro

[@AnuragShrivastava77]

In last example I have got (A'B' + A ) then I minimized For minterm answer is ( B'+A. )

[@davidsadindi2289]

Thats correct In his other video he actually said you should ignore the compliment in that case

[@mukeshpathak7302]

bhai wedenesday ko exam hai DE ka.. abhi tk kuch nhi aata.. aaj se start kiya h.. ache number aa gye to kasam se gift bhejunga tere ko..address de diyo.. faadu teacher hai yar tu _/\_ #respect

[@tigerhoodrumo1531]

hello sir thank u so much for this video sir iam doing btech from nit Arunachal Pradesh

[@thamminachandrakala99]

how do we know the min terms when numbers are given like in 2nd question

[@tangenikufuna524]

But is that last answer not B ? For instance if you use the absorption law

[@ShivamSingh-hk5pn]

Sir Why neglect B in this case Y=Comp(B) +AB

[@shankhadeepchoudhury8656]

I'm sure it will help me in my isc

[@kiranharish4471]

nice work

[@lice-sb5qi]

Thanks 👍👍

[@rahulsola8763]

thank you very much sirr

[@froopi2]

Thanks

[@shlokmantri799]

how did you write truth table ??? from which logic you have make that table??

[@xnns8195]

for finding sop, shouldn't we have to use the AND table? because the minimal are in product form? didn't understood? can anyone make me clear ?

[@aditisingh1808]

I am also not the getting the same thing, sir

[@santoshkumar7900]

do we have to remember the truth table becoz value of mo,m1,... will differ for diff. truth table

[@anupriyarani6902]

Sir , if we taken negative logic system instead of taking positive logic system then will be still take 0 for A and 1 for A compliment. As no of terms in POS and SOP will be get interchanged is we follow 1 for A and 0 for A compliment. I hope you gotten my question 😥

[@albraa951]

As i know, the standard form is the minimal form you are mentioning, yet the canonical is the form that contains all the min/max terms!!

[@Fitbrahman7]

Q. Simplify in SOP fom. F(A,B,C,D)=(0,1,2,5,8,9,10) Sir kaise hoga??

[@rajarshiraychowdhury1501]

if min terms are given like Y= summation m (1,5,6,7,11,12,13,15) then how can i write the expression for Y in SOP form using minimum number of terms?

[@yusufefl]

use karnough for 4 variables.

[@abby.studios]

will we always get the truth table with these types of questions?

[@parvgarg3191]

in the second question also we are writing the SOP form of the given expression, but then it contradicts the fact that we write minterms for those combinations only for which output is high, but in the 2nd question 1st minterm is m0 , combinations for which doesn't give output as 1 it is 0 in Truth Table . EXPLAIN ?

[@circuitsanalytica4348]

The problems are different, I think you had mixed Q1 and Q2...

[@obiwanjacobi]

@6:23 should m2 not be /AB and not A/B?

[@akalee37]

compliment -> complement

[@sanket4242]

Sir you didn't explain Minimal SOP to Canonical SOP

[@circuitsanalytica4348]

This is available in my channel....

[@FundaTechAnalysis]

Sir here in the second example you have taken m0 for which y=0 but In the last lecture you told that we do sop form for only high value that is where y=1. So could you please explain why you had taken m0 in second example?

[@bechir406]

Sumit Kumar m0 and m2 it’s weird

[@bhargav1811]

0:55 Is there any trick to directly find minterm just by seeing like this ?? Any trick??

[@jmy976]

Is there any video by Neso Academy about Converting POS to SOP or SOP to POS?

[@continnum_radhe-radhe]

🔥🔥🔥🔥

[@VishalSharma-jf2hs]

How you are taking truth tables

[@uietchandigarhvelfies5590]

thanks sir. but there is one question. as u have taken m(2)=[1 O]. if I will take it as [O 1]. then our answer will be true??

[@wenxuli4234]

you should not mix up the order of 01 or 10. 01=1(2^0) but 10=2(2^1).hope that answers your question.

[@sciencemahfil6106]

Sir why in 2 nd questions we are saying sop form but the output of m1 is 0 and in sop form we take only 1 as output

[@avradeephazra4409]

We're writing the minterms only when the output is high for the corresponding function. But, in Q(2), for m0 you're taking A'B' while the output is low according to the given table in Q(1). I can't understand this part. Please explain.

[@SahilKumarSah12]

Y output (0,1,0,1) is applicable for qn 1 only. Qn 2 is different from qn 1. For qn 2 since Y(A,B)= Σm(0,2,3) therefore the output will be (1,0,1,1)

[@Peeks...dreams]

how u created that truth table

[@sarangghatkar3937]

sir please upload videos on microcontroller

[@CMTejalNANKADE]

Sir how to find the result of truth table mentioned in this video

[@CMTejalNANKADE]

Sir please reply

[@circuitsanalytica4348]

Consider each minterm, add all minterms, that is your answer.

[@santanubanerjee5371]

sir can u give me a one more problem solution of sop expression with four variable (a, b, c, d)

[@marbles5590]

how did you get m1, m3, m0 in 1:08?

[@Davidlahall]

why is A`B] m1 , AB] m3 , A`B`]mo??? as opposed to m0, m2,m3

[@itsbarki3656]

Love from Pakistan

[@gautamsoni4375]

how these truth tables are created ? plz let me know

[@harshitahuja5043]

Doubt - How to convert Minimal SOP form Into Standard / Canonical SOP form ??

[@martynaaaaaaajl]

I would make a k-map and then name all the k-map minterm entries

[@harshitahuja5043]

@@martynaaaaaaajl Thank you ...

[@hetaeramancer]

@@martynaaaaaaajl what's a k-map?

[@circuitsanalytica4348]

Suppose if variable C is missing in first product term, multiply that term with C+C', if two variables are missing, say Cand D, then multiply that product term with C+C' and D+D'

[@krishnajangir1784]

sir i got the answer of 2nd question as A'+B. Is this correct

[@hamedhamed-ox9ty]

we cn take A also right

[@akashkumartiwary3223]

How m(0,2,4,7) is convered in sop form

[@rishabhpandey8226]

in the very last question we were having y= (AB)' + ab' +ab can we take x= ab and further we will left with y = x'+ ab'+ x = x'+x+ab' =1+ab' =ab'

[@rohitnamballa236]

no..when 1 is OR with any other variables then asnwer is 1..so 1+AB'=1 no AB'

[@rohitnamballa236]

also according to de morgan's law A'B'=(A+B)' not (AB)'....(AB)'=A'+B'

[@circuitsanalytica4348]

No, according to your steps the answer is 1

[@Abir_Dutta]

1. A'B' is not equal to (AB)'. [(AB)' = A'+B' by De Morgan's Law] 2. The answer will be 1 by your steps.

[@9315roshankumar]

Can i take A common from last two

[@yashmishra8244]

Why we write SOP for High Outputs only??

[@circuitsanalytica4348]

The SOP expressions evaluates to 1 and POS evaluates to 0

[@nateeflix2845]

The Quiz doesn't work. I'm sad

[@MrecCSEA]

How do u write the truth table directly?