Clausius Clapeyron Equation Examples and Practice Problems

[@TheOrganicChemistryTutor]

Final Exams and Video Playlists: www.video-tutor.net/

[@thatannoyedbeing4751]

Someone that finally tells me how to use the equations instead of the theory behind it

[@nuclearrambo3167]

I would like to know whereby that equation is derived

[@hdgamerz7623]

@@nuclearrambo3167 ight lil nigga... ur done😭

[@marcmacchiaverna5509]

This guy is good. calm. good pace. clear. Thanks for lending your talents.

[@Thebestcoldkilla]

I just wasted 30 minutes trying to read and figure out how to do this and here you come again saving me with epic 20 second explanation, Thank you so much!!!

[@egemeyvecioglu3165]

My body gets filled up with peace every time i watch one of your videos.

[@hopeherren5044]

You have literally helped me in Calculus 3 and Chem II. You're amazing.

[@briann5144]

I have a midterm tomorrow, and this is way better than my professor teaching it in over an hour.

[@graceremo5724]

Hello Brian, can you please teach me how did he get 28.6 torr? :(((

[@rominnoodles]

@@graceremo5724 he did 21 times e raised to 0.31037

[@freddymendoza9393]

You help me with Calculus AND Chemistry? What can't you do? Lol

[@garrettludescher9588]

show his face

[@IbnFulan]

History

[@trentjones8220]

Organize his videos so they follow any kind of curriculum

[@kwames.8411]

I LOVE YOU CHEM BAE

[@Mary-eu6bm]

Thank you so much. I kept seeing different formulas and never understood why it changes, I was so confused. You are the only one that explained this!

[@caitygart]

Thank you sooo much for explaining how to deduce the unknown variable mathematically...my professor is excellent but conveniently skips over these parts so I either have to go in for tutoring or am stuck. This really helped, as usual. You rock!

[@FlipperBee9368]

You've just saved me, i have my exam in two days and i was STRUGGLING with Clausius 😭😭😭 thank you so much

[@montypizzle5780]

Thank you so much. If only my professor explained things half as well as you do.

[@YellengSolomon]

You are the best tutor in chemistry thank you❤

[@greyeyedone_2119]

Great video.....started this in class today..... Thank you for making this topic easier to understand 📚👩🏽‍💻🤓

[@ziyadatulilma4]

Thank you so much mister. From this channel i can learn for my olympiade contest 😭

[@erzas556]

Thank you, but how do we calculate for T1 if we only had the pressure and the enthalpy of vaporization?

[@kimberlydavis7322]

your videos are truly life saving!!

[@wettersocks]

Yezzirrrrr ! Took my forever to get my answer correct finally got it after this video.

[@NZIT1]

Hi, I just wondering how did you get p2= p1.e^(-dh/R).(1/t2-1/t1)? if ln(p2/p1) = lnp2- lnp1. how is it possible when P1 changed the side has multiplied by e^(-dH/R).(1/t2-17t1)? . Thanks very much Sir.

[@kkarwoski]

You rock! If I get a great grade on my test, I'm going to owe it all to you

[@kaseythompson353]

How did you get the -2.9737 from dividing this? I am confusion.

[@fluffandstuff6089]

THIS MAN IS THE BEST OH MY GOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[@AddixXxion]

i don't know why, but not even my teacher could get me to understand this bs, thanks bro!

[@dunkelbier6414]

Thank you so much, you really helped me out, greetings from Mexico!

[@brianaranda2831]

Why is R negative when solving for enthalpy of vap? When I convert the original equation I have a positive R

[@noahgarcia8888]

Thank God that you and this video exist!!!!

[@Bilbus7]

Noah Garcia god is make believe.

[@johnbaute5916]

I tried to solve for T2 a bunch myself...and failed. It's been 30 years since I had to do this. Lots of searching for this came up empty. Thank you.

[@adnysh3144]

I have a question. If the pressure given in pascal, do we have to change to torr?

[@CSReeves987]

One pascal is equal to 0.00750062 torr

[@adnysh3144]

@@CSReeves987 so we must use torr as the unit. Just continue calculate in pascal cannot?

[@ritangambi5513]

Same method of calculating though we are using the R constant as 8.314 giving me a final answer of 22

[@jontober4381]

YOU MADE THIS SO EASY THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!

[@rootlocker197]

If I have a child I will talk them you're legend.

[@RohitSharma-yw4iv]

Here in the equation, we have an enthalpy of vapourisation and we have two state 1 and 2. So which latent heat should we need to consider state 1 enthaply or state 2 enthalpy. Please help me in this doubt.

[@julienalexander6113]

Thank you so much, man

[@Nikola.Tesla369]

Thanks

[@Kuasarsama]

Gracias bro joder

[@ehiagheonakinor7149]

How can I solve for boiling points at different pressures?

[@KelticLegend]

you saved me AGAIN. thank you.

[@74dorset]

Thank you Chemistry Bae

[@Russo-cy5pg]

You are a lifesaver! Thank you

[@noordurrh5306]

Thank you soooo much ,God bless u🤍

[@AJ-et3vf]

Great video. Thank you

[@stupidliving6272]

this really helps a lot

[@Airraca]

So question... How to know whether to use the very first (base equation) and when to use the other equation to find another pressure. The questions look the same when I looked it up.

[@corey5454]

I got 20.3 torr for the question. How did you get 28.6 torr?

[@saurabhpatil5487]

Good explanation

[@rosseddins3510]

How do you raise it the negative 1 power to get kelvin? Im working with a Ti-30xa Calulator.

[@shougnaljasmii9791]

Thank you so much, all clear

[@o_kneepixel]

Very helpful! Thanks

[@rusulhasan1243]

thank you so much !!!you are a life saver

[@Feranmitrillions]

What of the case that we have the formula as InP=-∆H(1/T)/R + C for graphical function

[@Feranmitrillions]

Is it correct or wrong, Pls Explain

[@ralghahhallas2460]

Is there a equivalent formula that describes the transition in between liquid to supercritical states?

[@pethiasmusunka9940]

So helpful ! Whats the tutor`s name please?

[@christophermassari2241]

very good thank you so much

[@abubakrialliy3350]

The molar heat of vapourisation of water is 9700cal/mol, what's the vapour pressure of 5 moles of water at 90°C (given that vapour pressure of 1 mole of water at 100°C is 78mmHg and the gas constant is 1.987cal/mol. Someone should please help with this question.

[@MrDrProfPatrick]

Isn't the enthalpy of vaporization changes depending on the temperature? How come there is just one value of enthalpy of vaporization between two different temperatures?

[@gelomelo3426]

Thank you so much 🌹 ❤

[@mateofranco4612]

Can pressures also be taken as atmospheric pressures?

[@abdulabdullah653]

Thank you so much

[@Jellly_bean]

So when using the equation to find P2, the exponents to "e" are all divided by R? He found T2-T1, then multiplied by 24000 (Hvap), THEN divided by R. However, the equation was written as Hvap/R * (1/T2-1/T1)... Our tutor found 1/T2-1/T1, multiplied by Hvap, then divided by R, which would be (Hvap*(1/T2-1/T1)) / R as the exponent to e ... if someone can clarify that would be super helpful! Thx!

[@luisfernandohernandezlopez662]

you are a ver help! thanks for the T2 clearance :)

[@celinearas]

Thank you.

[@stocktonoviatt9638]

How did you get from [3.7026x10^3]^-1 to 270K?

[@Love-wy8pf]

On your calculator there should be a button that says (1/x). Click that and you’ll get the same result.

[@angieknows08]

@@Love-wy8pf chem made me realize that idk how to use a calculator

[@mayyousayhd5967]

R is multiplied by 2.303 or is it?

[@darraghbuckley3884]

Wrong R value for the first problem? We are using torr so shouldn't R = 62.36 L*torr / (K*mol)

[@haolekegs696]

How do you determine which pressure is either P1 or P2?

[@danielb6281]

P1 is the pressure at the start with T1. When you change either P1 or T1 it becomes the second parameter of its kind. If you cange the temperature, the temp. you change it to becomes T2 with its own pressure P2

[@senalilvanya]

Thank you soooooo much!!!

[@Anthony_Molosi]

Thank you

[@byronescobar7863]

Thanks!!

[@khinetun340]

You’re the best!!!

[@karwinchau4684]

I dont understand how you got 1/310= 3.2*10^-3? I got 0.003225

[@ronaldobarrientos8259]

como se pone en la calculadora para que salga 3.70263x10ex-3 y tambbien 270.1k

[@alejandroleal8801]

Nice video dude

[@cailinduffy1479]

What is e?

[@graceremo5724]

same question huhu

[@markcervantes706]

Can some one explain to me how i got 21.66 torr instead of 28.6 at 7:03

[@selinebre]

I was wondering the same thing tbh

[@mondimaggie7917]

Thanks🤩🤩

[@dsolis7532]

Is the same equation all the time... Why you called different forms of the equation?

[@AG-xi8mn]

so helpful!!

[@JamesM517]

at 6:50 how did you determine the e value?

[@Faulheit]

calculator

[@daniellige5311]

e is a constant my dude: 2.718...

[@draegoabdurrahmanlesmana1620]

3:06

[@loudenmoran3883]

you are clutch

[@ZiadAmerr]

1 kJ is "about" 1000 J? ABOUT???

[@brajeshsharma3456]

very helpful so I like it

[@vajahatbukhari9251]

Hi I've watched your videos and I've a question. I've examination in physics about a vacuum boiling water experiment by manipulating the pressure to a low point so the water in the bowl starts boiling at a low temperature. I've tryed to find some table or calculator that can somehow demonstrate that the result I've found is close to what we can see in tables eg. Are there any calculators (tryed to find some but they didn't work) or law that I can refer to? I hope that you can help? Best regards Mowaddat

[@jacopobaccarin7623]

It'd have been smarter to show the passages from the first formula to the others, and not giving all the formulas like they are different. What's the sense of learning all of them, you just need the first and you need to know how to reverse it. but yeah, just my opinion

[@william-abel]

Isn’t it p1/p2

[@Cheekybaby4]

Wait I still don't understand...

[@patrickmutch6875]

🙌🏾🙌🏾🙌🏾 respect

[@ernestoruestarojas5552]

GRACIAAAAAAAAASSSSSS

[@hermannklein-hessling7612]

Is this still high school level or undergrad?

[@komunist_kedi]

Hermann KLEIN-HESSLING undergrad

[@dhruvkhatri3590]

nice

[@thayhh02]

Thanks....

[@israelbattle5997]

Wait a minute what is C

[@Busting_Dat_Nut]

The Clapping Cheeks equation

[@alokikverma]

Gyanesh se kisko nhi smjha fitjee jha2

[@kaanakyuz7402]

what is 'R' at there ,ı dont know cause this vid is not in my language

[@kaanakyuz7402]

hm okay raydberg constant

[@gabor6259]

@@kaanakyuz7402, it's not the Rydberg constant, it's the universal gas constant.

[@ozkansolmazjr]

R is called the ideal gas constant or universal gas constant ; R=8.314 J/mol or it can be R=0.08206 atm*L/mol*K

[@tioco12]

Really thought the R was the gas constant. Now I know why I failed my test :(

[@910suck]

IT IS gas constant, not the universal gas constant.

[@danielb6281]

@@910suck What do you mean? The R he used in this video was the universal gas constant (8,3 J/K mol).

[@dylant830]

holy shit I hate chemistry

[@grace.florejost4611]

urgh am I the only nerd who gets mad when ppl say a kilo joule s ABOUT 1000 joules No it is EXACTLY 1000..

[@srv1v342]

Claucius is my ancestor. It’s pronounced Claw-Shus