LDO basics: Dropout voltage

  Рет қаралды 90,190

Texas Instruments

Texas Instruments

Күн бұрын

Пікірлер: 48
@Liveables
@Liveables 4 жыл бұрын
Make simplified explanation, this one is even more complicated than the one in my books, use practicals that's y we come to KZbin to visually see not to listen to someone reading for us what we left in the books
@himanshuful
@himanshuful 4 жыл бұрын
Exactly. I had expected a simple explanation and introduction in first video
@maksudulhossainjewel378
@maksudulhossainjewel378 3 жыл бұрын
You made it more complicated than necessary.
@manuk4759
@manuk4759 3 жыл бұрын
LOL
@erdem--
@erdem-- 3 жыл бұрын
Explanation is great! i don't know why everyone complaining about this!
@technologylover5976
@technologylover5976 2 жыл бұрын
You're teaching very fast. Not easy to be understood by beginners
@agstechnicalsupport
@agstechnicalsupport 5 жыл бұрын
Not bad, the video explains basics of LDO and points attention to the dependence of dropout voltage on various variables. Volume should be higher though. Thank you !
@kwekker
@kwekker Жыл бұрын
isn't there a volume button on your device
@agstechnicalsupport
@agstechnicalsupport Жыл бұрын
@@kwekker There is, but even when cranked up it was low.
@gavincurtis
@gavincurtis Жыл бұрын
Why did you change pin convention on what was standard for 40+ years? Why is pin 1 no longer input but GND? Why is the tab on a standard positive volt regulator now Vout?
@ajingolk7716
@ajingolk7716 6 ай бұрын
So it is better to have a very low dropout voltage
@gotj
@gotj 6 жыл бұрын
The volume is too low.
@petertwiss356
@petertwiss356 5 жыл бұрын
This LDO diagram at 3:15 is showing positive feedback, did you mean negative feedback?
@kiromaisus
@kiromaisus 5 жыл бұрын
It's positive sign, but negative feedback, as the PMOS has inverted signal behavior, in relation to the NMOS. So the higher the op-amp voltage, the lower will be Vout, and this 2 will be balanced to reach the setpoint.
@nicholaskenneth487
@nicholaskenneth487 2 жыл бұрын
to add on, the PMOS here acts as a CS (commons source) amplifier, which gain is negative. Hence, the output (at drain) is feedback to the positive terminal for negative feedback
@annguyendang8388
@annguyendang8388 4 жыл бұрын
Hi Sir, what does the output current means? I think that this value depends on the load condition as the output voltage is fixed!
@PreludeSon
@PreludeSon 3 жыл бұрын
it is the max current that it can supplied.
@alfredbadasu7644
@alfredbadasu7644 5 жыл бұрын
the volume of the video is too low....A company like Texas Instruments should do better
@PramodKumar-gr6hz
@PramodKumar-gr6hz 4 жыл бұрын
how to do jumper ldo ic
@jakoblawrence34
@jakoblawrence34 Жыл бұрын
Hey, this isn’t Let’s Drown Out!
@satzhanaskarov2306
@satzhanaskarov2306 2 жыл бұрын
kzbin.info/www/bejne/n6iXq2NtpK96p5I Here you are saying that 175mV is the MAX DO voltage and WHY you are assuming that the LDO will ALWAYS drop the Input voltage by that value?
@unboxingwithkhushi-w3k
@unboxingwithkhushi-w3k 4 жыл бұрын
I was searching why is a dropout even there 👍
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@simranmahendraker1441 5 жыл бұрын
Too technical.
@kavinduvindikasomadasa352
@kavinduvindikasomadasa352 5 жыл бұрын
worst in explanation
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@HallJillian-yi5ns Жыл бұрын
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@BelnoMakia 4 ай бұрын
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