Рет қаралды 2,943
The mass of a simple pendulum bob is \( 100 \mathrm{gm} \). The length of the pendulum is \( 1 \mathrm{~m} \). The bob is drawn aside from the equilibrium position so that the string makes an angle of \( 60^{\circ} \) with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be
a. \( 0.49 \mathrm{~J} \)
b. \( 0.94 \mathrm{~J} \)
c. \( 1 \mathrm{~J} \)
d. \( 1.2 \mathrm{~J} \)
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