The EASY WAY to do a Timber Post Calculation

Here's how to calculate how much weight a timber post, column or strut can carry.
💥Download the timber calculation reference tables I used in the video: geni.us/timbercalculation
Starting from scratch with no previous knowledge of structures required, we do a timber post calculation the easy way, working out the allowable stress based on the effective length.
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[@RobindeJongh]

✅Get the timber tables here: geni.us/timbercalculation

[@yogasciencemusic]

Well explained. Thank you Robin, you r doing a great job. Please keep posting more video. You are a mentor to me. 🙂

[@RobindeJongh]

That's really great to hear, Santosh. Keep up the good work with your learning.

[@johndaniels5407]

Thank you so much for sharing!

[@saddammb5633]

Well explained…👌👍🏻

[@davidbostock4145]

Hi Robin many thanks for the video, I’m doing a similar design for a friend but wondered if I need to take in to consideration the bending caused by the loading from the front (horizontal) beam?

[@fedoremilyanenko4589]

Thank you sir, what about internal chords ? How to determine them ?

[@EffiomE]

Thanks for posting Robin. Could you help me understand what factors were used to produce a compressive strength value of 7.9 N/mm2,for C24 down from 21 N/mm^2 from the BS EN 338 table. I suppose material factor, load duration factor etc will come into play however I seem to be missing something

[@RobindeJongh]

Hi Effiom. As per the Roy Mech website "the strength values in this table are characteristic strengths ( fifth percentile values derived directly from laboratory tests of five minutes ) whereas the equivalent values in the BS 5628 table are grade stresses which have been reduced for long-term duration and already include a safety factor."

[@benhoweysurf]

Hi... can you explain why the answer is different using Pcr=pi^2*EI/L^2 ? Should they be the same?

[@davidselin9860]

Hi Robin, thank you very much for this very clear explanation. Do you have a video that will help me with the following. I am retired and a volunteer at a local farmland museum. We would like to build a capony over a pair of dounble doors to make the entrance to the cafe more attractive. Unfortunately the building is clad i asbestos, which i want to avoid fixing to. My plan is to build the canopy on gallows brackets mounted on posts either side of the entrance. the posts will be 1.8Mtrs apart and the highest point i can affixe them to the wall is 1.2 mtrs before i meet the asbestos. The height to the top of the brackets will be in he order of 2.2 Mtrs. How do I calculate the size of he posts to minimise the deflection of the posts under the weight of the canopy (pitched roof canopy) to prevent a permanent gap appearing between canopy and asbestos wall. I intend using a flexible sealant between.

[@RobindeJongh]

Hi David. Might be best to make the canopy entirely self supporting in this case, and isolated from the building. You can use flexible sheeting of some kind if you need to bridge the gap for water runoff. You will need to design the posts as cantilevers to take the moments created by the canopy roof with snow and wind loading (can be severe). Would usually also need large concrete pad bases.

[@abedrahman4943]

in relation to tensile tension do you explain? and that I am doing a work on tensile stress in wooden structures, and this complicated to find know where I can find an example with the calculation?

[@kiranmathure880]

Hi sir, We want to construct H type frame for hydraulic press, I have calculated to platten size which is 1200mmx1200mmX200 mm thick The force on this top platten through hydraulic cylinder is 200MT(vertical) I have to constrain both side wall...pls help me find thickness of this plate

[@asif530]

Great video. Can you please post the link to the chart you used.

[@RobindeJongh]

Thanks! I've put the link to the chart in the description.

[@asif530]

@@RobindeJongh many thanks much appreciated.

[@benjaminbuljevic7977]

Thank you very much for the video. Im planning a storage floor type of construction for my workshop, which is why i wanted to calculate the maximum allowable weight i could store up there.I study mechanical engineering so i dont have much to do with wood. I had a look at the german version of en 338 and under "Druck in Faserrichtung" (compression parallel to grain, f(c,0,k)) it sais 21N/mm^2, which is obviously much more than the value you used. Is there something im missing here? What is the reason for this huge discrepancy? This is especially confusing because the youngs modulus values are very similar. In the 2016 version of the german en 338 the mean youngs modulus for c24 timber is 11 kN/mm^2 and the minimum is 7,4kn/mm^2. Do your allowable stress values already have a safety factor included in them?

[@RobindeJongh]

Hi Benjamin. Good question! The difference is that in the "permissible stress" method I use here, the factors of safety are already calculated in. In European Union you use "Limit state" which adds the factor of safety afterwards. Key thing for you to bear in mind also is to ensure it is well braced to stop it moving laterally. That is where the majority of the strength and safety comes from.

[@benjaminbuljevic7977]

@@RobindeJongh thank you very much!

[@pauldeezy2272]

When you have to watch a bunch of other videos just to understand half of what this video said 😂

[@jamesbrookes5614]

Great video. The link does not appear to work. Can you please check please, thank you in advance

[@RobindeJongh]

Thanks James. The link works ok for me - what do you see when you click it?

[@nandanm-xj7pg]

what does C24 mean technically .

[@geoffreygwyther]

Although I know what you mean, your phrasing is open to interpretation. 9025 mm squared is 81,450,625 square mm. Saying 9025 square mm for an area , cannot be confused

[@RobindeJongh]

Thanks Geoff. I will be a bit more careful in future. Well spotted!

[@TheMohadam]

De John? Dutch..