Synthetic Division with a Quadratic Divisor

This video shows an example of how to use synthetic division when the denominator or divisor is a quadratic function. It might me easier to use long division for this process, but if you are required to use synthetic division, hopefully this video will help you.
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[@rocks813]

Wow, this is new to me! Lucky KZbin recommended this video, thank you for the new knowledge

[@mrcrash4107]

Very informative, thanks for all the work

[@xtremegamemaker]

Thank you. I was looking for this... Just one question, please tell me what changes I'd have to make for a non monic quadratic. Also will it help if i factorise the quadratic first and then repeatedly divide.

[@christmastunip4913]

Math and Stats Help, can you make a video about the addition & subtraction of Integers? Thank you!!!

[@holyshit922]

It is useful for Bairstow's method Write it in a loop

[@kreshnaapriiyaa4857]

Very nice explanation 😁😁😀

[@MathandStatsHelp]

Thank you

[@user-uz6we7hv7b]

how to divide when the power of X in divisor is greater than the dividend?

[@MrMask-zt9uo]

Why is there x in the remainder 2x? I got the rest but that one..

[@robonthecob5092]

The table from left to right goes down in degree, so the second to last one will be of degree 1

[@MathandStatsHelp]

If you were to do long division, you would probably be able to see the remainder better. Basically what happens is that you have a remainder in both the linear and constant terms.

[@eduwithsh9991]

what if the divisor is x^2 - 2x -1

[@MathandStatsHelp]

You would put the opposite sign on the outside for the linear and constant term. 2 and 1 would be used.

[@mrlarrydapuppet4337]

This doesn't work it's not a monic quadratic right? How would you do this if the x^2 coefficient was something other than one?

[@johngambino5105]

She explained that you would need to divide all coefficients by the leading coefficients

[@mrlarrydapuppet4337]

@@johngambino5105 Damn I must have been really tired when I made this comment XD, thanks for replying anyway

[@uttkarsh2092]

not sure but i would guess if the equation is like ax^2 + bx +c then u can write it was a(x^2+b/a*x+c/a) and do it then