The fresnel integrals solved using contour integration

  Рет қаралды 10,588

Maths 505

Maths 505

Күн бұрын

Пікірлер: 43
@CM63_France
@CM63_France 5 ай бұрын
Hi, "ok, cool" : 2:42 , 4:15 , 6:26 , 7:52 , 11:27 , 12:18 , "terribly sorry about that" : 8:53 , 9:16 , 11:09 , 12:52 .
@Dedicate25
@Dedicate25 4 ай бұрын
This is one of the comments of all time
@DaMonster
@DaMonster 2 ай бұрын
Very helpful, thank you
@HeyKevinYT
@HeyKevinYT 5 ай бұрын
I learned these integrals last week in my complex analysis course! My professor did the general case of the integrals from 0 to ∞ of cos ax² dx (call it I₁) and of sin ax² dx (call it I₂), with a > 0. This means I₁ + iI₂ = integral from 0 to ∞ of exp(iax²) dx (call it I₃). We then set up the same contour and path parameterizations that you did and obtained the expression for I₃, whose real part and imaginary part are equal = I₁ = I₂ = √2/4 * √(π/a), and the case of a = 1 gives the solution as in the video. A slightly different approach for the definition of f and still very elegant!
@edmundwoolliams1240
@edmundwoolliams1240 5 ай бұрын
This was how I first learnt how to solve them! 😊
@bandishrupnath3721
@bandishrupnath3721 5 ай бұрын
wonderful teaching sir
@maths_505
@maths_505 5 ай бұрын
Thank you my friend
@jorgelovaco7527
@jorgelovaco7527 5 ай бұрын
Beautiful beyond words 😍
@ikuyas5227
@ikuyas5227 5 ай бұрын
What app are you using? It looks super smooth.
@axeitor
@axeitor 5 ай бұрын
I think its the samsung notes app
@redroach401
@redroach401 23 күн бұрын
How do you know when to sue a specific contour because some have semi-circle or box or pizzaslice or keyhole, etc. and I don't understand when to use which
@maths_505
@maths_505 23 күн бұрын
Experience is a great teacher
@Unidentifying
@Unidentifying 5 ай бұрын
what kind of master/specialization are you doing bro?
@maths_505
@maths_505 5 ай бұрын
Astrophysics bro
@Unidentifying
@Unidentifying 5 ай бұрын
@@maths_505 wow !! awesome, didn't expect that. Thought you would do pure math. I'm doing a very similar study, seeing your grasp you will do fantastic I'm sure.
@zab_
@zab_ 5 ай бұрын
could you do it using Imaginary and Real parts of (e^i(x^2))
@RocketsNRovers
@RocketsNRovers 5 ай бұрын
i loved it
@usmansaleem3173
@usmansaleem3173 5 ай бұрын
Nice ❤ Which whiteboard application you are using
@maths_505
@maths_505 5 ай бұрын
Samsung notes
@usmansaleem3173
@usmansaleem3173 5 ай бұрын
@@maths_505 thanks for your help. Kindly rate the tablet good for teaching Wacom One Remarkable 2 Apple ipad pro Etc
@sciencelover-c2j
@sciencelover-c2j 5 ай бұрын
What is the same Integral but without limits ?? Can I use the UV method to solve it?
@marioangelov113
@marioangelov113 5 ай бұрын
Both integrals have no elementary solution when they are indefinite.
@sciencelover-c2j
@sciencelover-c2j 5 ай бұрын
@marioangelov113 so ,can I solve it by udv ??
@marioangelov113
@marioangelov113 5 ай бұрын
@@sciencelover-c2j No, they can be evaluated only as definite integrals (unless we use special functions). The classical methods of solving indefinite integrals (integration by parts, substitutions, etc.) do not work. Essentially this means that there are no elementary functions that we know, whose derivative is cos(x²) or sin(x²).
@sciencelover-c2j
@sciencelover-c2j 5 ай бұрын
@marioangelov113 That's mean when they come as indefinite (open integral ,no limits) ,we can't make integration for them?
@marioangelov113
@marioangelov113 5 ай бұрын
@@sciencelover-c2j yes
@petterituovinem8412
@petterituovinem8412 5 ай бұрын
first
@prudhvi634
@prudhvi634 5 ай бұрын
Second
@maths_505
@maths_505 5 ай бұрын
Third
@Ghostwriter_zone
@Ghostwriter_zone 5 ай бұрын
Fourth😂😂
@phylI
@phylI 5 ай бұрын
just had to solve them in my homework, solved using double angle formula🙃
@alex_bor
@alex_bor 5 ай бұрын
How would that work? Im a bit rusty but isnt the double angle formula for sin(A+B), not sin(A²)?
@phylI
@phylI 5 ай бұрын
@@alex_bor cos2A = 1 - 2sin^2(A)
@alex_bor
@alex_bor 5 ай бұрын
​@@phylIsin²(x) is something different than sin(x²)
@phylI
@phylI 5 ай бұрын
@@alex_bor oh youre right, saw it wrong😅 I had sin^2(A)
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