dammit, now we gotta cancel the funeral arrangements
@slamwall90573 жыл бұрын
Oh my cosh this is such a good video
@alphalunamare Жыл бұрын
In my first job I was tasked with calculating the length of a catenary so as to figure the amount of tarmac on a road bridge. It took me two days until using multiple trig substitutions and the result had square roots everywhere. I calculated a length of 102.7 ft. I showed it with pride to the Engineer and he took a piece of string, ran it over a technical drawing, measured it and said Yep! I felt daft having gone through all that and then to make it worse a new graduate said: Why didn't you use a hyperbolic substitution? What's that I asked ... feeling even more stupid. I went home and looked them up and was stunned at how easy they made things. I quit my job and went to college :-)
@helloworldfromvn Жыл бұрын
Damn, you need to tell us more 😂
@alphalunamare Жыл бұрын
@@helloworldfromvn It's nice to share 🙂
@andreandes7485 Жыл бұрын
when was this@@alphalunamare? Are you still in college? Did you go to college for your bachelor's or master's?
@altuber99_athlete3 жыл бұрын
I hope KZbin is paying you very well. When first starting to read a textbook of a given topic (electrical engineering in my case), I always found it hard to give the first step. I mean, no motivation is usually provided, so I think “why am I learning this?” or “what can I do with this?”. Providing applications as you do in many videos is the motivation many people need. So thank you a lot for these free videos.
@cheiron81633 жыл бұрын
Around 5:00. Minimal surfaces dont (necessarily) minimize the surface area (there are some that do minimize it). In fact, the catenoid doesnt minimize the surface area of the soap between the rings, it just locally minimizes it . If you take a larger part of the catenoid and replace it by a cylinder the surface area gets smaller. Edit: I am not sure about the soap, it might burst when large enough, but the process I described above reduces the surface area of a "mathematical" catenoid. Edit2: I have found a video of what actually happens when you pull the rings too far apart: kzbin.info/www/bejne/jqKudY14btOreqs
@xaviergonzalez51453 жыл бұрын
Interesting!
@kindlin3 жыл бұрын
A get that curve between the 2 rings must have a longer path than a straight line, but if you think about a ring around the catenoid, parallel to the rings, its smaller with a catenoid. So, in full 3D, the catenoid does have less surface area.
@cheiron81633 жыл бұрын
@@kindlin Thats not right. Lets say we cut the catenoid off at the heights -a and a (it should be "centered" at height 0). Then we get an expression like A_1=C*(cosh(a)sinh(a)+a) for the surface area. If we do the same for a cylinder from height -a to height a we get A_2=D*a*cosh(a) where C,D are constants. Now cosh(a)/sinh(a)-->1 for a to infinity, so A_1 behaves asymptotically like cosh^2(a) and A_2 behaves like a*cosh(a). With that we can see that A_1/A_2 goes to infity for a to infinity. That shows that the cylinder has a smaller surface area for big a.
@kindlin3 жыл бұрын
@@cheiron8163 You're way over complicating this. A catenoid forms between the 2 rings, easily shown and google'd, which itself is comprised of a continuously rotated hyperbolic curve. The mid point of this curve is necessarily closer to the centroid of the straight-lined ring-cylinder, and so the surface has a smaller diameter and area.
@cheiron81633 жыл бұрын
@@kindlin 1. I am not talking about the ring stuff, but about a mathematical catenoid (that goes on forever, otherwise i would not talk about limits). 2. Yes, your argument explains intuitively why the catenoid has a smaller area for small height, but it cant be applied in all cases. 3. Your argument "your proof is complicated, so it is wrong, as i found an easier answer on google" is irrational (not to be rude, but you cant just reject an argument because its "complicated"). 4. If you dont trust my proof, here is a thread in math.stackexchange about the topic: math.stackexchange.com/questions/1505835/understanding-an-example-for-minimal-surface-doesnt-imply-least-area (its more complicated, but maybe helpful) 5. If you want to verify it yourself, just take the formula for rotational surfaces and use it from height -a to a like I did. You can search up the integral of cosh^2 or maybe use the definition and factor the exponentials. Maybe you trust your own calculations more than mine :) 6. Feel free to ask questions if you have any.
@johnchessant30123 жыл бұрын
Fun fact: Take a parabola and "roll" it on a flat surface; the focus of the parabola traces out a catenary curve.
@trilogeee3 жыл бұрын
I’m interested but don’t quite understand what you mean by “roll”
@skylardeslypere99093 жыл бұрын
@@trilogeee just like how you roll a ball over the ground. Imagine you have a very large physical shape that is a perfect parabola. If you start pushing it, it will keep on rolling like how a ball or an egg does. Because the concavity of a parabola doesn't change (and is positive), you can keep rolling it indefinitely.
@mostly_mental3 жыл бұрын
Similarly, a square wheel rolls smoothly on a catenary. (I made a video about that, for anyone curious: kzbin.info/www/bejne/hpevq2qelqupoc0 )
@skylardeslypere99093 жыл бұрын
@@mostly_mental nice video! I watched it all the way through and it was very clear. If you're willing to accept constructive criticism, I'd just change the way you calculated the integral. It's not ideal to have to pause and read for yourself while watching a video. But a great nonetheless :D
@mostly_mental3 жыл бұрын
@@skylardeslypere9909 Thanks. The integral wasn't the important part, so I didn't want to interrupt the flow, but I can see how that would be distracting. I'll try to avoid that going forward.
@mujimuji60023 жыл бұрын
Fantastic timing, i was just thinking about this while leaving the library.
@kartikarora35213 жыл бұрын
After binge watching your other channel, you feel completely different on this channel. I almost forgot that you used to make Science videos.
@danielyuan98623 жыл бұрын
he DID?
@jlpsinde3 жыл бұрын
Simply amazing and top quality. I loved it!
@crimfan3 жыл бұрын
Hyperbolic trig functions show up in statistics, too. For instance, Fisher's z transformation of the correlation coefficient is the inverse hyperbolic tangent. This happens because the transformation was derived using a differential equation that is satisfied by the hyperbolic tangent function. The ubiquitous logistic function is essentially a differently scaled hyperbolic tangent. Inverse hyperbolic sine mimics the natural logarithm for medium to large values but behaves like the square root near 0 and is defined for negative values.
@kevincorrales97743 жыл бұрын
Awesome video! I got all the way through differential equations in college and we never talked about hyperbolic trig at all. This was a great intro it!
@Triadii Жыл бұрын
Not all high schools teach it I heard
@physicsboi17443 жыл бұрын
Another useful thing about hyperbolic trig is that cos(ix)=cosh(x) and sin(ix)=sinh(x), so for a function sin(theta) = 2, there are no real solutions, but if we let ix=theta, sinh(x)=2, therefore x = arcsinh(2), theta=ix = arcsinh(2)i
@godfreypigott3 жыл бұрын
Wrong. sin(ix) = i sinh(x). And theta = - i arcsinh(2i)
@raymondfrye50172 жыл бұрын
@P. BPI: You should proofread your argument for it to be complete. Regards
@wafikiri_ Жыл бұрын
Although an i is missing in some places there, once replaced where missing, the reverse also works: cosh(ix)=cos(x) sinh(ix)=i sin(x)
@ashokfrancis9673 жыл бұрын
1. cosh is the EVEN part of e^x and sinh is the ODD part of e^x. This lets us exploit symmetry as coshx + sinhx = e^x 2. Chebyshev: differential equation, polynomials of first kind, type-I and type-II filters all use hyperbolic cosine. Also, say you want the inverse cosine of 1.2 (i.e. out of the range -1 to +1), you go for cosh inverse. This is directly applied in Chebyshev applications
@danielyuan98623 жыл бұрын
1. is also a good example of how a function can be split into an even function and an odd function that add to each other. [The general case is f(x)=(f(x)+f(-x))/2+(f(x)-f(-x))/2]
@noahgonzalez41112 жыл бұрын
That’s what I was trying to say
@بِلَادٱلرَّافِدَيْنبِلَادٱلرَّ3 жыл бұрын
I literally just learned about hyperbolic trig 2 days ago and wondered why it would be useful lmao perfect timing
@debabrata36053 жыл бұрын
Please make a full course on mathematics from zero level(elementary) to the advance level ! We all want to learn mathematics from you. The way you teach mathematic is awesome. This course will be very helpful full for the young generation. And there is no such well constructed course available online with a teacher like you!
@dannyCOTW2 жыл бұрын
Kahn academy is pretty good ngl
@diomauia4295 Жыл бұрын
@@dannyCOTW like legit or just pretty good
@jayp9158 Жыл бұрын
Just grab a high school algebra book, then study geometry and trig, then move to calculus and whatever you are interested in.
@aashsyed12773 жыл бұрын
Sin and cos is imaginary exponentials
@aahaanchawla53933 жыл бұрын
sin(ix) = isinhx
@sohangchopra64783 жыл бұрын
@@aahaanchawla5393 I remember feeling quite proud of myself when I "discovered" this relation myself! (Hyperbolic functions were not in the school syllabus)
@aahaanchawla53933 жыл бұрын
@@sohangchopra6478 I discovered it when I was searching for a way to find trigonometric functions of complex numbers. I watched someone do it, then forgot about it, and hen derived it myself using some algebra and euler's identity.
@liangdong32263 жыл бұрын
Omg as an engineering student, I would say this video is absolutely amazing!!
@christianbatista18373 жыл бұрын
Hey Zack, don't forget about the Meniscus, when a fluid is added to a graduated cylinder. great video.
@NewWesternFront Жыл бұрын
oh cool thats cosh?
@jamesraymond11588 ай бұрын
Great video and great to see someone who benefitted from college. Those tough homework problems that take hours and hours to solve really pay off. They give you the confidence to tackle more difficult problems.
@pfeilspitze Жыл бұрын
13:55 I hope the course doesn't say that suspension bridges are catenary curves. The load from the bridge deck means they're parabolas, *not* catenaries, since the forces from the downward loads they're carrying dwarf the impact of the weights of the cables themselves.
@anirudh20002 жыл бұрын
These videos bring interest naturally! Thank you for showing the applications.
@floriskleinestaarman32003 жыл бұрын
Please keep going with making your videos. They are great. I lreally like your puzzles and these random mathematical subjects in particular. So much respect.
@TheLolle973 жыл бұрын
Good stuff! You managed to hit a topic that was pretty much neglected so far by all other math channels I follow. Was definitely worth the wait ;)
@randilibin50663 жыл бұрын
Perfect timing. We started talking about this in class today and I was SO LOST
@punditgi2 жыл бұрын
Beautiful explanation! Well done!
@rodrigop97143 жыл бұрын
Idk if this was also the case for other engineers world wide but they didn't really teach us about this in introductory math and I feel like it's a pity. I was curious to know exactly what shape did strings described when hanging them and learning about h trig functions and their properties has been very stimulating for me. Thanks for the awesome explanation
@shersinghsaini85103 жыл бұрын
I just finished doing my homework on quadratic air resistant, first time working with hyperbolics. Honestly, I'm starting to lose fear to them and enjoy understanding their implications. Thanks!!!
@user-zb8id6hf5t6 ай бұрын
I’ve stumbled across your videos again and want to say these are clear, concise, and fun. Keep up the great work.
@CARLESIUS3 жыл бұрын
You should have explained that for both circular and hyperbolic functions, the argument is the area between the x-axis, the curve in question, and a vector that goes from the origin to the point of the curve. Thus, these are area functions. In the case of a unit circle, the arc is equal to the area, but it is possible to define hyperbolic and elliptical functions (dependent on the parameter e, which is the eccentricity), which have the arc as their argument and not the area.
@rababalnajjar31703 жыл бұрын
Your channel is so interesting, I'm happy your video was recommended to me. I'm a physics student and I enjoy your videos. Keep it up!
@artsmith13473 жыл бұрын
Nice video. Like many other things that could have been covered in college, my first exposure is on YT. I ran into the cosh a few times, but I don't recall that it was ever explained well. It seemed to be presented as an ad hoc black box that made a solution easier to write. A link to the Desmos page with the tractrix at 07:20 would have been nice. The link in the description is to the calculator without an example.
@hunterthemadman3 жыл бұрын
Funny how one of your skits was in the suggested videos section to the side when you pulled up "Catenoid". Your channels are growing fast. Quality video. I learned a bit even though most of it went over my head.
@cardinalityofaset49923 жыл бұрын
This is absolutely fascinating. After Watching this video I have imediately wanted to solve some DEs where hyperbolic trig functions :)))
@d4v1dc0fuse93 жыл бұрын
just reached university, I was having nightmares with hyperbolic, glad you're alive
@iTeerRex3 жыл бұрын
The curve of a tooth of gear also falls in this category. Very cool stuff.
@nicepajuju39003 жыл бұрын
Your videos are very informative man! Thanks!
@andreandes7485 Жыл бұрын
I am in Calc one, barely understand the basic trigonometry. And you bring up this new thing called hyperbolictrig. I seriously need to study trigonometry over the winter break
@josephtraverso27003 жыл бұрын
You’re channel is absolute awesomeness
@INGIE322 жыл бұрын
Another cool link between hyperbolic trigonometry and regular trigonometry is that a cosine/sin/tan with an ix argument is just a hyperbolic cosine/sin/tan function and vice versa.
@FerghusCameron4 ай бұрын
You have opened a new perspective to shapes and math in general for me; Blessed are the meek. 🔥
@brucea98713 жыл бұрын
There is an additional correspondence between trig and hyperbolic functions you didn't mention. A formula for the sine of a complex number z is sin z = (e^(iz) - e^(-iz))/(2i) and for the cosine of a complex number z we have cos z = (e^(iz) + e^(-iz))/2 where ^ represents exponentation and i is the square root of -1. Those formulas are very similar to the formulas for sinh and cosh (in fact they are identical if we remove the i from the sin and cos formulas).
@joeyhardin59032 жыл бұрын
9:57 "greenland looks like it's the size of all of africa, when it's only really the size of greenland"
@aa_ahnaf3 жыл бұрын
My reaction after seeing the thumbnail: Oh, there's all the torturous devices I don't ever wanna find lying on the living room floor.
@MathTutor13 жыл бұрын
Excellent work. Keep up.
@peerizahmanavsingh50422 жыл бұрын
Very much informative...very good for visualization...👍👍
@3moirai3 жыл бұрын
I always wondered about the hyperbolic trig functions on my calculator. Now I know more about them.
@fabienyoutube47433 жыл бұрын
My favourite: surface gravity waves whose relation of dispersion involves a tanh! Thanks for the nice vid :-)
@loftyTHEOWNER3 жыл бұрын
This video is amazing, thank you Zack
@godfreypigott3 жыл бұрын
You missed the opportunity of referencing relativity and Minkowski geometry.
@protocol63 жыл бұрын
Cool and informative video. I learned something new. Thanks. This really only relates to your intro but it has long bothered me that circle and the hyperbolas are oddly not directly comparable despite both being the rotations in their respective algebras. It's the square in minkowski space that double covers the circle in euclidean space when you rearrange from A²=C²-B² to the equivalent A²+B²=C². You have to do the conversion twice to relate the rotations which doesn't seem right algebraically. It has always felt to me like neither is quite the "right" way to represent things and there should be a better way. Perhaps it's something to do with our units and the way our perception works such that we square root sound and light intensity when we sample it and square it for output or transformation. Or, Einstein and others were right and all frames are equally right or wrong and there's no universal frame. Probably that, but it chafes.
@coleeto2 Жыл бұрын
What was the site used at 10:04 to check the size of Greenland?
@Rupss.873 жыл бұрын
❤️ Doubts solved... Nicest explanation sir🔥
@AJ-et3vf3 жыл бұрын
Awesome video! Thank you!
@JimSmithInChiapas3 жыл бұрын
A wonderful video. I've subscribed to this channel, and to your Spanish one. A quibble, though, regarding the suspension-bridge cables depicted in the thumbnail: the shape of uniformly-loaded cables (like the ones in suspension bridges) is indeed a parabola, rather than a catenary.
@davidchartrand1033 Жыл бұрын
Very good video. Thanks!
@reidflemingworldstoughestm13943 жыл бұрын
I really hate to see respected STEM channels resort to hyperbole. You're better than that Zach.
@reidflemingworldstoughestm13943 жыл бұрын
@Hisham Malik sinh and cosh
@pierfrancescopeperoni3 жыл бұрын
Also central forces proportional to the inverse of the distance square are awesome, quadrics are some of the most beautiful trajectories.
@glamorousarts2291 Жыл бұрын
This channel just show me how much I love maths
@minimonster3466 Жыл бұрын
Also the hyperbolic trig functions can be expressed using complex numbers and there regular counterparts Tanh(x)=tan(xi)/i
@rebanelson6072 жыл бұрын
Excellent vid!
@jeremybeale_2 жыл бұрын
7:11 this is art
@Clemfandang06 ай бұрын
Great video, I subbed
@brandonmaldonado70083 жыл бұрын
Can you make a video on -Architecture -Biotechnology -Engineering Physics -Petroleum Engineering -Cryogenics -Cryogenic Sleep
@bpenaval25413 жыл бұрын
That a lot of videos
@readjordan22573 жыл бұрын
I dont think he wants to compete with SciShow
@danielyuan98623 жыл бұрын
@@readjordan2257 maybe he accidentally placed this comment here instead of at SciShow
@readjordan22573 жыл бұрын
@@danielyuan9862 but they already have at least one video on those topics. So he cant be. If he said "a new" or "another" maybe.
@readjordan22573 жыл бұрын
@@danielyuan9862 however, if zach star talked about these things and it didnt deviate from his usual style, id definitely watch. But im not sure how he could unless it is all a hodgepodge video
@HollywoodF13 жыл бұрын
The first necessary observation of soap film as a material is that is cannot sustain shear and must resort to principle stresses. Catenoids balance the tension in orthogonal directions at each point (element) such that there is no shear. These resulting hoop stresses cinch the cylinder into its characteristic shape.
@krelly90277 Жыл бұрын
Excellent video.
@theodoresweger4948 Жыл бұрын
Loran C comes to my mind a system to find your location at sea. signals transmitted by two seperate radio stations simultaniously you have a chart showing showing you on one line from one station and then you look up your ine fr the other station and where they cross is your location, now done by compute I am sure.., the I believe its still in use today but I may be mistaken. also you use the same principal listen when artiliary is fires and the difference between two separate locations you can calculate where it came from . My discription may not be very accurate but its been quite a few years since I was involved..
@kjessee923 жыл бұрын
Powerlines hang in catenary. I make a living getting wire correct.
@theastuteangler3 жыл бұрын
what benefit is gained from making the calculations of hanging cables? Less strain on the posts?
@hiccupwarrior893 ай бұрын
I literally got jumpscared when I saw your face and realised you were the guy who makes comedy skits
@alexanderfigueroa6293 жыл бұрын
Great video!
@calmatic42543 жыл бұрын
I'm starting to think that topologists are crazy
@hhhsp9517 ай бұрын
I mean, you're right..
@mattgsm3 жыл бұрын
8:33 how did you get this? I've done my own integration, wolfram too and they all give different answers. Yes I remembered +c Edit: I differentiated your integration and also used desmos and wolfram alpha and none of them end up being the -sqrt(l^2-x^2)/x we started with
@TerranIV2 жыл бұрын
Another cool application of hyperbolic trig is the path of an accelerating mass in a spacetime diagram. As it approaches light speed it traces out a hyperbolic curve between the time axis and the 45 degree line representing c, just like a tracrix. In this case I guess it would represent the universe conserving energy in spacetime?
@kierandrilon64522 жыл бұрын
5:55 "Minimal surfaces are not that easy to find" Kufufu I found a minimal surface when I blew my nose on some tissue and slowly opened it to find one. I am the greatest just kidding sorta. I finally learnt a use for hyperbolics thanks Zach
@jackwillcox93303 жыл бұрын
The goat is back
@bjornfeuerbacher5514 Жыл бұрын
Additional to the important applications in Special Relativity which others already mentioned, you also forgot a very imporant application in General Relativity / cosmology: The function sinh (to the power of 2/3) describes the expansion of the universe! See e.g. the article "Lambda-CDM model" at Wikipedia. What the article doesn't mention (but it's easy to calculate that): The function coth describes the time dependence of the Hubble parameter.
@Xayuap3 жыл бұрын
is the back wheel of the bicycle following the front one while traveling straight a tractrix?
@akaHarvesteR8 ай бұрын
In orbital mechanics, there's a lot of hyperbolic trig as well. The moment an orbit's eccentricity goes above one, it goes from being an ellipse to a hyperbola, and it's all hyperbolic trig to solve those.
@mr.tommy__85863 жыл бұрын
Do more say more just like this ☺️☺️☺️ your video is awesome nobody tells this much of math and science keep going you are doing a great job on planet Earth 🌎🌎🌎
@MrInventer803 жыл бұрын
Can you make a video about Nyquist theorem for signal analysis
@ItsJustyceVids3 жыл бұрын
Interestingly, I just learned about hyperbolic sin and cos a few days ago in my differential equations class!
@evelynleslie26332 жыл бұрын
Me, a theatre major, one minute into the video: 👁👄👁
@looksintolasers Жыл бұрын
Thanks for the video! Hyperbolic trig, somehow we missed that in calc.
@TorreFernand3 жыл бұрын
Me in math class years ago "Everybody got that? Good. Now we're going to introduce a function called hyperbolic sine" "Um... why?" "BECAUSE IT'S IN THE CURRICULUM!"
@ichigonixsun3 жыл бұрын
10:10 Angry flat-earthers noise
@corbintocarbon8170 Жыл бұрын
10:49 if this is a almost to true size comparison of the world I had no idea America was an island in comparison to Europe let alone any other continents. Wild.
@maarrccoss Жыл бұрын
Where can I find this program ???
@artilleryisbetter3 жыл бұрын
Didn't expect to be looking at Math this early in the day...
@HypnosisBear3 жыл бұрын
It's night for me here!
@samuelmcdonagh15903 жыл бұрын
are you sure the catenoid surface formed between two circles minimises surface area? It seems intuitively obvious that the minimal surface area between the points would be a cylinder. I suppose you meant to say that the catenoid surface minimises the elastic energy within the soapy film rather than the surface area?
@MePeterNicholls3 жыл бұрын
This video is too short! Fascinating stuff
@jacobstarr90108 ай бұрын
Fun fact: the gateway arch in St Louis was designed using a hyperbolic trig function, and its max height (in m) is exactly equal to the maximum of the hyperbola.
@trelligan423 жыл бұрын
Yay, real math content. And I *_have_* been curious about this.
@DilipKumar-lu9bs3 жыл бұрын
Please do a video on different job roles like software developer, data scientist, data analyst etc., describing them ..similar to your past videos on different engineering branches ...
@caiomarques53273 жыл бұрын
amazing vídeo!
@jmachadok3 жыл бұрын
I wish your videos existed when I was learning math in school.
@tomkerruish29823 жыл бұрын
No mention of the gudermannian? Well, I suppose I can still upvote your video. XD
@paulsavitz3 жыл бұрын
I'm having trouble thinking about the minimization of the surface area between two rings--the problem is that I end up with opposite results depending on how I think about the integration, and they both seem intuitive. In both cases I'm imagining a vertically-oriented shape, like in the video. I go about finding the side surface area (i.e., not including the top and bottom ends) in one of two ways: METHOD 1: Start with a horizontal cross-section (say, at the bottom of the shape) and then translate that up to the top of the shape. The surface area would be the sum of each "ring", or the perimeter of each of those infinitely thin cross-sections. To minimize this area, it would make sense to minimize the radius of each of these rings, meaning that we would want the curve to be as "pinched" as possible. At the extreme, this would be an arbitrarily skinny tube connecting the top and bottom circles, and the surface area (not including the outer ends) would approach the area of the top and bottom circles. METHOD 2: Start with a vertical line or curve connecting points on the top and bottom circles, and then rotate that curve around the vertical axis (like in the video). The surface area would be the sum of the areas of each infinitely narrow vertical area. To minimize the area in THIS case, it would make sense to have each vertical curve be as short as possible, meaning it would be a straight line, or a straight-sided cylinder. Again, both of these methods seem intuitive to me, but they seem to lead to opposite results. Can anyone shed line on this? Thanks!
@cheiron81633 жыл бұрын
I ll try my best, I am not sure that I can explain it well though. The answer is somewhere in the middle, both of your methods can reduce the area, but are not guaranteed to find a surface with minimal area. If you rotate the graph of a funtion f around an axis and want to get the surface area from height a to b, you can use the formula: Area = Integral_a^b sqrt(f(x)^2 * [1+f'(x)^2] ) dx Now your first method reduces the factor f(x)^2 (thats the squared radius of the ring at height x). Your second method reduces the factor [1+f'(x)^2] (for a straight line f'(x)=0, so you just multiply with [1+f'(x)^2]=1). Now to find a shape with minimal surface area you have to find a function f, such that the whole integral is minimal (if we just focus on rotational surfaces). But for finding such a function you cant just focus on one of the factors in the integral (maybe that makes some sense).
@sleekrings6203 жыл бұрын
Can you tell me where you do these equations animation?
@erniesulovic47343 жыл бұрын
Qn: do they do the physical test first and draw the graph and then find the eqn which is never taught on how to do, or do they first mathematically guess it and then test via physical experiment? I have often wondered if I were to draw a graph, how does one work backwards to find its equation?
@jackkalver464411 ай бұрын
The inverse hyperbolic sine can be used to find arc length on a parabola, arithmetic spiral, or exponential curve.
@HighKingTurgon Жыл бұрын
Imagining a "hyperbolic spring" is actually rather helpful-if it were to apply force in the same direction as it was pulled, you could see the infinite, asymptotic, non-periodic motion approximating the unit hyperbola.