The Compression Factor, Z, and Real Gases - What you NEED to Know!

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Brainy Nerd Tutor

Brainy Nerd Tutor

Жыл бұрын

Understand the compression factor in thermodynamics better than anyone in your class! I fully explain it so that you'll be a boss at this topic! Check out my compression factor cheat sheet (link below).
Learn how the compression factor accounts for real gas behaviour and how is changes based on pressure, temperature, and molar volume. We will dive into the compression factor on all levels: macro, micro, and symbolic (math).
Check out my compression factor cheat sheet here:
drive.google.com/file/d/1s-Ck...
I've got TONS of other thermodynamic videos here:
• Thermodynamics
Animation of gas expansion and compression from:
ch301.cm.utexas.edu/simulatio...
Image of pin from: pixabay.com/vectors/nail-hamm...

Пікірлер: 6
@leomcpie7904
@leomcpie7904 6 ай бұрын
Keep it up, this video can save lives.
@florentinosanchez3969
@florentinosanchez3969 7 ай бұрын
Thank you so much, you finally made sense to this which no one really explains
@florentinosanchez3969
@florentinosanchez3969 7 ай бұрын
Best video ever
@raed_ksa9449
@raed_ksa9449 2 ай бұрын
"if you want to surprise someone at a party" lol
@raghula5916
@raghula5916 7 ай бұрын
Sir I first case we keep v and t constant then how pressure decrease for z=0.9 and pressure increases for Z=1.1 my question is you are adjusting moles in the container for first case removing mole lead to attractive force for second case adding moles
@brainynerdtutor1626
@brainynerdtutor1626 7 ай бұрын
Good question. Let us assume that we have two containers at the same T and V with the same moles of gas. Thus, n, V, and T are constant. If the gases were perfect (ideal, Z=1), then the pressures would be the same. This is because everything in the perfect gas equation (pV=nRT) is constant). But for a real gas pV=ZnRT. So if n, V, T are constant, then the pressure will change if Z is different. If Z=0.9 for one container, attractive forces are dominant. The attractive forces mean that the gas is more attracted to itself and won't collide with the container as much, hence lower pressure. If Z=0.1 for the other container, repulsice forces are dominant. The repulsive forces mean that the gas is crowded or repels itself and will collide with the conatainer more often, hence greater pressure. Z can change if you change V, n, or T. But Z is also dependent of the type of gas. Does that help?
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