5.15 Perfect Number in Java

In this video we will check whether a number is perfect number or not. A perfect number is a positive integer that is equal to the sum of its proper positive divisors excluding itself. The first perfect number is 6, because 6=1 + 2 + 3.
A perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisors excluding the number itself .
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[@caribbeanman3379]

It is good practice to always use { } with your *if*, *for* and other block statements - even if the statement is just one line. Why? If you fail to enclose a single line block statement with { }, you may later add a second line to the block statement and forget to add the { } (in which case you wouldn't actually be adding a new line to the block statement even though you might think you are). This will introduce a logic error that is extremely difficult to find since no errors will be thrown by the compiler.

[@SmartProgramming]

thats new for me, thanks for this program sir 👍👍

[@kavyavadla3322]

i think its can be possible with while loop { int i,n,sum=0; while (i

[@jamunasuresh8352]

Can you please explain the program for the following question: Write a program to accept 'n' numbers and stop if the user enters multiple of 7.

[@prathammishra4480]

Uncle why is your voice to some extent like a robot ???

[@yezralama2507]

hello sir .This syntax is not working in eclipse. there is no link between int n in two methods. So can you help me.

[@yugalsingh154]

facing the same issue.

[@vampiriclion1176]

You can also return n == sum, without using if statement

[@sanisan5787]

Sir if we can take i

[@sathishakula6998]

Every number is a factor of itself. So if we take like that then sum will be more than the entered number .Then we won't get any number as perfect number.

[@abhishekvenkataraman4908]

this is for 3 digit right? if the input is not known what should we do?.Like ahould we import scanner and then like reversin Can anyone explain me

[@souvikroy3740]

package project4; import java.util.Scanner; public class proj4 { public static void main(String[] arg){ /* PERFECT NUMBER*/ Scanner sc1 = new Scanner(System.in); System.out.println("Enter your number"); int x1 = sc1.nextInt(); int sum=0; for(int i=1;i

[@sagarsahu2555]

Sir plz make a video for Happy number in java with code

[@ndawallah782]

Very very thanks

[@NishaMeenachocolover]

Hi How can we use scanner in the same program to get input from user. Thanks in Advance

[@medhabobbili5018]

We should use import java.util.Scanner function and write class scanner with object and call it.

[@parasarora2606]

scanner is predefined class in java.To use this u make a obj for this class eg-> scanner obj =new scanner(System.in); int x=obj.nextInt(); //for integer

[@user-pc2kx7kv1y]

import java.util.*; public class Perfect { public static void main(String[] args)throws Exception { int sum=0; Scanner sc=new Scanner(System.in); System.out.println("ENTER ANY NUMBER"); int n = sc.nextInt(); for(int i=1;i

[@jibanjyotijena9070]

Sir.... Actually I didn't get you.plz elaborate , what are those function and argument .why we follow this process instead of normal procedure

[@dannyg8682]

I am not sure what you mean by normal procedure, but he is just showing you how to think in a way that will help you when you are actually trying to find solutions while writing a program. The Prime number method he used is simple but looks complicated and he didn't explain what he was doing very well. First he gives n a value, say 28 and then he runs the program which divides 28 by i checking the remainder for 0, and i is increasing on every loop 1, then 2, then 3 until it gets to 28 and stops. it puts all the numbers that had no remainders in the sum variable adding them up to see if the factors add up to be the same number he originally put in. If the remainder was not 0 that number does not go into the sum variable. for 28 the sum variable got 1+2+4+7+14 because all those numbers have a remainder of 0. If he used six he would get 1+2+3 in the sum variable because all those numbers have a remainder of zero. And if you were to use the number 10, it would put 1+2+5 in the sum and that does not equal ten so 10 is not a perfect number but 28 and 6 are perfect numbers

[@bhaveshaudichya]

if i want print all factors also what should i do

[@sunilreddy9297]

Inside If block, Print 'i' value, It will give u all the factors of the number

[@bhaveshaudichya]

thanku

[@evanexcel7148]

import java.util.Scanner; public class Main { public static void main(String[] args) { System.out.println("Enter the number to check if it is perfect"); Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int sum =0; for(int i =1;i

[@prathammishra4480]

@@sunilreddy9297 Are you his brother ????

[@jasonbhatnagar7134]

Does anyone know how to write a program like this except it only shows the perfect numbers up to number entered? So if I entered 1, no perfect number would show. If I then entered 100, 6 and 28 would show. If 1000, then 6, 28, and 496 would show. If 10000, then those three and 8128 would show. Also, the program should show the factors of each perfect number in the ouput.

[@user-pc2kx7kv1y]

Jason Bhatnagar import java.util.*; public class Perfect { public static void main(String[] args)throws Exception { int sum=0; Scanner sc=new Scanner(System.in); System.out.println("ENTER ANY NUMBER"); int n = sc.nextInt(); for(int i=1;i

[@sanathboddhula4599]

code isn't working

[@Anilkumar-ec8sj]

/*Wrote a simple program */ public class PerfectNumber { public static void main(String[] args) { int n =22; int temp; int sum=0; temp = n; for(int i = 1; i

[@vemurisaikrishna9079]

/* * To change this template, choose Tools | Templates * and open the template in the editor. */ package myproj; import java.util.Scanner; /** * * @author Vemuri Sai Krishna */ public class perfectnum { public static void main(String[] args){ int i,s=0,n; System.out.println("enter a number"); Scanner in = new Scanner(System.in); n = in.nextInt(); for(i=1;i

[@thespiritualjourney369]

your every programs are soooo complicated when they CAN be so easy.

[@RS-ux5zu]

how to find a logic ?

[@shuvshaw9594]

int x=6, sum=0; for(int i=1; i

[@varunshandilya7456]

why i am getting output always as it is not perfect number...my code is same public class PerfectNumber { public static void main(String[] args) { int n=6; boolean b=isperfect(n); if(b) { System.out.println("perfect"); } else { System.out.println("not"); } } public static boolean isperfect(int n) { int sum=0; for(int i=1;i

[@harisharma8500]

Just type n in place of n/2 in for loop.

[@varunshandilya7456]

@@harisharma8500 thanks...bro

[@nithyashreenaidu8357]

you have to put

[@anjalidubey6972]

5. Write a Java program to check whether a number is an Q5 Number(changed the original name) or not. In recreational mathematics, a Q5 number in a given number base, is an integer that is divisible by the sum of its digits when written in that base. Can u please solve this i can't get the question 😟😟

[@vignesh4062]

import java.util.*; class Main { public static void main(String args[]) { Scanner sc = new Scanner(System.in); System.out.print("Enter a number : "); int n = sc.nextInt(); int x = n, d, sum = 0; //finding sum of digits while(x>0) { d = x%10; sum = sum + d; X = x/10; } if(n%sum == 0) System.out.println(n+" is a Q5 number."); else System.out.println(n+" is not a Q5 number"); } }

[@user-pc2kx7kv1y]

package com.example; import java.util.*; public class Perfect { public static void main(String[] args)throws Exception { int sum=0; Scanner sc=new Scanner(System.in); System.out.println("ENTER ANY NUMBER"); int n = sc.nextInt(); for(int i=1;i

[@venkateswarluguntaka7370]

❤

[@charanguggulla6899]

class Perfect{ public static void main(String charan[]){ int i,j,k,sum=0; i=28; j=i; while(0!=j--){ if(j==0)break; if(i%j==0){ sum=sum+j; } } if(i==sum){System.out.println("it is perfectnumber");} else System.out.println("it is NOT perfectnumber"); }}

[@anjelaryal6249]

/* As I dont know much about method, I wrote a simple one*/ public class KZbin { public static void main(String [] args){ int n = 28; int sum = 0; for(int i = 1;i

[@sowmyaburgula5359]

This is simple and easy to understand thanks :)

[@evanexcel7148]

This way also it works- Let me know your thoughts as well import java.util.Scanner; public class Main { public static void main(String[] args) { System.out.println("Enter the number to check if it is perfect"); Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int sum =0; for(int i =1;i

[@shivaprakashreddyyeredla1705]

I didn't understand this vedio

[@elangovan2045]

लसनगजलचु

[@pravarkunnath3519]

istg brh this launguage makes me wanna kms