REAL SQL Interview PROBLEM by Capgemini | Solving SQL Queries

In this video, I solve a REAL SQL Interview PROBLEM asked by Capgemini. This problem was shared with me by someone who took this interview.
Upcoming Data Science Bootcamp on OdinSchool:
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In this problem, we are given information about Lifts and Passengers. We need to come up with the final list of passengers allowed to enter the lift based on the maximum capacity of the lift.
THANK YOU for watching!

[@sonalirajput417]

I am an Odin student. No placement support nothing. It's been 3 months since I completed the course. Not a single vacancy I got in placement assistance. Anyway you are the best teacher after completing the course still clearing doubts from your videos.

[@Sami34152]

This is called real facts 😂😂😂

[@grvdjkg]

people from iit, even after completing full time course are not getting placed. Doing these online course will not help. There was a time in the past when these quick certifications would work, but right now its not possible

[@DivineDiction_]

Which Batch DS3A😄

[@agarwalaarzoo3738]

What they r telling regarding job assistance?

[@snakesa1]

Hi can we connect? I'm also from odinschool

[@Khader_views]

Thoufiq you are the real mentor good teacher waiting for more videos and live advance SQL classes.😊

[@shubhampalde8030]

Glad to see you back again sir 😌

[@bushmaster75]

Excellent Tutorial. Clear, concise and very useful ....

[@emmanueltondikatti8754]

Well explained! Intuitive and to the point

[@shekhark1139]

Thanks ! You are back with new challenge , Thank you for the video, everytime I learn something new or different aporoach solving queries, thank you very much.

[@malcorub]

For my fellow Americans Lift = Elevator. 😀 Welcome back Thoufiq!!!

[@aspa18]

Could you please do a video where you explain the select statement or maybe the aggregates with group by and having ? Thank you for your work 🙏🏼

[@oluseyeoyeyemisunday4890]

I miss your videos. Thank you for this one.

[@GamerShaggy]

create table lifts ( id int , capacity_kg int ); insert into lifts values (1, 300); insert into lifts values (2, 350); create table lift_passengers ( passenger_name varchar(50) , weight_kg int , lift_id int ); insert into lift_passengers values ('Rahul', 85, 1); insert into lift_passengers values ('Adarsh', 73, 1); insert into lift_passengers values ('Riti', 95, 1); insert into lift_passengers values ('Dheeraj', 80, 1); insert into lift_passengers values ('Vimal', 83, 2); insert into lift_passengers values ('Neha', 77, 2); insert into lift_passengers values ('Priti', 73, 2); insert into lift_passengers values ('Himanshi', 85, 2);

[@bankimdas9517]

Thanks for providing script. This will definitely help most of us

[@devendrabarasker4987]

thank you for script

[@2424rara]

Thoughtful and much needed

[@pragatiaggarwal8103]

Thank you so much :)

[@riasingh11]

You're an angel

[@1112electronics]

Thanks for the great video 🎉

[@jagadeeswarareddy_sathi]

Thanks for the video ❤

[@bankimdas9517]

Welcome back sir

[@techTFQ]

Thank you :)

[@GurleenKaur-eg7bh]

Explanation is awesome 💯

[@apppu1k221]

for mysql - with cte as ( select * , SUM(weight_kg) OVER (partition by lift_id order by weight_kg) as running_weight from lift_passengers lp JOIN lifts ON lift_id = id) select lift_id, group_concat(passenger_name) as passengers from cte where running_weight

[@bienfaitnkurunziza6941]

Thank you bro👌

[@atifsuhail7803]

Ms sql: with cte as( select p.* ,l.weight, case when sum(weight_kg) over(partition by p.lift_id order by weight_kg) < l.weight then 1 else 0 end flag from passengers p inner join lift l on l.lift_id=p.lift_id) select lift_id, string_agg(passengername , ',') name from cte where flag=1 group by lift_id order by lift_id;

[@rohithb65]

with cte as (select * , sum(weight_kg) over(partition by lift_id order by weight_kg) runing from lift_passengers) select c.lift_id,group_concat(c.passenger_name) as passenger from cte as c join lifts as l on c.lift_id = l.id and l.capacity_kg >= c.runing group by c.lift_id

[@Muchatla_rani3040]

Hi Thoufiq , I have been following your channel from past 1.5years it was helped me lot for sql and absolutely you are doing a great job .we all knew how much effort you are putting to create this series for sql and please try to create the same series for python also.Thank you so much for your hardwork☺️.

[@techTFQ]

Thanks Anusha .. appreciate your kind words.. I’ll think about your suggestions 👍

[@gideon6319]

Welcome back Touafiq

[@techTFQ]

Thank you :)

[@RashmiBiradar-vr2cs]

Below method is using CTE and this works in Oracle SQL: with new_table as (select lp.*, sum(weight_kg) over (partition by lift_id order by weight_kg asc) as sum_weight from lift_passengers lp) select l.id, LISTAGG(nt.PASSENGERS_NAME, ',') from lift l inner join new_table nt on nt.sum_weight < l.CAPACITY_KG and nt.lift_id =l.id group by l.id

[@debpatro]

How to retrieve all sets of lift passengers combinations for two sets of given lifts weight? It's an extension to the question??

[@rajeevyadav1637]

Let's begin

[@ThePinanknagda]

Hey Toufiq, if we dont want to use the string_agg function, what other method can we use? My first thought came to use recurssive

[@swethathiruppathy9973]

Hi Sir, Thank you for your videos hereby sharing my solution with cte as ( select *,sum(weight_kg) over(partition by lift_id order by weight_kg) as running_weight from lift_passengers P join lifts L on p.lift_id =l.id ) select lift_id ,STRING_AGG(Passenger_name,',') as list_passenger from cte where running_weight

[@sivakumarisadineni3193]

Hi sir, Could you update if you are working on any sql course like you mentioned in your previous servey? I have been waiting on update since that post

[@user-uc9wp8mx3j]

with cte as (select *, sum(weight_kg) over (partition by lift_id order by weight_kg) as sum_weights from lift_passengers) ,cte2 as ( select c.passenger_name, l.id, case when c.sum_weights - l.capacity_kg

[@Madhuripalug]

Hi can you explain about the cursor

[@balavijayakumar1300]

Good job

[@anuraghaldar128]

RITI as a girl is offended to be 95 KG 😂 , just kidding well explained sir , want more problems like this

[@DiwakarLearn]

Is this String_agg function will work on all the environments

[@akhilsingh5251]

with cte1 as ( select *, sum(weight_kg) over(partition by lift_id order by weight_kg) as running_sum from lift_passengers lp inner join lift l on lp.lift_id = l.id), cte2 as (select *, case when capacity_kg>= running_sum then 1 else 0 end as runn_sum from cte1) select id , STRING_AGG(passenger_name, ',') as total_pass from cte2 group by id

[@avijayreddy3401]

Thanks for the Beautiful SQL question. Here is my Solution to the Problem. WITH CTE as ( select p.*,l.*,SUM(weight_kg) OVER (Partition By id ORDER BY weight_kg) as Cumulative_Sum from lift_passengers p LEFT JOIN lift l ON p.lift_id = l.id) SELECT string_agg(passenger_name,',') as Passenger_Name from ( SELECT *,CASE WHEN Cumulative_Sum

[@abhishekn2048]

I am a beginner but in know thw concepts but i am not able to implement plz help me

[@selvitw7404]

Can any one help me on which SQL, this problem is solved, because i tried with Oracle Sql not able to solve it.

[@saib7231]

same question in meesho also asked

[@oluseyeoyeyemisunday4890]

drop table if exists lift; create table lift( id int, capacity_kg int ); drop table if exists lift_passengers; create table lift_passengers( passenger_name varchar(50), weight_kg int, lift_id int ); insert into lift values (1,300); insert into lift values (2,350); insert into lift_passengers values ('Rahul',85,1); insert into lift_passengers values ('Adarsh',73,1); insert into lift_passengers values ('Riti',95,1); insert into lift_passengers values ('Dheeraj',80,1); insert into lift_passengers values ('Vimal',83,2); insert into lift_passengers values ('Neha',77,2); insert into lift_passengers values ('Priti',73,2); insert into lift_passengers values ('Himanshi',85,2); select * from lift; select * from lift_passengers;

[@ajaysubramaniam4453]

for the sum aggregate function , inside over() with order by clause gives running total without order by clause gives total sum within the window why it is so???

[@varunas9784]

Hi there, if you haven't found the answer yet, here's an explanation, All window functions have a default frame clause 'RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW' if not specified explicitly. So, when you write a window clause for Sum without an 'order by ' i.e.: Sum(weight_kg) over (partition by lift_id) , the SQL server, by default considers the ORDER BY clause to be ordered by "lift_id" and the frame clause to be 'RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW' therefore, the sum function operates in a window where weight is calculated for lift_id and also orders for lift_id automatically (since you didn't specify it explicitly). NOTE: 'Window/ frame clause, i.e., RANGE BETWEEN UNBOUNDED...' doesn't have any effect here, it only comes into play when order by column has repeated values and if you are in need to tell apart such rows of that column

[@vishnureddy1491]

with cte as( select *,sum(weight_kg) over(partition by id order by weight_kg) as cum_sum,if(capacity_kg>=sum(weight_kg) over(partition by id order by weight_kg),1,0)as flag from lift2 as e join lift_passengers2 as f on e.id=f.lift_id) select lift_id,string_agg(passengers_name,',') from cte where flag=1 group by lift_id; string_aggregate is not working th sql workbench , can we use any alternative other than string_agg() function?

[@srikanthkalluri318]

in MYSQL group_concat with group by

[@43_jaymohitepatil47]

can we solve this problem without using window function

[@anduamlaktadesse9284]

My solution using SQL Server: with main as ( select lp.lift_id, l.capacity_kg, lp.passenger_name, weight_kg, sum(weight_kg) over(partition by lp.lift_id order by weight_kg range between unbounded preceding and current row ) as Total_Kg from lifts l inner join lift_passengers lp on l.id=lp.lift_id ), Overlift_Capacity_check as ( select * , case when Total_Kg < capacity_kg then 1 else 0 end as Overlift_Flag from main) select lift_id,STRING_AGG(passenger_name,',') as passengers from Overlift_Capacity_check where Overlift_Flag 0 group by lift_id;

[@Kirankumar-ml1ro]

with cte as ( select lp.passenger_name, lp.weight_kg, sum(weight_kg) over (partition by lift_id order by weight_kg) as cumu_sum,l.capacity_kg,lp.lift_id from lift_passengers lp join lifts l on l.id=lp.lift_id ) select lift_id,string_agg(passenger_name,' , ') from cte where cumu_sum

[@chethan4160]

with paa as( select *, sum(weight_kg) over(partition by id order by id, weight_kg) runing_total from lift_passengers join lift on id=lift_id ), stg AS(select * from PAA where capacity_kg>=runing_total) select LIFT_ID, STRING_AGG(passenger_name, ',') from stg GROUP BY LIFT_ID

[@MsNizamkhan]

Thanks Toufik, However You considered only one combination but There could be multiple combination from lift 1 of those having sum of weight

[@FaisalAli-ps7th]

+1 A solution with output as you mentioned would go better with the requirement of the question.

[@unnamamarkrishna827]

Nice one

[@techTFQ]

Thanks 🔥

[@ujwalkumar4750]

I would suggest you layoff is going in IT so wait atleast 3 month wherever you r

[@shabbiransari7584]

Why do not you teach PL\SQL?

[@Ggghhddd]

when i using my phone and iam sleeping ,iam struggled a lot in my area they are create sleeping and they are too much struggle for me and my son.

[@shresthaupadhyay5739]

this question is there in the Ankit bansal's 100 sql question course

[@viveks288]

Hi sir , instead of using string_agg shall we use listag is that possible

[@manikandanbalasubramanian6668]

I too thinking the same

[@anchal7876]

with cte as (select lift_id,passenger_name,weight_kg,sum(weight_kg) over(partition by lift_id order by weight_kg) as cc, capacity_kg from lift_passengers join lifts on lift_passengers.lift_id=lifts.id ), cte2 as(select *,case when cc>capacity_kg then 'n' else 'y' end as 'ff' from cte ) select lift_id,string_agg(passenger_name,', ') as passengers from cte2 where ff'n' group by lift_id

[@gouthamstar6558]

with cte as ( select l.*,lp.*, sum(lp.WeightKG) over(partition by l.id order by l.id,lp.WeightKG) as w from LiftPassengers lp left join Lift l on lp.LiftID =l.ID ) select ID, STRING_AGG(PassengerName, ' , ') as passengers from cte where w< CapacityKG group by id

[@sapnasaini851]

dataset ?

[@sandhanamurali444]

Hi I want to learn your bootcamp SQL can share the details please

[@chinmayjoshi5770]

For what designation and experience level was this for?

[@gawlianilnrayan]

just for info.... ORDER BY can't use in CTE statement... correct me if i am wrong

[@malcorub]

Within Post Gre SQL yes, but not SQL Server. But your also ordering it within the SUM(weight_kg) window function so you should be good either way.

[@shubhamgupta2246]

for MySql with cte as (select * , sum(weight_kg) over(partition by id order by id,weight_kg) as cummulative_sum, case when capacity_kg>= sum(weight_kg) over(partition by id order by id,weight_kg) then 1 else 0 end as flag from lifts join lift_passengers on id=lift_id order by id,weight_kg) SELECT lift_id, GROUP_CONCAT(passenger_name ORDER BY passenger_name SEPARATOR ', ') AS passenger from cte where flag=1 group by lift_id;

[@Satish_____Sharma]

Here is mysolution using MYSQL with cte as (select lp.passenger_name,lp.lift_id,sum(lp.weight_kg) over (partition by lp.lift_id order by lp.weight_kg) as wt,l.capacity_kg from lift_passengers lp left join lifts l on lp.lift_id=l.id) select lift_id,group_concat(passenger_name) as passenger_name from cte where wt

[@m.s.k5300]

Capegemini interview very simple I have attended three times cleared three times as well

[@srivishwa9189]

For which role?

[@sueyourself5413]

Ouais, on te croit pas gros, sa sent la merde.

[@premakolia]

how would you estimate the level of this task? (beginner, intermediate etc). thanks

Intermediate

[@prasadmekala258]

How many experience he had on this sql

[@shivanitiwari8349]

with cte as (select*, count(*) as sums from Trips join Users on client_id = users_id where banned = 'No' group by request_at) select cte.request_at 'Day', round(count(id)/cte.sums, 2) 'Cancellation Rate' from cte where cte.status in ('cancelled_by_driver', 'cancelled_by_client') group by request_at; Can someone please find the error in this code I am getting runtime error saying "FROM keyword not found where expected"

[@DEwithDhairy]

Pyspark Version of this problem : kzbin.info/www/bejne/Zp-aknqEi6iniMUsi=hnpqw1o3yiNLUWi2

[@shivaprasad-kn3kw]

here is my solution with CTE as ( select name, weight , liftid, capacity from lift_passengers a join lifts b on a.liftid = b.id) ,CTE2 as ( select name, weight, liftid, capacity, sum(weight) over(partition by liftid order by weight) cumm_weight from CTE) select liftid, string_agg(name, ',') as passengers from CTE2 where cumm_weight

[@mrbartuss1]

Good to know you still remember your YT password!

[@techTFQ]

yeah, I am glad too :D

[@dhrupadsaha4171]

justice for Riti 😢

[@Abc22333]

😂

[@saadabdulghani7390]

Hi taufiq, I didn't get your solution. I'm little confused. Our task was to find the list of passengers who can be accomodated in lift without exceeding lift capacity, right? So, Shouldn't there be all the possible combinations for each lift 1 & 2, for e.g. for lift 1: { rahul, adarsh, riti},{rahul, adarsh,dheeraj},{adarsh, riti, dheeraj},{ rahul, riti, dheeraj} like that but in increasing order of weight?? Please clarify me. Thanks

[@blse2000]

Exactly, I resonate you. Just asking this question here (out of curiosity) that, If we have to get all the possible combinations, Is it possible to achieve just by SQL alone? or should we be using any programming language like Python/Java etc? Please can anyone respond from this forum...

[@Nnirvana]

+1

[@rajathratnakaran7893]

Exactly my thought as well when i first read the question. But then why would they give lift id against the passengers. I guess we will need to accommodate Riti (in this case) on a separate row, with lift id 1, which will make more sense (Unlike the sample output).

[@gowri-uk1wd]

with cte as (select *, sum(weight) over(partition by liftid order by weight) as r from lift_pas) select cte.liftid, string_agg(cte.name,',') as pas from cte join lift l on cte.liftid = l.id and cte.r

[@pradeepvadlakonda007]

select lift_id,group_concat(passengername) from (select l.id as lift_id,l.capacity_kg,lp.lift_if,lp.passenger_name as passengername,lp.weight_kg, sum(lp.weight_kg) over(partition by lp.lift_if order by lp.weight_kg asc) as total_weight, case when l.capacity_kg>sum(lp.weight_kg) over(partition by lp.lift_if order by lp.weight_kg asc) then 1 else 0 end as wight_req from lift l join lift_passengers lp on l.id=lp.lift_if) as x where wight_req=1 group by 1;

[@PrayasPikalmunde]

Justice for riti 😮

[@narendrashekhavat]

I am bit late to post answer but enjoy your problems. i didn't still watch full but here it is my answer: with cte_1 as ( Select * from ( Select Name,ID,capacity,total, flag_sum,case when flag_sum>capacity then 'N' else 'Y' end as flag from( Select Name,ID,capacity,total,sum(total) over (partition by id,capacity order by total) as flag_sum from ( Select Name,ID,capacity,weight as total from Lift_passenger join lift on lift_id=id ) A)B)C where Flag'N') --Select ID,Name from cte_1; Select distinct A.ID,STUFF((Select distinct ', '+B.Name from CTE_1 B where A.id=B.id for XML path (''),TYPE ).value('.', 'NVARCHAR(MAX)'),1,2,'') Passenger from CTE_1 A Happy Learning☺

[@ashurathi9286]

Arey ye zindaa hain

[@Munna_007]

Bhai Jan Hindi mein kyon Nahin content banate ho Hindi mein

[@NabeelKhan-um1zk]

create table details as (with a as (select * , row_number() over(partition by lift_id order by weight asc) as ranks from passenger) select * , sum(weight) over(partition by lift_id order by ranks) as running_weight from a ); select * from details; with a as ( select passenger_name , lift_id from detailsss where running_weight

[@ArghyadeepPal92]

My solution :- 1)On ms sql server with t1 as (select li.id, sum(weight_kg)over(partition by lift_id order by weight_kg) as cum_sum,passenger_name,li.capacity_kg from lift_passengers as lp join lifts as li on lp.lift_id=li.id) select id, STRING_AGG(passenger_name,',') as passengers from t1 where cum_sum

[@chaitusai7674]

select lp.passenger_name+',', lp.lift_id from lift_passengers lp join lift l on lp.lift_id=l.id where sum(weight_kg)

[@iamkiri_]

My Solution with cte as ( select lp.*, l.capacity_kg , sum(weight_kg) over(partition by lift_id order by weight_kg) as rollsum from lift_passengers lp left join lifts l on lp.lift_id = l.id ) select lift_id , string_agg(passenger_name, ',') from cte where capacity_kg >= rollsum group by lift_id ;

[@user-dw4zx2rn9v]

MySql Solution: with cte as ( select passenger_name, weight_kg, lift_id, capacity_kg, sum(weight_kg) over (partition by lift_id rows between unbounded preceding and current row) as cum_sum from lift_passengers as lp inner join lifts as l on l.id = lp.lift_id ) ,cte2 as ( select * from cte where cum_sum < capacity_kg ) select lift_id, group_concat(passenger_name) as passengers from cte2 group by lift_id

[@Harish0402]

with cte as( select lift_id,passenger_name from (select lift_id,capacity_kg, passenger_name,sum(weight_kg) over( partition by lift_id order by weight_kg)r from lift_passengeres inner join lift on id=lift_id) where r

[@gnaneshwarg8552]

with cte_running_weight as ( select *, sum(weight_kg) over(partition by lift_id order by weight_kg) as cumulative_weight from lift_passengers lp ) select lift_id, string_agg(passenger_name,', ' order by weight_kg) as passengers from cte_running_weight cte join lifts l on l.id = cte.lift_id and l.capacity_kg>=cumulative_weight group by lift_id;

[@devg7929]

select id, group_concat(name) from ( select *, sum(wt) over(partition by id order by wt) sop from ( select lp.name, lp.wt, l.id, l.capacity from lift_passengers lp inner join lift l on l.id = lp.lift_id )a)b where sop < capacity group by 1 for mysql

[@office4321]

passenger p on l.id = p.lift_id isnt? May I know why he didn't mentioned their l. p.but still it worked?

[@Nnirvana]

It works fine unless there's any ambiguity in the column names. Since they're different, it's okay not to mention the table names.

[@office4321]

@@Nnirvana Eye opener, where do I get to know these minor quirks?

[@Nnirvana]

@@office4321 I'm not aware of any particular resource, I think it comes with experience. I remember myself too getting amazed at some things which were new to me.

[@ishashaw2561]

My Solution: with cte as (select l.PASSENGER_NAME, l.WEIGHT_KG, sum(WEIGHT_KG) over(partition by l.lift_id ORDER BY l.PASSENGER_NAME rows between unbounded preceding and current row) as cur_wt_on_lift, l2.id, l2.CAPACITY_KG from lift_passengers l join lifts l2 on l.LIFT_ID = l2.id), cte2 as(select id, PASSENGER_NAME from cte where CAPACITY_KG >= CUR_WT_ON_LIFT) select id, listagg(PASSENGER_NAME, ',') as PASSENGER_NAME from cte2 group by id

[@KIYASUDEENJAMALM]

WITH tab AS( SELECT id, passenger_name, capacity_kg, SUM(weight_kg) OVER(PARTITION BY lift_id ORDER BY weight_kg ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS tot FROM lift_passengers T JOIN lifts L ON T.lift_id = L.id), cte_2 AS( SELECT * FROM ( SELECT id, CASE WHEN tot< capacity_kg THEN passenger_name ELSE NULL END AS passenger_name FROM tab) AS X WHERE passenger_name IS NOT NULL) SELECT id, group_concat(passenger_name) AS passenger_name FROM cte_2 GROUP BY id;

[@falahanwarkhan8223]

With CTE AS (SELECT B.lift_id,B.passenger_name,B.weight_kg, Sum(B.weight_kg)over(partition by A.id order by B.lift_id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) as RN from lifts A left Join lift_passengers B on A.id = B.lift_id), CTE2 as (Select lift_id, (case when RN < 300 and lift_id = 1 then passenger_name WHEN RN < 350 and lift_id = 2 then passenger_name else NULL END) as RT2 from CTE) SELECT lift_id, String_agg(RT2, ',') as logo from CTE2 group by lift_id;

[@Mathematica1729]

Soln in MYSQL:- SELECT LIFT_ID , group_concat(PASSENGER_NAME SEPARATOR ' , ') AS PASSENGERS FROM (SELECT *, SUM(WEIGHT_KG) OVER (partition by LIFT_ID order by WEIGHT_KG ) as r_sum FROM lift_passengers p JOIN lift l on p.LIFT_ID = l.id)h where r_sum < capacity GROUP BY LIFT_ID;

[@rajansingh-fw3lp]

with cte as ( select id, lift_id, passenger_name,capacity_kg, weight_kg,sum(weight_kg) over(partition by id order by id, weight_kg rows between unbounded preceding and current row) as cum_sum from lift_tst L join lift_passengers_tst P on l.id=p.lift_id order by id, weight_kg) select lift_id,listagg(passenger_name,',') as passengers from cte where cum_sum

[@aarizkhan9471]

Sir i want to talk to you send me your contact. regarding sql queries and sql concepts

[@prakritigupta3477]

with cte as (select e.passenger_name, e.weight_kg,e.lift_id,w.capacity_kg from lift_passengers as e join lift as w on e.lift_id=w.id order by lift_id asc), cte2 as( select passenger_name, weight_kg,lift_id, sum(weight_kg) over(partition by lift_id order by lift_id desc) as total_weight, capacity_kg, row_number() over(partition by lift_id order by weight_kg desc) as max_rn, case when sum(weight_kg) over(partition by lift_id order by lift_id desc)>capacity_kg and row_number() over(partition by lift_id order by weight_kg desc)=1 then 0 else 1 end as flag from cte group by passenger_name, weight_kg,lift_id, capacity_kg) --select*from cte2 select lift_id, string_agg(passenger_name,', ') as final_names from cte2 where flag0 group by lift_id

[@shivsharma9153]

with new as (select passenger_name, weight_kg, lift_id, capacity_kg, row_number() over(partition by lift_id order by weight_kg) as rown, sum(weight_kg) over(partition by lift_id order by weight_kg) cumsum from lift_passengers lp join lifts l on l.id = lp.lift_id) select lift_id, group_concat(passenger_name order by rown SEPARATOR ', ') as passenger_name from new where capacity_kg > cumsum group by lift_id

[@harshitsalecha221]

WITH cte1 AS (SELECT passenger_name, sum(weight_kg) OVER(PARTITION BY lift_id ORDER BY weight_kg) as cum_sum,lift_id FROM lift_passengers as lp) SELECT lift_id, group_concat(passenger_name) FROM cte1 as c INNER JOIN lifts as l ON c.lift_id=l.id WHERE cum_sum

[@bodybuildingmotivation5438]

with cte as ( select *,sum(weight_kg) over (partition by lift_id order by weight_kg) chk from lift_passengers a left join lifts b on a.lift_id=b.id) select id,STRING_AGG(passenger_name,',') as Outputs from cte where chk