Final Exams and Video Playlists: www.video-tutor.net/
@warryen4 жыл бұрын
So many The Organic Chemistry Tutor chrome tabs open..
@tomatrix75254 жыл бұрын
warryen cramming for finals, so many tabs of this dude open I opened a whole new chrome to make it easier to see...
@soso-zz9qf Жыл бұрын
from struggling over calculating empircal formulas in grade 11 to struggling over calculating ODEs in 4th year university, the struggle never ends but you remain the GOAT. Keep up the good work brother.
@priyanshusharma1812 Жыл бұрын
we have to solve ODEs in our first year 🥲
@DerangedIntellectual9 Жыл бұрын
@@priyanshusharma1812 second year for us
@sudasatoshi97699 ай бұрын
Yo why they got us doing this in our second year :(((
@teodormateitomuta74906 ай бұрын
Same@@priyanshusharma1812
@Breakerchannel15 ай бұрын
@@priyanshusharma1812 😂😂 ouch It's the second yesr for us
@GooperPooper2 жыл бұрын
My professor sucks at teaching this, you're out here saving lives right now.
@michal56423 жыл бұрын
The differences in teaching the same material differ from both teacher to teacher, but also country by country. In the Netherlands, they taught us this method in relation to the Wronskian and lin algebra. It is nice to see this different perspective as well to solidify the material thought to me.
@sharpnova23 жыл бұрын
sounds like the Netherlands teaches it stupidly
@jumalejumdin48282 жыл бұрын
😂😂😂
@debrachambers13042 жыл бұрын
They taught us with the wronskian too
@soham57182 жыл бұрын
we in india also been taught in the wronskian method
@ado4224 Жыл бұрын
Yikes looks painful for a beginner to grasp
@ado4224 Жыл бұрын
These tutor and some more visualisation based chanels are a gem to society.
@joeyGalileoHotto5 жыл бұрын
Just in Time! We have our DE final in less than 2 weeks and I HATED variation of parameters. You are the best! :)
@ahmedwael9943 жыл бұрын
waw mine is tomorrow
@dnzssrl2 жыл бұрын
mine is in 4 hours 😁
@MrPutin-gb1yx2 жыл бұрын
Mine in 2 hours😅
@nidhishsharma94712 жыл бұрын
mine is in 5 days, goodluck to everyone in the future
@I_Am_The_Pataphysicist2 жыл бұрын
mine is in 29min, damn what am I doing with my life?
@zackgrey44723 жыл бұрын
I wish there were more sample equations, these are so helpful!!!
@tomatrix75254 жыл бұрын
This just summarised a week of lectures, equivalent to like 15 hours
@cassandra-lynnecowley6475 Жыл бұрын
bless your beautiful soul for making variation of parameters much easier to understand!
@nicholegarcia1807Ай бұрын
I have been trying kahn and other videos but I feel I understand you the best. you break it down step by step. appreciate you sharing the knowledge
@chimetimepaprika2 жыл бұрын
I am just an average dude trying to go for math and physics and these videos have been helpful to keep me up with my peers!
@sebastianlahens77362 жыл бұрын
To me is crazy how me pay thousands of dollars to universities to take these courses, but we always end up coming back to the organic chemistry tutor to actually learn for free.
@easybeliever7 Жыл бұрын
You said it.
@YusuphaBah-bu7oh6 ай бұрын
Man makes complex things so easy to understand. Thanks
@viclociraptortheoneandonly22643 жыл бұрын
thanks so much for this, much easier when you explain step-by-step rather than comparing textbook to bare-minimum "example" vids teacher provides 👍
@FenjaminBranklin953 жыл бұрын
My professors from the University need to take a lessons from O-Chem Tutor for how simple his videos are. Quite sad and ironic that many of my Upper Division Professors were unable to adapt to Zoom and online teaching
@Benedict_Miriti2 жыл бұрын
Men you're my university education saviour. I owe you lunch.
@riteshrk183 жыл бұрын
How the Condition at 2:57 came? Is it Pre decided or Taught in Some else lecture Plz tell *Professor* ⚠️⚠️⚠️⚠️⚠️⚠️
@bubblemind33882 жыл бұрын
This inspires me to drop out of engineering school.
@ridesafealways49297 ай бұрын
Engineering school presents an easier format of DE compared. No need to write proofs.q
@derrickjoe18722 ай бұрын
At my school, everyone takes the same DifEq class. No difference, not even different options. @@ridesafealways4929
@kenniemozey22113 күн бұрын
Hey Did you drop out??
@KingInTheSoutha6 ай бұрын
At 1:29, why do we pick r1, and not r2? Could it have worked either way, meaning we can have two differing yc's? One where beta is 1 and another where beta is -1?
@georgesadler78302 жыл бұрын
Professor Organic Chemistry Tutor, thank you for another exceptional video/lecture on The Variation of Parameters in Calculus Three/ Introductory Differential Equations. The example in this video is a well-known problem in all of Introductory Differential Equations. Differential Equations books used Wronskians, to solve this exercise. Although Wronskians was not mentioned in the video, it is also used to solve the problem. This is an error free video/lecture on KZbin TV with the Organic Chemistry Tutor.
@ammontraeden79792 жыл бұрын
Have you thought about doing another example of one of these but using the Wronskian method? It has another concept to understand, but it makes problems like this take a bit less work and makes them a little easier in my opinion.
@mariakibtia59854 жыл бұрын
Why don't you use Wronskian formula to slove this?
@FenjaminBranklin953 жыл бұрын
Think he does without explicitly saying so. When he does the whole Product Rule of Primes, isn't it basically Wronskian?
@AradhyaAggarwal-yj6cq7 ай бұрын
This man is doing God's work
@Dailytech-bro6 ай бұрын
Watching this in 2024, your videos never get old. Thanks boss
@alexevans68035 жыл бұрын
Please make a video on how to solve DE’s with power series next!!!!!!!!
@no_respect_k_y_s Жыл бұрын
i just want to graduate and then probably will end my life i am just not eligible for this world, thanks for making my miserable life easier, liked and subbed so helpful
@easybeliever7 Жыл бұрын
Hey, don't say that. We all have our own problems going on in each of our own lives. But we can find hope in the midst of suffering. Faith in God, and specifically in His Son Jesus Christ gets me through tough times. Jesus died for our sins and rose again from the dead, so I know that by believing in Him I am forgiven for all of my past mistakes and free from the guilt of my sins. We can live with the assurance of life beyond the grave by believing in Christ. Please reach out to me if you need someone to talk to. God bless.
@p_dubbsssyt Жыл бұрын
for the first equation you made y_c wouldn't you have sin(-x)? since you have to still use -1i no?
@DKJhub Жыл бұрын
God bless you OCT, I'm writing a D.E paper in 30 minutes.
@unlowyer3 жыл бұрын
how did you obtain the c1cosBx+c2sinBx on 1:45
@salinalamasl2 жыл бұрын
When solving homogenous equations, there are three types of solutions. One of them is complex roots. That’s the given equation for complex roots whereby the only thing that changes is the alpha and beta. The layout of the equation is same in complex roots..
@allysam83066 ай бұрын
How does the u primes add up to zero when the sin and cosines aren't second derivatives
@Casa_Mia..3 ай бұрын
yea
@clearflow7925 Жыл бұрын
is the calc 3 playlist complete?
@amjedhamed82 Жыл бұрын
UR No.1 in the world 👏👏
@sailung10764 жыл бұрын
I understand this more than my professor's lecture .
@salinalamasl2 жыл бұрын
Can I ask why we are multiplying by wind and cosx at 7:28? Please and thank you!!
@Speed_Demon02 Жыл бұрын
I know I'm super late in your response, but the answer to your question is Systems of Equations. After multiplying the sinx and cosx, you're able to cancel the u1'cosxsinx.
@ApiolJoe2 жыл бұрын
Why was I not subscribed already? I know your channel for a few years now and I knew how good quality the content was. Pfff, at least it's corrected now.
@snmstudios96615 жыл бұрын
What is the software you use to make these videos? The drawing platform.
@mertgoksel354 жыл бұрын
smoothdraw4
@Hanakin-Sidewalker Жыл бұрын
The integral of -tan(x) is -ln|sec(x)| is it not?
@carultch Жыл бұрын
It is. With properties of logs, you can show that it is also +ln(|cos(x)|)
@albertesquer8467Ай бұрын
At 1:55 why was r1 used only and not r2 for the beta. r1=1 and r2=-1 ?
@him31anshu3 жыл бұрын
2:49 WHY that condition is applied? What's the reason? I know that is helpful to find U1 and U2 but why?
@sanjaysivapragasam37953 жыл бұрын
please i still dont know, does anybody know?
@him31anshu3 жыл бұрын
@@sanjaysivapragasam3795 Both U1 and U2 are unknowns, we have to eliminate them and write in terms of Y1 and Y2. Two unknowns, we are free to apply to conditions. That's is why it is chosen in such a way that it will eliminate the unknowns. Beautifully explained in book SL Ross
@mfundisombhokane30525 жыл бұрын
I have been waiting for this. THANK YOU 👊
@leovc21274 жыл бұрын
Really helpful, thank you!
@sotadern19 күн бұрын
how do i proceed if its order 3? which parameters should i set to 0 while deriving y_p?
@SeadaUmer-cy7cn Жыл бұрын
Thanks God blessed you
@SeadaUmer-cy7cn Жыл бұрын
Amin
@oswaldmahabi93903 ай бұрын
If there was a cot x instead of a sec x, then how can we find the values of U1 and U2 in elimination process.
@nick45be10 ай бұрын
Why in 2:41 you write down that condition U1'y1 + U2'y2 = 0?
@abdulhadikseibi9404 жыл бұрын
At the integration step , you integrated without adding a constant c , wouldn’t that create a problem in the solution? Thank you.
@anasbouhafs89924 жыл бұрын
According to me there should be arbitrary constants in there. When I plug in random values those also yield the same solutions.
@ved30554 жыл бұрын
Exactly what I thought but then I realized, when you add yp and yc, the constant term is added from there already, so just assume it as a total constant
@zyankarim5444 жыл бұрын
since c1=u1 and c2=u2 according to 2:54, can they be written as c1=lncox and c2=x in the final solution?
@skepticmoderate57904 жыл бұрын
They're not equal. You must replace the constants with functions of x for variation of parameters.
@lordhazimuka52324 жыл бұрын
Is that condition u1"y1+u2"y2=0 for all Variation of parameters, or was it just for this question?
@sorenezung58753 жыл бұрын
Assuming that u'y1+u2y2=0 because we hve two unknown i.e u1 and u2 but our original differential equation is 1 equation , So inorder to get an equation for the the unknowns
@collegestudent60714 жыл бұрын
Did I miss a video on this? Or is this his only video on VoP?
@physicsdepartmentuniversit8770 Жыл бұрын
your video's are really nice
@Jason-ot6jv5 жыл бұрын
Isnt this supposed to have a wronskian involved somewhere? im confused :S
@verrawar79065 жыл бұрын
Yes u r correct
@abassusarma90242 жыл бұрын
Please what app do you use for this recording?
@AnirbanBanerjeeBPS2 жыл бұрын
Nice explanation
@allenhirahara2242 Жыл бұрын
Thank you~ You are a life saver~
@سبحانالله-ق9ز8و2 жыл бұрын
What application you used to make these videos ?? Please any one can tell me
@Pages_Perfected4 жыл бұрын
I was waiting for the second example bcs the first one have imaginary nums LOL
@mattstormtornado Жыл бұрын
Extremely helpful. How would I solve an equation in the form ay''(t) + by'(t) + cy(t) = dx'(t) +ex(t)?
@carultch Жыл бұрын
Rearrange it to standard form, which is a trivial step: ay''(t) + by'(t) + cy(t) = dx'(t) +ex(t) a*y"(t) + (b - d)*y'(t) + (c - e)*y(t) = 0 Now it's just a second order equation with constant coefficients. b-d becomes the new B, and c-e becomes the new C. a*y"(t) + B*y'(t) + C*y(t) = 0 Assume an ansatz of y(t)=e^(r*t). (a*r^2 + B*r + C)*e^(r*t) = 0 Solve for two values of r, and construct a linear combination r1 = (-B - sqrt(B^2 - 4*a*C)/(2*a) r2 = (-B + sqrt(B^2 - 4*a*C)/(2*a) In the case that both r1 and r2 are real and distinct: y(t) = K1*e^(r1*t) + K2*e^(r2*t) In the case that r1 = r2, call it r: y(t) = K1*e^(r*t) + K2*t*e^(r*t) In the case that r1 and r2 are complex conjugates: y(t) = e^(Real(r) * t) * (K1*cos(imag(r)*t) + K2*sin(imag(r)*t))
@lilyr94958 ай бұрын
what a beautiful problem and method
@keyndomfloyd783425 күн бұрын
Why does sin(x) + cos(x) =0 and cancel out
@nameerammar80706 ай бұрын
Bro is the only one who is holding me up in university
@ably21096 ай бұрын
Yeah i am gonna repeat this course
@m-squaredfibonacci64834 жыл бұрын
What software are you using to make such videos?
@k.oblack.7196 Жыл бұрын
Big love Mr...
@ahmedmghabat79823 жыл бұрын
Can i consider those equations as undetermined coefficients?
@ChasinNorthernLights2 жыл бұрын
No that has a seperate video i guess
@gian82514 жыл бұрын
this whole thing is confusing
@jamesmcclain50054 ай бұрын
Now when you add Power Series, Bernoulli Equations, UC Functions, Laplace Transforms, Separable Differential Equations, Integrating Factor, you end up with a very hard class.
@adveshdarvekar7733 Жыл бұрын
but there is a formula to find u1 and u2 directly without this process. Can you share that
@easybeliever7 Жыл бұрын
I think it is the Wronskian method
@zlecklamartv87565 жыл бұрын
PLEASE MAKE AN INTEGRATION VIDEO
@dom67609 ай бұрын
Sir where is the first order? I can't find it anywhere😭
@jevcampbell23014 жыл бұрын
LOL i lasted till the 8 minute mark before i was lost lol the power of an Eng Sci student :')
@qingyuanwu4 жыл бұрын
Have you tried Davis' lectures? It's SO helpful
@gwenith67632 жыл бұрын
@@qingyuanwu davis explains things so well. i LOVE his teaching style
@justinernest68812 жыл бұрын
what if the given differential equation is of order greater then 2?
@carultch Жыл бұрын
The methods of second order diffEQ's still works, you just need to solve a cubic formula instead of a quadratic formula. You'll also need second derivatives to construct the third row of the Wronskian, and you'll evaluate sub-Wronskian determinants. As an example (I'll just show an arbitrary function g(t), since it's very difficult to come up with examples that can be practical to do): y'"(t) +7*y"(t) + 14*y'(t) + 8*y(t) = g(t) Assume a solution of y=e^(r*t), for the homogeneous equation (r^3 + 7*r^2 + 14*r + 8)*e^(r*t) = 0, Since all the signs are positive, this means there cannot be any positive roots, unless accompanied by an equal and opposite negative root. The rational roots theorem, tells us that -8, -4, -2, and -1 are all possible roots, as well as their positive counterparts. Trying -4, -2, and -1 will produce our three roots. This means our homogenous solution is the following combination: yh(t) = A*e^(-4*t) + B*e^(-2*t) + C*e^(-t) Calculate the Wronskian of these three solution components. The underscores are just placeholders to help me align. | ___e^(-4*t), ___e^(-2*t), e^(-t) | | -4*e^(-4*t), -2*e^(-2*t), -e^(-t) | = W = 6*e^(-7*t) | 16*e^(-4*t), 4*e^(-2*t), e^(-t) | Then we evaluate the Cramer's Rule Wronskians, by replacing each column, with a column of zeros and a 1 in the final row: W1 = | 0, ___e^(-2*t), e^(-t) | | 0, -2*e^(-2*t), -e^(-t) | = e^(-3*t) | 1, 4*e^(-2*t), e^(-t) | W2 = | ___e^(-4*t), 0, e^(-t) | | -4*e^(-4*t), 0, -e^(-t) | = -3*e^(-5*t) | 16*e^(-4*t), 1, e^(-t) | W3 = | ___e^(-4*t), ___e^(-2*t), 0 | | -4*e^(-4*t), -2*e^(-2*t), 0 | = 2*e^(-6*t) | 16*e^(-4*t), 4*e^(-2*t), 1 | The particular solution will become: yp = yh1(t) * integral g(t)*W1/W dt + yh2(t) * integral g(t)*W2/W dt + yh3(t) * integral g(t)*W3/W dt Implementing what we have: yp = e^(-4*t) * integral [g(t)*e^(+4*t)/6] dt + e^(-2*t) * integral [1/2*e^(+2*t) * g(t)] dt + e^(-t) * integral [ 1/3*e^(t) * g(t)] dt The general solution would therefore be: y(t) = A*e^(-4*t) + B*e^(-2*t) + C*e^(-t) + e^(-4*t) * integral [g(t)*e^(+4*t)/6] dt + e^(-2*t) * integral [1/2*e^(+2*t) * g(t)] dt + e^(-t) * integral [ 1/3*e^(t) * g(t)] dt I'll leave it as an exercise to you, to come up with a non-polynomial / non-trig / non-exponential case of g(t), that makes these possible integrals to do.
@munchy_monkey2483 жыл бұрын
Hi. If the question is tanx instead of secx, what do you recommend we do to find u1' and u2'?
@arshsheikh9353Ай бұрын
i love u man
@levied89704 жыл бұрын
7:27. you dont really explain why you chose to multiply by sin or cos
@tyromejenkins24424 жыл бұрын
He's using the algebraic method of solving a system of equations, the Elimination Method. First step in this method is to multiply the two equations in a system by terms such that a term repeats, therefore, you can eliminate the term by adding/subtracting both equations.
@SwagDawg3 жыл бұрын
@@tyromejenkins2442 Wow thank you, that was a great explanation
@jj.wahlberg4 жыл бұрын
I got an Amy Schumer Tampax ad in the middle of this video 😫
@jacksonmadison99949 ай бұрын
Wronskian method is easier v1' = w1 / w v2' = w2 / w integrate to get v1, v2 yp = v1y1 + v2y2
@abdullahsam17603 жыл бұрын
Can Anyone tell me how to write Yp ?
@spookybrojo71863 жыл бұрын
You saved me
@jisancy54232 жыл бұрын
(8) clear
@habibrifiagznay10632 жыл бұрын
Thank a lot
@nigotheboss3 жыл бұрын
5 seconds into this video: Nah bruh, imma drop out
@erzcav47934 жыл бұрын
Thank you so much!!!!
@NewyearCute2 ай бұрын
Thank you
@KibetEnock-f2l2 ай бұрын
Thanks so much sir Ur taking tiz degree home
@typhwomp7686 Жыл бұрын
literally the goat
@kaantapan34554 ай бұрын
Thanks😁
@regnaldmtei33194 жыл бұрын
more amazing toturial
@TheStrossicro2 жыл бұрын
this is insanely hard compared to separation of variables etc
@jackbenner1013 Жыл бұрын
My first Diff Eq exam is in one hour
@awildmoosey5 жыл бұрын
Variation of Parameters > Undetermined Coefficients
@jj.wahlberg4 жыл бұрын
Ugh no. Variation of parameters is more versatile but it’s also more complicated
@RagingBrohemoth44 жыл бұрын
lol, more like last case scenario
@RagingBrohemoth44 жыл бұрын
Separation by variables>integrating factor>undetermined coeffiecients>variation of parameters... fact
@Ilmard994 жыл бұрын
Not among your best tutorials imo
@ibrahimmuhammad907 Жыл бұрын
You are too fast slow down 😭for people to digest in the equations
@diamondninja4938 Жыл бұрын
Wronskian Gang rise up.
@azellahramos5437 Жыл бұрын
the shortest shortcut 🥵
@kleenexpresslaundrette22184 жыл бұрын
but u can use the formula just plug in
@marcelgunadi24293 жыл бұрын
This lecture was confusing for me
@josephpugh1331Ай бұрын
you are the goat
@Pages_Perfected4 жыл бұрын
I watched 6 ads in 11:35 minutes like how much time did i waste ?
@hemantdevkota85873 жыл бұрын
why u1'y1+u2'y2 = 0 only why it cannot be a any function.