Remainder Estimate For The Integral Test

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The Organic Chemistry Tutor

The Organic Chemistry Tutor

Күн бұрын

This calculus 2 video tutorial explains how to find the remainder estimate for the integral test. It also explains how to estimate the sum of the infinite series using the partial sum and using the remainder estimation theorem for the integral test and confirming the answer with the calculator. This video also explains how to find the number of terms for the estimate to accurate within 0.005.
Improper Integrals:
• Improper Integrals - C...
Converging & Diverging Sequences:
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Introduction to Series - Convergence:
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Divergence Test For Series:
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Integral Test For Divergence:
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Remainder Estimate - Integral Test:
• Remainder Estimate For...
P-Series:
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Limit Comparison Test:
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Пікірлер: 48
@TheOrganicChemistryTutor
@TheOrganicChemistryTutor Жыл бұрын
Next Video: kzbin.info/www/bejne/rmeVYqWqftyVlZY Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Math & Science Videos: www.patreon.com/mathsciencetutor/collections
@georgesadler7830
@georgesadler7830 2 жыл бұрын
Professor Organic Chemistry Tutor, thank you for explaining the Remainder Estimate for the Integral Test in Calculus Two. I am somewhat confused on this estimate for the Integral Test; however, doing problems is the best way to increase my understanding of the material. This is an error free video/lecture on KZbin TV with the Organic Chemistry Tutor.
@muhsinkhalif3621
@muhsinkhalif3621 4 жыл бұрын
thanks man! we appreciate your efforts a lot and God bless you!
@shayorshayorshayor
@shayorshayorshayor 5 жыл бұрын
"this might take a hot minute"
@darkducky2
@darkducky2 5 жыл бұрын
"This might take a hot minute" 12:45 lmao you right. thanks!
@cornetapluspluseleven9296
@cornetapluspluseleven9296 5 жыл бұрын
what kind of calculator are you using? I entered the expression sum(1 / x^2, x, 1, 1e6) // sum from one to a million in wolfram alpha and it took about three seconds.
@eduardomoreira7624
@eduardomoreira7624 4 жыл бұрын
😭😭
@bobingsonbob8893
@bobingsonbob8893 3 жыл бұрын
​@@cornetapluspluseleven9296 Or if you know a bit of code and are on a computer, you can write an easy for loop and accumulator and it'll go far faster than any calculator (provided you aren't on a dinosaur of a computer, my time for the exact summation that he was doing was .756 seconds just on a basic ass loop).
@MultiMathtutor
@MultiMathtutor 5 жыл бұрын
In part d) you find that n>200. But in part c) the sum is bounded to within 0.005 (the maximum of 1.649768-1.64522 and 1.64522-1.640677) so in fact only 10 terms are needed. To ensure an error less than 0.005 the remainder estimate says that you need more than 200 terms, but part c) says you need only 10. I think it would be good to explain that n>200 only ensures that the error will be less than 0.005 but it doesn't say how much less. If you were to compute the error in part c) with n=200 it will be much less than 0.005.
@kyokokirigiri166
@kyokokirigiri166 4 жыл бұрын
Saving us again god bless❤️
@hermione._.w
@hermione._.w 3 жыл бұрын
Why when you raise both sides to the power of negative 1 you don't switch the inequality sign also?
@JamesBrodski
@JamesBrodski 2 жыл бұрын
Thank you for making this video. It is great!
@ueda6512
@ueda6512 7 ай бұрын
this guy is amazing!
@MhamadSoubhiKhalil
@MhamadSoubhiKhalil 2 жыл бұрын
Shouldn't we flip the inequality when we raise both sides by -1? 15:34
@erikdahlen9140
@erikdahlen9140 2 жыл бұрын
no?
@selfwunder
@selfwunder Жыл бұрын
@@erikdahlen9140 yeah we should it's basic math
@spencerkimball7450
@spencerkimball7450 4 жыл бұрын
The last inequality is giving me some trouble. 0.005
@allie7049
@allie7049 4 жыл бұрын
you're right! the sign should have been switched because he took the inverse of both sides of the inequality. so n should be greater than or equal to 200 :)
@robertoberidojr.435
@robertoberidojr.435 3 жыл бұрын
I also noticed that one
@albertlegaspi9614
@albertlegaspi9614 3 жыл бұрын
Recall 1/(n+1)=200 and n>=199....so to satisfy both it should be n>=200
@zachb9440
@zachb9440 Жыл бұрын
@@albertlegaspi9614 actually appreciate this explanation - it actually showed the error he made (which was not just forgetting to flip the sign)
@toddholmes594
@toddholmes594 11 ай бұрын
Not my favorite video feels like there could be a better structured explanation. Love your videos btw.
@DerzTheCheeseStick
@DerzTheCheeseStick 6 жыл бұрын
For part D, shouldn't you solve 1/n < 0.005 instead of 0.005
@kamves8822
@kamves8822 5 жыл бұрын
It can go either way, 1/n < .005 , deviding n to the right, then deviding .005 from .005n to the left is the same as .005 < 1/n being powered by a negative 1
@pheonix6553
@pheonix6553 Жыл бұрын
@@kamves8822 If you devidde the left side by n you get 1/n^2 not 1
@zlatanibrahimovic8329
@zlatanibrahimovic8329 3 жыл бұрын
for part d the video is wrong, you have (integral from n to infinity) > Rn, then you know that if 0.005 > (the integral from n to infinity) then the error must also be less than 0.005. so work out the integral, assuming it's 1/n, you would work with 0.005>1/n>Rn and this is true for n>1/0.005 = 200, so n > 200.
@lanefrasier6214
@lanefrasier6214 6 жыл бұрын
Would the inequality switch as you take the reciprocal of both sides?
@zomboy33
@zomboy33 6 жыл бұрын
Yes
@aydengertiser4346
@aydengertiser4346 4 жыл бұрын
Cool fact: that infinite series (1/x^2) actually converges to pi squared over 6
@eduardomoreira7624
@eduardomoreira7624 4 жыл бұрын
Never knew
@warwick802
@warwick802 2 жыл бұрын
The inequality doesnt change in part d, if you multiply both sides by n and divide both sides by 0.005 you should get n
@scitwi9164
@scitwi9164 6 жыл бұрын
Nice :> Now I can approximate the Zeta function that way :)
@prateeksharma5539
@prateeksharma5539 4 жыл бұрын
15:43 you raised the negative power without changing inequality ? Are you kidding???
@kaddanki096
@kaddanki096 Жыл бұрын
Goated Video
@baharsalman3439
@baharsalman3439 Жыл бұрын
Allah razı olsun, God bless you
@lucasargandona4658
@lucasargandona4658 4 жыл бұрын
Why does the inequality sign change around 15:00 ?
@kasungimhana3640
@kasungimhana3640 6 жыл бұрын
Very understandable
@jordanmain7453
@jordanmain7453 6 жыл бұрын
thank you so much!
@gaspell
@gaspell 3 жыл бұрын
thank you
@candacehuynh5942
@candacehuynh5942 Жыл бұрын
thank you :]
@cringy7-year-old5
@cringy7-year-old5 9 ай бұрын
actual answer is exactly pi^2/6
@robertoberidojr.435
@robertoberidojr.435 3 жыл бұрын
Isn't it confusing that n should be greater than 200 cause 1/n should be greater than 1/200?
@druwprods6587
@druwprods6587 4 жыл бұрын
i love you
@guymorag8380
@guymorag8380 8 ай бұрын
I don't get it
@katieyoner5522
@katieyoner5522 6 жыл бұрын
you're a fucking gem man
@PoonsYungv
@PoonsYungv 2 ай бұрын
Why are yall quoting “hot minute” what’s so crazy about that?
@김지혜-t8o8z
@김지혜-t8o8z 4 жыл бұрын
목소리 존나 좋다
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