The Specific Heat Capacity of Aluminium

In this video I demonstrate an experiment to determine the specific heat capacity of aluminium.
There are several ways of processing the data: One is just to determine the total energy added (current x voltage x time) and then divide it by the mass and the total change in temperature.
A better method is to take the time at which the temperature reaches two specific values (e.g. 20 degrees and 30 degrees) and then use those times to determine the energy added.
Alternative, a graph of temperature against time can be plotted: The specific heat capacity is then relative to the reciprocal of the gradient - for the best value, look for the steepest gradient section.
The experiment has a number of inaccuracies: The main one (heat loss) means that the value obtained is always greater that the actual value. You might like to think of ways in which the experiment could be improved.
You may also notice, it takes a while for the temperature on the thermometer to start increasing. This is because it takes a little while for the heat to spread through the block. For this reason, I left the experiment running after turning off the power supply, to give the final bit of heat time to reach the thermometer.
You may also notice a small systematic error with the ammeter: For some reason, at the end of the experiment, it continued to read "0.04A" even though there was no current. I'm not sure why this was, as it worked earlier on, although by the time I set the apparatus up it was already reading "0.01A".
Finally, I'm sorry about the reflections from the thermometer, which can make it a little hard to see the temperature at times. I didn't notice these at the time of recording, as they only became apparent when I zoomed in on the video afterwards.

[@mantosh56]

Damn this was quite helpful thanks for the vid ❤️

[@user-gw1uw5gp3m]

ток в конце эксперимента возможно связан с эффектом Зеебека)

[@Ghost-oh1vc]

*sped

[@riskirahmathia3694]

First xD

[@mantosh56]

Ok 🙄😑