💥The Ferranti Effect💥

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Megavolt Homeschool

Megavolt Homeschool

Күн бұрын

A simulator showing the Ferranti Effect, in real time. A small amount of capacitance is introduced into a circuit containing an inductance. The two act in series with one another, resonating within a low voltage transmission circuit. The result is a voltage rise of 15 - 20 percent at the receiving end of the line.

Пікірлер: 30
@jasonkenney5970
@jasonkenney5970 Жыл бұрын
Very cool! Stuff they don't teach us in the field.
@t13fox67
@t13fox67 3 жыл бұрын
This has helped me understand this alittle better. I've been an electrician most of my career and this is one of those "grey areas" I didnt completely understand. Thank you. I like the illustration setup.
@overunityinventor
@overunityinventor Жыл бұрын
Saying that "you have earned a subscriber today" would exhibit my overconfidence, so I'd say that "I've added another mentor in my list today". Thanks for the wonderful explanation, setup & video👍
@ericg2975
@ericg2975 8 ай бұрын
Thanks for breaking it down to simplest terms my brother!
@bojack_man1792
@bojack_man1792 3 жыл бұрын
Straight forward explanation.. thank u for your efforts!
@danielaugustopagiferreira9021
@danielaugustopagiferreira9021 3 жыл бұрын
Great work! Simple and straightforward! Congrats!
@OKaFee
@OKaFee 3 жыл бұрын
Awesome explanation.
@robbytheremin2443
@robbytheremin2443 3 жыл бұрын
Cool! Resonance is how a Tesla coil can achieve such insane voltages. 😎
@ronaldomelo2006
@ronaldomelo2006 3 жыл бұрын
Ótima explicação! Este brasileiro agradece imensamente pelo material compartilhado.
@shekinah.a
@shekinah.a 3 жыл бұрын
Thanks Randall. Great detailed practical explanation. Learnt about it just yesterday. I'll surely be back here a few more times before my finals.
@HananMohamed-ph7on
@HananMohamed-ph7on 2 жыл бұрын
Thank you Mr ☺️
@jamesknkrumah6962
@jamesknkrumah6962 3 жыл бұрын
very explanation......thank you Sir.
@MegavoltHomeschool
@MegavoltHomeschool 3 жыл бұрын
Thanks and welcome
@mikehoman7351
@mikehoman7351 Жыл бұрын
Not sure if I have all this correct but if a voltage is higher as you move away from the source then there are three possibilities - one - the electron drift velocity is not metering the potential flow perfectly and some of the potential flow still gets past the electrons - two - some of the ambient field is becoming entrained into the potential flow - three - some of the electrons that are involved with the drift are ablating back into potential and this would also drop amperage - all three effectively raising the voltage - one or more of these things could be taking place simultaneously - - I'm curious to know your opinion on this
@MegavoltHomeschool
@MegavoltHomeschool Жыл бұрын
I've not thought to associate "potential" as a separate entity from charge density. Drift velocity x charge density = current. I'm not sure if that is what you are implying. Capacitive voltage rise, if I understand it correctly, is largely dependent upon charge density (as well as permittivity). Yes, there is a drift velocity (current) needed to produce charge density, but the diff eq's demand that current always be 90* leading the charge density "potential". Those two can not be in phase with one another. It gets very convoluted when trying to explain without a white board handy. In fact, reading what I just wrote, I'm not sure I even understand myself! 😅
@mikehoman7351
@mikehoman7351 Жыл бұрын
@Megavolt Homeschool I assumed that you have read more of Tesla's work that I have - Do you use any of Tesla's writings for consideration ? - Tesla is not my reference but he gave some clues - What I was trying to ask you had more to do with the anatomy of the electrical flow, a physical description of what was happening around and in the wire, so I stay away from the words like charge or capacitance, etc., because those are provisional terms that don't describe physically what's happening - I saw that you had built some Tesla coils so I thought you might have some insight into the subject
@MegavoltHomeschool
@MegavoltHomeschool Жыл бұрын
@@mikehoman7351 I am always quick to point out, my fascination with electricity (and physics) goes far beyond my ability to understand it. You'll be surprised to know, I have read none of anything Tesla wrote. Yes, he was a genius/savant. The unit of magnetic flux density is even named after him. But, he was an engineer at heart, not a physicists or a mathematician. I've studied Maxwell, Faraday, Ampere, Gauss, and others to learn the laws/theories of electromagnetism. And although conceptualization is important, mathematics is crucial. If a complete understanding is to be achieved, then there must be a mathematical framework employed to support it.
@mikehoman7351
@mikehoman7351 Жыл бұрын
@@MegavoltHomeschool I agree with you - The only issue I have wherein mathematics is employed, is it supports means of prediction, without actually knowing how something works quite a lot of the time, throughout physics and especially in quantum mechanics - I believe also this will not always be the case as the anatomy of particles and the actual true nature of energy are understood, then mathematics will have even more power
@Sportsman134
@Sportsman134 2 жыл бұрын
How does you know how much inductance to add via the reactor? thanks for the demo, great content!
@MegavoltHomeschool
@MegavoltHomeschool 2 жыл бұрын
The voltage rise at the receiving end is caused by the capacitive 'leading' current at the source. This capacitance is 'parasitic'. An inductor at the receiving end will create a component of 'lagging' current at the source. The inductance is typically a 'shunt'. If the component of inductive reactance (XL) = the component of capacitive reactance (XC), the two will be exactly 180* and the same magnitude. This will cause their currents to cancel, leaving no imaginary component (X = 0). Example: if an unloaded 500 kv line sees 50 amps leading current at the source, that implies a parasitic capacitance of ~265 nF (60Hz system). XC = 10 kΩ. A shunt inductance of ~26.5 Henries would provide the same amount of inductive reactance (XL). That amount of inductance would exactly cancel the capacitance. Great question. ❤
@Nxb9ch
@Nxb9ch 5 ай бұрын
Kool !
@MegavoltHomeschool
@MegavoltHomeschool 5 ай бұрын
Indeed 🙂
@engrHamdy
@engrHamdy 2 жыл бұрын
I wish you could make a video for explaining the spinning reserve in power system. Thanks
@ashenafidejene3347
@ashenafidejene3347 3 жыл бұрын
How is the load current affected by this at the receiving end?
@MegavoltHomeschool
@MegavoltHomeschool 3 жыл бұрын
In theory, it isn't. Any load, assuming it's real, should only help to increase power factor. However, I can't speak from empirical knowledge.
@milogonzalez1334
@milogonzalez1334 3 жыл бұрын
is this an example of faster than light transmission?
@Ferraday
@Ferraday 3 жыл бұрын
Don’t be silly
@milogonzalez1334
@milogonzalez1334 3 жыл бұрын
@@Ferraday dont be so dismissive
@deskmark
@deskmark Жыл бұрын
Milo: For 70 years Secret Military. Must sign NDA. Then if you qualify you can travel all over the Milkyway and beyond, faster than light. Otherwise, very soon you can use Quantum Entanglement free phone. They already talk to people on Mars with no delay to put up with. Trump talked to a space crew: They faked the slow speed and pretended they had to wait at least a half minute for a response.
@andremare7869
@andremare7869 Жыл бұрын
Parasitic capacitance? 🤔 Sounds a lot like energy induction from the atmosphere. Free energy
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