Power Dissipation In Resistors, Diodes, and LEDs

This electronics video tutorial explains how to calculate the power dissipation in resistors, diodes, and LEDs or light emitting diodes. The power dissipated in a diode is equal to the voltage across it multiplied by the electric current flowing through it.
What Is a Diode?
• What Is a Diode?
Full-Wave Bridge Rectifiers:
• Full Wave Bridge Recti...
Voltage Multiplier Circuit:
• Voltage Multiplier Cir...
Light Emitting Diodes:
• LEDs - Light Emitting ...
Power Dissipation In LEDs & Diodes:
• Power Dissipation In R...
LED Resistor Value:
• How To Select The Resi...
________________________________
Potentiometers - Variable Resistance:
• Potentiometers - Basic...
LED Dimmer Circuit:
• LED Dimmer Circuit - B...
Thermistors - Temperature Sensors:
• Thermistors - NTC & PT...
Zener Diodes:
• Zener Diodes
Voltage Regulators - Zener Diodes:
• How To Make a Voltage ...
Zener Diode Solar Cell:
• How To Make a Solar Ce...
________________________________
Power Zener Diodes - Voltage Regulation:
• Power Zener Diodes as ...
12V LED Battery Level Indicator:
• 12V LED Battery Level ...
Reverse Polarity Circuit Protection:
• Reverse Polarity Circu...
High Voltage Surge Protection Circuit:
• High Voltage Surge Pro...
AC DC Polarity Tester Circuit:
• AC DC Polarity Tester ...
_______________________________
DC to AC Reverse Polarity Circuit:
• DC to AC Reverse Polar...
Varactor Diodes - Voltage Capacitors:
• Voltage Controlled Cap...
Final Exams and Video Playlists:
www.video-tuto...
Full-Length Videos and Worksheets:
/ collections

[@TheOrganicChemistryTutor]

Final Exams and Video Playlists: www.video-tutor.net/

[@bjornnordling269]

This man is the true hero

[@ChemPm]

Thank you, I was wondering why I kept on getting different values. I was using the ohm of each resistor rather than the total resistance.

[@successthruknowledge]

A very thorough discussion of power dissipation in all of those elements. Good practice to strengthen our understanding of all of those different equations for power in relation to voltage and current and resistance!

[@serkanozkan8793]

Very well explained the way it is complicated. But current limited power supply sometimes need different way of calculation under the output power in load!

[@paulkanucawec9489]

KZbin tutorial GOAT tutor 🐐🥰🥰🥰

[@zadkeilpaul7472]

How? Or are you a fool?

[@parkerkenney6113]

This dude carrying me through my freshmen engineering and pre calc classes

[@DRMath]

Well explained with example, thanks for sharing. Happy teaching ✌️

[@elephants730]

Now this is a sexy lesson

[@kd013n]

tf

[@shoaibasghar9046]

Thanks.. Allah apko hamesha Khush Rakhy Ameen

[@ivan-dg6ep]

Can you by a chance make a video regarding the science behind diodes? Like N-type, P-type, Holes etc?

[@generalistfactz2938]

I m an Indian🇮🇳........ Love ur work.... 🤟 Thnx

[@MissPhilemon]

Topic is understandable it’s just that sometimes I get confused with the formulas to use. Any tips?

[@francisvalenti2541]

As always , great explanation.

[@vinoliakwenda9606]

Thank you well explained I now understand

[@yollandasigauke5217]

thank you for your time,

[@harigopaladamus9481]

wow is it really that hard for school networks to explain this?? It is so simple if taught CORRECTLY

[@alanmontiel9601]

Hey if you could let us know what software you are using that would be great.

[@LuciferFFOfficial]

Thanks for explaining.

[@samdicks9146]

wish you would shwo that V2/R works aswell,, had me second guessing myself

[@khayratkhayrat8663]

Hi, which software you use to explain those topics? I wanna use it

[@humayunbilal8333]

Shut up

[@OnlyOne1Dee]

Sir you the best

[@beausky4100]

The Organic Chemistry Tutor sir, in problem 4, if the value of the resistor changes, does the voltage drop would still be the same of 5.4 volts. thank you

[@abhishekmehta7678]

Sir/mam can you please suggest any book Or article on the this topic for deeply understanding regarding energy dissipated in more electronics componentslike transistor, capacitor(polarize, mica, ceramic, etc) etc

[@MegaBeanHead0]

Thank you so much man

[@seanclaussen4364]

The formula for total current is I= V/R, you have I= V^2/R. But other than that very informative, thankyou

[@havardnakling4298]

V^2/R is for power (Watts), V/R is for electricity (Amps)

[@radokral]

Can anyone explain why if i use the other formula (V^2/R) im getting different numbers? With this formula the P=3600/20=180W for the 1st resistor and P=3600/10=360W for the 2nd resistor, much more than what we get by using I^2*R.

[@Misscakes089]

It is because, resistors connected in series have different voltages.

[@cugzarui5568]

thaqnksssss once again

[@uNknownrMx]

Thank you. Brother

[@tapobratdas1627]

Thank you so much 💓

[@vipinv6821]

Excellent

[@timewithakyedzi79]

I have a 5x 5watt led lights and 3 pendants lights what is the IB of the circuit? Pls any help?

[@abdullaabdikarim2455]

Thank you

[@hasanshahriasakib6418]

Thanks sir

[@radekholy7476]

That LED has also some internal resistance, so current will be even lower than 0.054amps..

[@boonedockjourneyman7979]

Better this time. But ... power is not equal to heat. It is equal to ALL of the work occurring in the system. Your example of an LED demonstrates the idea. How much work is involved in light emission? A nasty example is something like micro-phonics. Check it out. 40 years of teaching this stuff has convinced me that citation to the actual technical terms allows students to dig a little deeper on their own. In this case, you could have easily cited KCL and KVL. If you stick to what you know rather than what you Google you do better.

[@bunstie5208]

no one cares

[@ninjapig28]

goated

[@Keratin2222]

0:39 series 4:22 parallel

[@matthewkoob7600]

What a god

[@zachschinasi281]

great video think that the sume of the power is supposed to be equal to zero so the V source should be negative :)

[@zarifnawar9515]

Can I calculate of each resistance power by P= V^2/R Formula?

[@ronage2002]

Yes

[@radokral]

Then why dont i get the same numbers? If i use the V^2/R formula i get 60^2/20 for the first resistor which is 180W and 60^2/10 which is 360W for the second. What am i missing here?

[@ouukun]

So I found the total resistance Rt first, which is the inverse of the sum of the inverse of each resistors. Then plugged that into the P=VI, after I found I from V=IRt. But I got P = 66.66W. What did I do wrong?

[@ratyrat5]

one year late but it seems you were working with resistors in parallel. the current for resistors in parallel are not the same, but the voltage is. use V = I * R to find the current for each resistor then you can use any of the equations for power. you could even skip the step to find current and do P = V^2 / R, however it might be better to find the current anyways if you get asked about it in future questions

[@safiulfaiyaz7038]

Am I the only one who smiled at 8:11

[@pandiarajankk8041]

Good

[@johndelisio4933]

You da man

[@lazyboy1417]

Nice

[@yasirrizwan2959]

FIRST! Love ur vids man

[@DRMath]

Yasir Rizwan ✌️

[@FrjejjrhsHshah]

Bro where is organic chemistry in your channel 😂😂😂 All topics related to electrical engineering