Symmetrical Fault Analysis

Download Fault Analysis lecture notes (pdf) using the following link:
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Economic Operation of Power System (Playlist): Click the link below
• Economic Operation of ...
Fault Analysis (Playlist): Click the link below
• Fault Analysis
Stability Analysis (Playlist): Click the link below • Power System Stability
Per Unit System (In Hindi): (Playlist): Click the link below
• Per Unit System (In Hi...
Bus Admittance Matrix (In Hindi): (Playlist): Click the link below
• Bus Admittance Matrix
Gauss-Seidel Method of Load Flow (In Hindi): (Playlist): Click the link below
• Gauss-Seidel Method of...
Newton-Raphson Method of Load Flow (Playlist): Click the link below
• Newton-Raphson Method ...
Decoupled/Fast Decoupled Load Flow Method (Playlist): Click the link below
• Decoupled/Fast Decoupl...
Load Flow Analysis (Playlist): Click the link below • Load Flow Analysis
Power System Analysis (Playlist): Click the link below
• Power System Analysis
Network Theorems (Playlist): Click the link below • Network Theorems
Regards
Dr. Afroz Alam

[@DrAfrozAlam]

Download Fault Analysis handwritten lecture notes (pdf) using the following links: drive.google.com/file/d/18Zvgdi3YD6iAIkWJwz5-s7dVHRgM6lwZ/view?usp=sharing drive.google.com/file/d/1sfMf8BDsZ1BlKoehLLkokwizgtWHIbrr/view?usp=sharing drive.google.com/file/d/1eYOtrSzN7VwsqiLwjnrJ79BQd2LcE_Vy/view?usp=sharing

[@DrAfrozAlam]

You're most welcome

[@omerkarar8405]

This is exactly what I expect from a teacher, being direct and unbelievably precise! Thank you very much, teacher!

[@ganinitianelectricalkkr9686]

mashallah 😍.. bahut khubsurat lectures....... as like as dr. afroz alam sir. shukriya( thanks ) so much for providing these lectures as well as notes.

[@md.mehedihasan8314]

MashALLAH sir. First of all, your teaching quality too much good and uses simple & easy word. This is a good support for me.

[@sufiyashama8877]

Sir apka bhot bhot shukriya.. Apki wajah se meku bhot ache se samaj aya

[@Yusuf-dx4hw]

Thank your for your labor Sir. Much appreciated. Greetings from Ankara,Turkey

[@ohgoditsjames94]

Excellent video, many thanks from the U.K.

[@SurajChaudhary-mp1uw]

Sir, your method of teaching is awesome..

[@YoungsProton]

Sir... great lecture.. Cleared all my doubts.. on symmetrical faults. I calculated rest of the math.. Anyone Correct me if I am wrong: Current supplied on LT side = Ifault X 100/11X (root 3)=20 KA By current divider Ig1= 11.803 A and Ig2=8.196 A.

[@DrAfrozAlam]

Thank you Asif Khan for the comment. Your calculations are almost correct. As per my calculation, Total Current supplied on LT side = - j 19.995 kA ≈ - j 20 kA. Ig1= - j 11.8003 kA and Ig2= - j 8.1947 kA.

[@DrAfrozAlam]

For more problem practices on "Symmetrical Fault Analysis", you may visit the following link: kzbin.info/www/bejne/b3TInpeZa9ZqhZI

[@sattamdutta1899]

@@DrAfrozAlam thank you sir....you are the real saviour

[@DrAfrozAlam]

@Sattam Dutta, You are most welcome dear

[@DrAfrozAlam]

Download Fault Analysis lecture notes (pdf) using the following link: drive.google.com/file/d/18Zvgdi3YD6iAIkWJwz5-s7dVHRgM6lwZ/view?usp=sharing

[@baijaltudu3002]

Sr. Your lecture is vety good & explain easy language.

[@asrakhursheed664]

May Allah bless you and give you gardens of heaven.

[@mjmontesinos1]

Sir, thank you very much for your videos. They have taught me a lot. much Better explained than professor at my university.

[@caDet07]

Guys ANSWERS ARE i (G1) = -j 11.800 K ampere i (G2) = -j 8.194 K ampere ( here K= 1000) Thank you sir ❤❤

[@komalyadav4051]

Very nice lecture sir.thank u so much

[@ahmedsaleem5586]

بارك الله فيك دكتور و جزاك الله كل خير على هذا المجهود الطيب حفظكم الله

[@DrAfrozAlam]

أمين ، شكراً لك يا أخي على الثناء والاهتمام بمحاضراتي. يرجى مشاركة هذه المحاضرات في مجموعتك.

[@ahmedsaleem5586]

@@DrAfrozAlam تم نشر محاضراتك على قنواتنا في برنامج التلكرام I share it in telegram app Dr 💚 In : t.me/Electricity_Channel And t.me/ib_eng97

[@shubhampuri8865]

Sir if possible could you deliver lecture of power system protection as I can't understand the relays perfectly especially mho relay... Your lectures are really helpful for competitions

[@fioricoziuc1792]

Good explanation! Thank you!

[@malakspeters6052]

hi Sir,,,thank you for your insightful tutorial videos....they helped me understand power systems...great teaching...

[@surendrakverma555]

Excellent lecture Sir. Thanks 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@munierhussain]

THANKS a lot sir, Your teaching quality is top class ❤

[@kashifrehman2060]

MashALLAH Sir, your lectures are helping me a lot in PSA Subject. which book you are following for these lectures???

[@DrAfrozAlam]

I m glad to know this..... Some times, I follow Kothari and Nagrath.....You can see Hadi Saadat also. BTW, I use to prepare my own lectures as per my convenience.

[@vindicatress_]

Thank you so much sir, you explained it so well🔥👏👏👏👏

[@surendrakverma555]

Very Good lecture Sir. Thanks

[@1973jdmc]

Thank you so much for these great lecturers- truly appreciated-

[@crackbanking]

These are lectures are really helpful.thank you sir.

[@DrAfrozAlam]

It's my pleasure

[@HARVINDERSINGH-lx9vy]

Your lectures are awesome ...Thankyou sir🥰

[@DrAfrozAlam]

Most welcome Harvinder Bajwa

[@neminathnarule2257]

A huge respect and hatts off u sir.. Really ur teaching is awesome👏🙏👌tq sir

[@DrAfrozAlam]

You are most welcome dear

[@abuanas8569]

Thank you Dr may Allah reward you greatly

[@mohammadalisina8670]

thank you very much for your nice videos. may Allah save you

[@stanleypete1807]

...this is just perfect

[@Haider_Waseem_445]

Mashallah Sri G thank you so much for such kind effort.

[@DrAfrozAlam]

Thank you Waseem for the comment.

[@shahabrar1814]

Shukriya janab for the wonderful lectures..👍. One more request to you kindly arrange the uploaded lecture in sequence.it will be helpful to us🙂

[@DrAfrozAlam]

Thank you for the comment. The uploaded lectures are already arranged in the following Playlist: kzbin.info/aero/PLEVP-S4VFKO9skYbAegYfSQNXNJajL3oD

[@Aspirant-lp8cw]

Great lecture sir.. Thank you.

[@monicaraju903]

Master class sir..please post more videos

[@sathwik__goud]

classic and neat explanation

[@DrAfrozAlam]

Thank you Sathwik

[@amaan-123]

Thank you sir!

[@newindia294]

Awesome lecture Thanks lot Sir

[@DrAfrozAlam]

Most welcome

[@amarnishant7464]

Maulvi and Mathematics... great... actual requirement...

[@KAFKUBA]

Why isn't line impedance converted to new p.u.??

[@swaroopapte3440]

Sir i just have one doubt, sir आपने पहले numerical के पहले एक प्वाइंट लिया था की "if some fault impedance is given, then how to calculate" करके। सर मेरा सवाल ये है, की वहा पे fault impedance क्यों आता है??

[@prajwalraut4695]

Really good explanation

[@DrAfrozAlam]

Thank you Prajwal

[@zabehullah1033]

Sir ! Plz make some lectures on power system protection

[@roshandahal8344]

hello sir thank you for this lecture

[@utsavrai7587]

Love the way you teach

[@DrAfrozAlam]

Thank you Pratap

[@MahadKhaliq]

Thank you so much Sir, it was so helpful!

[@almoraldeme8664]

Where did you get VL and why is S=100?

[@KAFKUBA]

Shouldn't 132 squared be divided by 100,000 since it's MVA?

[@itsabhilasa]

Sir, can you please make a video on pre fault loaded systems ?

[@pranaymeshram8888]

Thank you 😊😊

[@hossaintarik7904]

Mashallah very interesting and simple way to do fault analysis.. But Sir, would you please explain kindly the reason of calculating value of XG2 whereas the value already given as 10% like you put the value of Xg1. wish to get more practice materials.thanks.

[@AryanBKumar]

Even if u apply the formula in xg1 u get 0.15*(100/100)*(11/11)^2 soo he directly wrote it , hope this answer helps you sir 🙏🏻

[@amadelfarooq]

Asalamu alikum , please help sir in this Q. A 10KVA,400/200 V single phase transformer with 10% impedence draws a steady state short circuit current of ?

[@DrAfrozAlam]

Wa Alaikum Assalam. Use the same procedure explained in this video lecture. Isc(p.u.) = 1/0.1 = 10, Isc(base) = (10×1000)/200 = 50 A, Isc(actual) = Isc(p.u.)×Isc(base) = 10×50 A = 500 A (Answer). Also, in case of 3-phase transformer, Isc(p.u.) = 1/0.1 = 10, Isc(base) = (10×1000)/(√3×200) = 28.868 A, Isc(actual) = Isc(p.u.)×Isc(base) = 10×28.868 A= 288.68 A

[@MrOptimusPrime.]

The reason why education is boring without practical classes is the difference between theory and reality. Most engineering students do not know what is motor, transformer, transmission line, circuit breaker, current transformer even in their advanced studies. But they have to make all these calculations theoretically in their engineering studies only on their mind....... This works only when you have hands on experience on substations and power stations........Otherwise this session is just an asmr.

[@sajadkhan887]

very well explained

[@DrAfrozAlam]

Thank you Sajad

[@JkFilm965]

Hi sir, I understand that the fault current return to the generator through the earth if generator is earthed at the neutral. But if the generator is ungrounded Wye, how does the fault current return to the generator? Do we still calculate the fault current the same way? Really appreciate your help, thanks!

[@ermuhanmaikhanov8259]

Thank you sir for this lecture! Can you just clarify 1 point for me? When making pu system in your example. We assume 100 MVA as a Base. Then Gen1 is 1 pu, but shouldn't Gen2 be 0.5pu?

[@DrAfrozAlam]

Both the generators are operating at 11 kV, hence at 11 kV base, operating voltages in pu for Gen 1 and Gen 2 are shown as 1 pu.

[@Phoenix16422]

sir can you please explain again how to find out the current through G1 and G2... you were explaining at the end but I couldn't get it...Thankyou

[@DrAfrozAlam]

Total Fault Current supplied by LT side = - j 19.995 kA ≈ - j 20 kA. Now applying current division rule, we get, IG1= - j 11.8003 kA and IG2= - j 8.1947 kA.

[@HaiderAli-pp9go]

@@DrAfrozAlam Sir why are we considering the LT side? Really confused about this

[@DrAfrozAlam]

@ Haider Ali, If it has been asked in the problem, you have to calculate it.

[@HaiderAli-pp9go]

@@DrAfrozAlam I mean why is the current division used by taking LV current? Why can we use HV current we calculated to find the current supplied?

[@DrAfrozAlam]

In Fault analysis, we can evaluate Fault current at any point

[@pavanvenkatasai5767]

Thank you sir

[@mubarakali-cj5gy]

Sir at time 42:03 .100/root 3*line voltage on h.v side you get the value (-j437.4) but I get the value (j0.43738 )... When divided by 100/root 3*132=(j0.43738)....sir how you find the value of (-j437.4) ?

[@DrAfrozAlam]

As 'S' is in MVA, you need to calculate as, (100*1000)/root 3*132 = 437.4

[@pritchardmabutho8018]

Thank you Dr, your video helped alot. But you didn't finish the last part, What are the values for the actual currents supplied by the two generators?

[@DrAfrozAlam]

Please see the pinned comment

[@pritchardmabutho8018]

Thank you Dr. If you find time please make a video on symmetrical fault analysis with a Load connected.

[@dganesh9391]

Good explanation

[@DrAfrozAlam]

Thank you D Ganesh

[@ismailpinjar]

Sir I think base current @hv side is -j3.8095*(S/(√3V)^2)=728159

[@DrAfrozAlam]

I think you should watch the following lectures on p.u. Systems: Per Unit System (In Hindi): kzbin.info/aero/PLEVP-S4VFKO85zhnjJYg_ZCVh1_Wqpvqi

[@technicalzargar8138]

Assalam ali kum Sir S/√3 VL = 437 .. how......? Sir what we take S 100* 10^6 = 100 MVA or If we take 100*10^3 the looks 100 KVA

[@DrAfrozAlam]

Wa Alaikum Assalam dear. S/√3 VL = (100*10^6)/(√3*132*10^3) = 437

[@technicalzargar8138]

@@DrAfrozAlam ok thanku sir

[@DrAfrozAlam]

Most welcome

[@maheboobmula1166]

thanks chacha jan.

[@abhishekrajwanshi5265]

vaibhav kuril was here

[@adnanrafiq4507]

Couldn't understand a little portion how to find G1 and G2 current Kindly tell me how to find these current after finding If(actual) on L.V & H.V side

[@DrAfrozAlam]

Apply current division rule

[@atibali1087]

Sir, What will be the effect on fault current in the case of LLL or LLLG fault if neutral of synchronous generator is ungrounded??

[@DrAfrozAlam]

In such faults, negative and zero sequence components of fault current are absent. i.e. only positive sequence component of fault current exists which does not require path through neutral. Note: Only zero sequence component of current requires its path through the neutral. Recall, neutral current In = 3*Io

[@jaydipprajapati5763]

Nice video

[@DrAfrozAlam]

Thank you Jaydip

[@leesadik]

wonderful class sir👌 may i konw where r u from

[@DrAfrozAlam]

Thank you Sadik. I teach in AMU, Aligarh, India. Where are you from?

[@MANOJKUMAR-mb2uw]

Sir why we take base voltages different sir on hv and lv side Can we take single base voltage for both sides

[@DrAfrozAlam]

As we know that actual value of voltage at any point of the system is equal to per unit value multiplied by its base value. Hence, base value is changed whenever actual value of voltage is changed due to presence of a transformer.

[@KAFKUBA]

I don't understand the last step with thevenin simplification

[@theyab65]

jzak allah khair

[@sarvjeetprajapati7257]

Thank you so much sir you are great sir

[@DrAfrozAlam]

Most welcome dear

[@leesadik]

what happens if the two generators are having different magnitude of voltage

[@DrAfrozAlam]

The voltages of parallel operated generators are always kept same.

[@leesadik]

iam from Hyderabad sir iam a btech student at jntuh

[@leesadik]

oh yes sir right i just forgot thank you sir

[@transmissionlinetricks9760]

Assalamualikum respected sir kindly guide me about substation and transmission lines book. JazakAllah

[@darmavarapugovindarao8386]

Sir please make a vedio psa first chepter ( chapter name is per unit representation and topology )

[@DrAfrozAlam]

Per Unit System (In Hindi): kzbin.info/aero/PLEVP-S4VFKO85zhnjJYg_ZCVh1_Wqpvqi

[@darmavarapugovindarao8386]

Sir I want to English language psa lectures for the purpose of 3-2 semister examinations

[@mdnurulislamnahid5424]

Thanks sir

[@DrAfrozAlam]

My pleasure

[@kalyanreddy4820]

Sir why in symmetrical fault calculations shunt elements are neglected. Please clear my doubt sir.

[@DrAfrozAlam]

To make the calculations simpler for undergraduate level students

[@DrAfrozAlam]

This assumption doesn't make significant difference in the accuracy of the results

[@Gagandeepsingh-uf2un]

sir, what about topics like transients on transmission line, short circuit of synchronous machine ,selection of circuit breaker , sir have you covered them or not?

[@ranjeetmaurya7913]

Makwana sir suggested me for this lecture

[@DrAfrozAlam]

Yes, Dr. Makwana sir has informed me about this. Feel free to ask me in case of any difficulty.

[@ranjeetmaurya7913]

Thank you sir

[@shahbazalam9993]

Sir plz upload fault analysis in hindi language

[@asror94]

what formulas calculation for LLLG sir?

[@DrAfrozAlam]

kzbin.info/www/bejne/f2qbeHSOnMmriJY

[@sohailjanjua123]

Salam , how come 437.4 ? . Please explain me. Thanks

[@DrAfrozAlam]

Wa Alaikum Assalam, On HV side, I_base=(Base MVA)/(√3*Base kV) = (100*1000000))/(√3*132*1000) = 437.4 A

[@sohailjanjua123]

@@DrAfrozAlam Salam , Thanks

[@duttadrj]

Sir please explain source transformation theory

[@DrAfrozAlam]

If you have problem in understanding 'Source transformation', then alternatively you can use Millman's theorem which is used to compute the voltage of a circuit of parallel branches.

[@uknown9633]

Fault current is -j19994.6

[@Rashed_007]

Thanks..

[@shilpasweety641]

Srir will these lectures helpful for gate??

[@DrAfrozAlam]

Ofcourse, after this lecture, you may watch the following solved GATE questions on "Symmetrical Fault Analysis": kzbin.info/www/bejne/b3TInpeZa9ZqhZI kzbin.info/www/bejne/bpubc6d-qLpseNE

[@honarfarhad]

Sir ican i get a notebook of fault analysis

[@DrAfrozAlam]

You can download Fault Analysis lecture notes (pdf) using the following link: drive.google.com/file/d/18Zvgdi3YD6iAIkWJwz5-s7dVHRgM6lwZ/view?usp=sharing

[@honarfarhad]

@@DrAfrozAlam thanks a lot

[@sarvjeetprajapati7257]

Chapter wise playlists banaiye sir

[@DrAfrozAlam]

Various playlists have now been created.

[@gustavomarcelo7250]

Hi sir. Not clear on the source; how can we say it is 1pu?

[@DrAfrozAlam]

Source voltage will be taken as base voltage (Base kV). Hence, its per unit value will be 1 p.u.

[@gustavomarcelo7250]

@@DrAfrozAlam How do we say two parallel source equivalent to one source?

[@DrAfrozAlam]

@@gustavomarcelo7250 Using source transformation. First convert each parallel voltage sources into current sources, then convert the equivalent current source into voltage source.

[@electricalengineeringmat6827]

Thankyou sir

[@electricalengineeringmat6827]

Sir do you have whatsapp group

[@akashpq]

sir why we use Dy11 transformers at receiving end of the transmission line and Yd1 at sending end of it?

[@atulsain6170]

Yd is used for step down (root 3 time more stepping down then yy or dd for line voltage) and dy is used for step up (more step up).

[@mouhammedboudjemel650]

Peace, mercy and blessings of God be upon you. I am Mohamed from Algeria, a university student majoring in electrical networks. I have sent you a picture of a topic that I could not solve in your e-mail. If you can help me in the shortest time, thank God

[@DrAfrozAlam]

The language of the questions mailed by you, is not English. So, I am unable to read those questions.

[@mouhammedboudjemel650]

@@DrAfrozAlam شكرا استاذي

[@mouhammedboudjemel650]

Salamu alikum sir I want your address mail if you can لقد فهمت الدرس جيدا لكن عندي مسألة استعصت علي و اريد منك المساعدة ان امكن وشكرا

[@DrAfrozAlam]

Wa Alaikum Assalam, [e-mail]

[@mouhammedboudjemel650]

@@DrAfrozAlam 🤲👍

[@ijaharalam8024]

Can you speech in Hindi language? please!!!

[@DrAfrozAlam]

Per Unit System (In Hindi): kzbin.info/aero/PLEVP-S4VFKO85zhnjJYg_ZCVh1_Wqpvqi

[@DrAfrozAlam]

Bus Admittance Matrix (In Hindi): kzbin.info/aero/PLEVP-S4VFKO-BAGScDSifBQQLGXRPwjvb

[@DrAfrozAlam]

Gauss-Seidel Method of Load Flow (In Hindi): kzbin.info/aero/PLEVP-S4VFKO8MBMECe3UfdlIurue36pqa

[@KAFKUBA]

I don't buy the thevenin explanation

[@MajidKhan-kq7se]

Zhcet😍

[@DrAfrozAlam]

Yes, I teach in ZHCET, AMU, Aligarh

[@MOKRABachour]

بارك الله فيك دكتور و جزاك الله كل خير على هذا المجهود الطيب حفظكم الله

[@DrAfrozAlam]

شكرا جزيلا للتعليق. هل لي أن أعرف من أين أنت؟

[@nidhichandrakar5097]

Great explanation sir