#28 Creation of Array in Java

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In this lecture we are discussing:
1)How many way to create array in java?
2)default value store when we creating array with object notation
3) fetching the value assign different value array element
#1
Ways to create array in java
a)Literal notation
Literal notation: int[] arr = {1, 2, 3};
b)Object notation
Array constructor: int[] arr = new int[]{1, 2, 3}; // this is not literal notation ,this is object notation with assignment of value
Array constructor with size: int[] arr = new int[3]; arr[0] = 1; arr[1] = 2; arr[2] = 3; //in this we manually assign value but by default 0 is assign in this case
#2
default value which store array when we create using object notation for primitive datatype.
-- When you create an array of primitive data types in Java using the object notation, the default value stored in the array depends on the data type:
-- int arrays: default value is 0
-- boolean arrays: default value is false
-- char arrays: default value is '\u0000' (null character)
-- byte, short, long arrays: default value is 0
-- float arrays: default value is 0.0f
-- double arrays: default value is 0.0d
code for you --
char ch[]=new char[3]; //declaration and initialization
for(int i=0;i less then ch.length;i++){
System.out.println(ch[i]);
}
check result--
#4
fetching the element of array :
-- for traversing whole array, you need to know either length of array or know length property of array
-- using length property we get length of array
-- using index we can fetch all value of array
suppose we create int nums[]={2,3,4,5};
access first element then nums[0],
access second element nums[1],
access third element nums[2],
access fourth element nums[3];
-- if you match pattern for accessing the element
you get nth element is nums[n-1];
for 7th element nums[7-1]; i.e is nums[6]
-- in array position start from 0,1,2, go till n-1 if n is length of array
change value of given position
int nums[]={2,3,4,5};
for(int i=0;i less then nums.length;i++){
System.out.println(nums[i]);
} //traversing whole array -- means fetching all elements of array
nums[0]=10;
nums[1]=11;
nums[2]=22;
nums[3]=33;
for(int i=0;i less then nums.length;i++){
System.out.println(nums[i]);
}
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[@justdevi]

just a mention, int nums[ ] = new int[4]; is C style array declaration. java style is int[ ] nums = new int[4]; Both are correct btw

[@ppganesh7822]

It is not possible in c

[@AnuragRawat01]

Nah buddy int nums[ ] = new int [4] that can't work in c

[@serrioton1858]

thanks i was confusedf

[@newmoviesthamizhantech2663]

​@@serrioton1858😂

[@wajdwael8775]

Thank you for this clear explanation.

[@laylachisom8996]

Super helpful

[@princeiiolaguera921]

please add exercises thank you

[@ricotabaque8705]

how to create new array as user input as identifier array ?

[@RameezKhalil-pn4yo]

You can create a for loop and then for each iteration you can store the value being passed at each index , for example: int arr[i]= sc.nextInt() // you will need to create an object from scanner class, so you can make use of it.

[@mso_studio_official]

public static void main(String[] args) { int a[] = {1,2,3,4,5}; for(int i : a){ System.out.println(i); } }

[@MadhukumarAp]

i have question why index value start with zero.

[@RameezKhalil-pn4yo]

Because that's how the memory structure works, and this is how the compiler interprets the value from the actual indexes. The values are placed over contagious locations with respect to each other so the next index gets calculated via (arr+i); for first element ( arr + 0) provides us with the first element; the list goes on until the last element

[@The_Motobikers_World]

And there is one reason for this naming convention is in array the index start from zero because here we calculating how far the element is from beginning of the array , the first element of an array is 0 position far from starting the second element is 1 position far from beginning of the array that's why the index value in many programming language's compiler starting from 0 .

[@ramakrishnanalluri2547]

.