The van der Waals equation | Khan Academy

[@belsanifrahim6428]

I really appreciate that they take less time to convey lectures unlike other teachers who makes 30 min video just for their profit and waste our time. It's sad that they do that. But I really respect all the teachers.

[@HerrFuuuu]

This was a very good explanation for something that went under in my process engineering class - greetings from germany :)

[@muskaanrohomaan783]

indeed

[@xinyansheng8028]

!!!also from Germany

[@tommyboy1653]

I felt a few pascal units of pressure on my mind on that one.😎😀

[@MasterCivilEngineering]

Good

[@pronambiswas2175]

A few times the pressure exerted by 76 cm of Hg(Mercury)😀

[@jamescaudry2300]

You should have been in my class when my teacher derived this from scratch. That's pressure.

[@AyanSayed]

Best teacher. ....thanku sir

[@MasterCivilEngineering]

One of the best equation in chemistry. This equation works like magic in chemistry

[@YouknowWho123]

Excellent explaination,sir

[@akshatparag2884]

I think ur videos ( especially physics) could be helpful to clear one's IIT jee in India

[@Rafiqul.Islam4]

Love from Bangladesh...🇧🇩

[@mishal81]

THIS IS SO GOOD! Thanksss

[@seachemistry]

Sal mate, you are such a good ducking teacher

[@So.expensive]

great explanation

[@Chamelionroses]

I will keep learning more. Thanks.

[@rahulchaurasiya2238]

Thanks

[@COOKINGWITHASHRIZ]

All videos very nice

[@mrbrian9438]

Exelente

[@MasterCivilEngineering]

Excellent

[@waqarghxuri]

Axilland.

[@wise_old_tree]

@@MasterCivilEngineering that's other language

[@pervinceferli7968]

Need love ur from india

[@kasparcersnakov6151]

Isn't the term "a * ( n^2 / V^2 )" due to surface effect (gas molecules near the surface of the container sense a net force towards the "inside of the volume", whereas the gas molecules "deep inside the volume" sense no net attraction since it compensates thanks to simmetry)? In that case... How is surface area taken into account in van der Waals equation? The container of the gas may be a ball, a cube, or a corrugated shape. Shouldn't that lead to different amounts of pressure reduction due to surface effect? Coefficient "a * ( n^2 / V^2 )" seems unrelated to surface area.

[@godspeed2124]

If the surface area is more then there will be more collisions happening near surface which will be proportional to n/v

[@thebeatdropbutton6354]

hey, why do you subtract directly from V, but indirectly from p (on the other side) ?

[@cursedstone7939]

If you get the answer for this, do tell me

[@Ramiro-c4o3k]

Because the volume V is still the volume of the conteiner, so, for it to be the real volume, where particles can actually be, you've got to substract the volume occuppied by the particles. However, the pressure P has been changed for the real pressure, therefore, for it to meet the ideal gas equation, we've got to rescalate it to the ideal pressure.

[@Chamelionroses]

That is interesting. Is there some way besides this you could do more on plasma? I am really curious if there is more on the topic than a playlist I created on that state of matter.

[@LastThai]

ah do you have video Explain how to find Van der waals internal energy ? I can't prove that it is U = U(initial)+cvT - a/v

[@noorafsa7168]

What happens if the pressure is 0?

[@mayanklucknow]

nice

[@WilliamShaksphere]

❤❤❤

[@Tom-t6k5x]

Hindi me boliye hum hindi medium se h 😊

[@이영석-m1s]

Is this enough for Korean middle school students to understand?

[@enabsfavour2700]

❤️❤️

[@kimberlycunningham5903]

hi

[@avatar5129]

Sorry sir, i wanna ask something. Why density (n/v)^2 ? not (m/v)^2? Sorry for my bad english, thx.

[@hanz4850]

I think we take concentration.. not density. That's why it is n/v. But I'm not sure because I'm also a student

[@COOKINGWITHASHRIZ]

😍

[@mohamedabdi5181]

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