The Millennium Prize Problems I

Lecture by John Tate
Riemann hypothesis, Birch and Swinnerton-Dyer Conjecture, P vs NP
Source of the video and also further information on the topics can be found under:
(1) www.claymath.org/
(2) www.claymath.or...

[@xCorvus7x]

To anyone who is complaining about 'how boring this lecture was' and 'how bad an educator' the lecturer seems to be: Has it ever occured to you that the real problem here might be yourself, that maybe you cannot concentrate enough to follow, or that you might fundamentally lack the interest to do so?

[@acetate909]

What a stupid comment. Why would someone who "lacked a fundamental interest" in mathematics seek out and then watch an hour long lecture on it's most dense and complicated areas of study? People who have trouble concentrating generally don't click on 47 minute academic lectures when browsing KZbin. "Has it ever occurred to you" that this may actually be a subjectively boring presentation? There are much better lectures, articles, videos that cover the millennium problems.

[@kenichimori8533]

Degree eight equal problem four. This is law of identity two. b + c = 2x

[@dobeeeeval]

Yeah, I guess I expected something a little higher quality, given the introduction. Then he pulls out a projector lol.

[@jojojorisjhjosef]

Clearly you haven't seen the entire video.

[@dobeeeeval]

jojojorisjhjosef What would I have said differently if I had?

[@kenichimori8533]

Four total equal five deductive eight is axiom non eulidian geometry k+1=k-1=0n

[@Adivasilover10]

great mathematician

[@kenichimori8533]

類体において八問と四問は二千年を証明しています。八題を四題にするにはメルセンヌ数に関数を仕組むのであり8k-4k/2=k-1にすると証明されました。

[@kenichimori8533]

Problem Millennium 2k

[@LRahmanGrandUnifiedModelLRahma]

L. Rahman of Bangladesh have Proved 7 Millennium Prize Problem Dhanbari Collegiate Model School 99 Batch Notre Dame College Dhaka Islamic University Kushtia University of Dhaka MS in IT

[@kenichimori8533]

2000 がメルセンヌ数で証明されました。2^n-1=2^k-1=point zeros.

[@kenichimori8533]

Demonstration theorem

[@ayyythatguy]

Good content, but I get the message that the speakers were not excited to share. They made it painful to sit through.

[@siciidyaasiin8500]

I will solve them

[@imironman5763]

I'm waiting

[@kenichimori8533]

Millennium problem is kilo kash bytes problem.　2k

[@magnuswootton7368]

even just listing the prime numbers is an np task.

[@kenichimori8533]

Millennium/1k

[@kenichimori8533]

Mersenne millennium problem m2k

[@kenichimori8533]

Aleph-0n

[@Ub3rSk1llz]

when people say maths is boring, it's because of lectures like this. these kinds of people must be excised from the education system for the benefit of humanity. /soapbox

[@zzeuqdhd9598]

Vérifie, les zéro non triviaux l idée de cherché l angle @(s) de la série puisque F(s)=a(n)^2+b(n)^2)×e^i@(s) a(n)=la somme cosbln/n^a et b(n)=sinbln/n^a , sinbln2×F(s)=la somme sinbln2×cosbln(n)/n^a +isinbln2×sinbln(n)/n^a l application de la formule sinax ×sinbx=-cos(a+b)X+COS(a-b)X/2 de même sinax× cosbx= sin(à+b) -sin(a-b)/2 on trouve sinbln2×F(s)=la somme 1/2×n^a ×(sinbln(2n)+icosbln(2n) + la somme 1/2×n^a(sinbln(n/2)+icosbln(n/2) =2^a-1 × la somme 1/(2n)^a ×e^i(π/2-bln2n +1/2× la somme 1/n^a × e^-i(π/2-bln(n/2) =1/2^1+ib × F(s)×i + 1/2^1+ib ×-i×F($) d'où (isinbl2+1/2^1+ib)×F(s)=1/2^1+ib ×F($) puisque F($) série pour $=a-ib F(s)=la somme 1/n^a ×e^ibln(n) finalement F($)=(i×2^1+ib ×sinbl2 +1)×F(s) puisque a(n)^2+b(n)^2=F($)×F(s) d ou e^-i2@(s)=(i×2^1+ib ×sinbln +1) d ou @(s)=1/2×i × ln(1 + i×2^1+ib×sinbl2) d ou pour F(s)=0 équivalent @(s)=0 équivalent b= k×π/ln2 quelques soit k appartiennent N la remarque quelques soit un nombre premier P×π/ln2~P' égalité d un autre nombre premier

[@cheekymonkey3929]

Obvious ly✌️😂

[@kenichimori8533]

analysis∀

[@systempatcher]

This is so mundane and boring. Math is fun don't kill it!

[@quantumfeet]

boring!!!!!!!!!

[@magnuswootton7368]

its because you dont understand.

[@v6790]

@@magnuswootton7368 lmao

[@happylittlemonk]

No disrespect, this is the worst presentation I have seen. No wonder no one has solved it. They have to give me a million first to listen to this.

[@sanitakanca4704]

You think it's boring because you don't understand it and you lack the interest to do so.