I learned these integrals last week in my complex analysis course! My professor did the general case of the integrals from 0 to ∞ of cos ax² dx (call it I₁) and of sin ax² dx (call it I₂), with a > 0. This means I₁ + iI₂ = integral from 0 to ∞ of exp(iax²) dx (call it I₃). We then set up the same contour and path parameterizations that you did and obtained the expression for I₃, whose real part and imaginary part are equal = I₁ = I₂ = √2/4 * √(π/a), and the case of a = 1 gives the solution as in the video. A slightly different approach for the definition of f and still very elegant!
@edmundwoolliams12405 ай бұрын
This was how I first learnt how to solve them! 😊
@bandishrupnath37215 ай бұрын
wonderful teaching sir
@maths_5055 ай бұрын
Thank you my friend
@jorgelovaco75275 ай бұрын
Beautiful beyond words 😍
@ikuyas52275 ай бұрын
What app are you using? It looks super smooth.
@axeitor5 ай бұрын
I think its the samsung notes app
@redroach40123 күн бұрын
How do you know when to sue a specific contour because some have semi-circle or box or pizzaslice or keyhole, etc. and I don't understand when to use which
@maths_50523 күн бұрын
Experience is a great teacher
@Unidentifying5 ай бұрын
what kind of master/specialization are you doing bro?
@maths_5055 ай бұрын
Astrophysics bro
@Unidentifying5 ай бұрын
@@maths_505 wow !! awesome, didn't expect that. Thought you would do pure math. I'm doing a very similar study, seeing your grasp you will do fantastic I'm sure.
@zab_5 ай бұрын
could you do it using Imaginary and Real parts of (e^i(x^2))
@RocketsNRovers5 ай бұрын
i loved it
@usmansaleem31735 ай бұрын
Nice ❤ Which whiteboard application you are using
@maths_5055 ай бұрын
Samsung notes
@usmansaleem31735 ай бұрын
@@maths_505 thanks for your help. Kindly rate the tablet good for teaching Wacom One Remarkable 2 Apple ipad pro Etc
@sciencelover-c2j5 ай бұрын
What is the same Integral but without limits ?? Can I use the UV method to solve it?
@marioangelov1135 ай бұрын
Both integrals have no elementary solution when they are indefinite.
@sciencelover-c2j5 ай бұрын
@marioangelov113 so ,can I solve it by udv ??
@marioangelov1135 ай бұрын
@@sciencelover-c2j No, they can be evaluated only as definite integrals (unless we use special functions). The classical methods of solving indefinite integrals (integration by parts, substitutions, etc.) do not work. Essentially this means that there are no elementary functions that we know, whose derivative is cos(x²) or sin(x²).
@sciencelover-c2j5 ай бұрын
@marioangelov113 That's mean when they come as indefinite (open integral ,no limits) ,we can't make integration for them?
@marioangelov1135 ай бұрын
@@sciencelover-c2j yes
@petterituovinem84125 ай бұрын
first
@prudhvi6345 ай бұрын
Second
@maths_5055 ай бұрын
Third
@Ghostwriter_zone5 ай бұрын
Fourth😂😂
@phylI5 ай бұрын
just had to solve them in my homework, solved using double angle formula🙃
@alex_bor5 ай бұрын
How would that work? Im a bit rusty but isnt the double angle formula for sin(A+B), not sin(A²)?
@phylI5 ай бұрын
@@alex_bor cos2A = 1 - 2sin^2(A)
@alex_bor5 ай бұрын
@@phylIsin²(x) is something different than sin(x²)
@phylI5 ай бұрын
@@alex_bor oh youre right, saw it wrong😅 I had sin^2(A)