Electric Field Due To Point Charges - Physics Problems

[@TheOrganicChemistryTutor]

Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections Full 87 Minute Video - Part 1: bit.ly/3ZfWyUU Full 73 Minute Video - Part 2: bit.ly/3WVnl7u

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00:05 Electric fields can be calculated using the formula F/q. 02:42 The electric field created by a point charge can be calculated using an equation. 08:22 The direction of the electric field can be determined based on the charge. 11:01 The direction of the electric field is due south. 15:47 The mass of the charge is approximately 0.255 18:05 An electric field can suspend a positive charge with a specific mass. 22:30 The electric field created by a 40 microcoulomb point charge placed at the origin is 14.4 kN/C at a point 5 meters away. 24:36 The electric field at point p is 1472.88 to 1476.16 29:01 The electron accelerates in the opposite direction to the electric field 31:14 The final speed of the electron is approximately 8.39 × 10^6 meters per second 35:51 The net electric field is 18 million. 38:07 The net electric field at point b is larger due to the closer distance and larger charge magnitude of q2. 42:41 The magnitude of the new electric field will be greater than 100 newtons per coulomb. 45:06 Electric field doubles when the magnitude of the charge doubles. 49:44 The net electric field at point A is not zero, but it is due to the combination of electric fields created by Q1 and Q2 51:46 The net electric field at point c will be directed east. 56:17 The net electric field is zero and e1 is equal to e2. 58:32 The exact location along the x-axis where the net electric field is zero can be calculated.

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